What are the solutions of the equation x^6 + 6x^3 + 5 = 0? Use factoring to solve.

Answers

Answer 1

Answer: see attached picture for answer

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which methods could you use to calculate the y-coordinate of the midpoint of a vertical line segment with endpoints at (0,0) and (0,15)

Answers

Answer:

Option D. Divide 15 by 2

Step-by-step explanation:

we know that

To find the y-coordinate of the midpoint of a vertical line, adds the y-coordinates of the endpoints and divide by two

we have the endpoints

(0,0) and (0,15)

The y-coordinate of the midpoint is (0+15)/2=15/2=7.5

therefore

Divide 15 by 2

Answer:

the answer is to count by hands ( A ) and divide 15 by 2 ( D )

Step-by-step explanation:

Tim mows neighborhood lawns for extra money. Suppose that he would be willing to mow one lawn for $12, a second lawn for $16, and a third lawn for $22. Also suppose that three neighbors are interested in having their lawns mowed. Mrs. Jones would be willing to pay $35 to have her lawn mowed, Mr. Wilson would be willing to pay $27, and Ms. Smith would be willing to pay $22.

Answers

And it is 4,192thats is what my bro said

2[s+3(s-31)]=18
how would i solve this

Answers

1. 2[s+3(s-31)]=18
2. [s+3(s-31)] = 9
3. s+ 3s - 93 = 9
4. 4s = 9+93
5. 4s = 102
6. s= 25.5

What is 87*798 and plz give me details thx.

Answers

87 times 798 is 69,426

What is the LCM of the numbers 3, 6, and 9?A.
9
B.
18
C.
36
D.
54

Answers

the LCM is option B. 18

Answer:

The LCM of the numbers 3, 6, and 9, is 18.

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

Show your work !

Thanks

Answers

For 1st.
you can solve it by general law or ,
since the coefficient of r^2 = 1
so u should think of 2 number which if u multiple them gives you 27 and sum of them is 12 and those numbers are 9 , 3
so the answer (x+9)*(x+3)
2nd problem :
g^2 - 9 = (g-3)*(g+3)
3rd problem:
2p^3 + 6p^2 + 3p +9
1st divide it into two parts
(2p^3 +6p^2)+ (3p+9)
from the 1st part
take 2p^2 as a common factor and from part 2 take 3 as a common factor and the equation be like
2p^2(p+3) + 3(p+3)
then take (p+3) as a common factor
so (p+3)* ( 2p^2 +3 )

1: (r+3)(r+9). 2: (g+3)(g-2). 3: (2p^2+3)(p+3). FOIL multiply the first, inside, outside, and last terms. add the inside and outside terms together. :)

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