In the light wave above, the property labeled A determines which characteristic of visible light?brightness
speed
reflection
color
In the light wave above, the property labeled A determines - 1

Answers

Answer 1
Answer:

Explanation:

i think the answer is Reflection


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Giant waves produced by gravity are called what?

Answers

Either a tsunami or an up welling!

Hope this helped!

A stress is considered a "bad" stress when it A. cannot be eliminated. B. keeps a person from feeling good. C. challenges a person to do better. D. doesn't lead to a productive end.

Answers

The answer is either c or d

The _______________ of two objects and their distance from each other determine the gravitational force between them. (Please help this is my last science question on my homework)

Answers

" ... product of the masses ... "
The masses of two objects

A kangaroo hops at an angle of 25° to the horizontal with a velocity of 20 m/s. What is the vertical component of the velocity? A. 8.5 m/s B. 12.5 m/s C. 18 m/s D. 20 m/s

Answers

Answer:

A. 8.5 m/s

Explanation:

vᵧ = v sin θ

vᵧ = (20 m/s) (sin 25°)

vᵧ = 8.5 m/s

I took the test and got A) 8.5 correct

The common name for the reflection of sound waves is an?

Answers


When sound waves are reflected in the right way so as to be heard
some time after they were generated, then the phenomenon is usually
called an "echo".

A 4.8-kilogram ball moving at 8 m/sec to the right collides with a 1.4-kilogram ball at rest. After the collision, the 4.8-kilogram ball moves at 4.8 m/sec to the right. What is the velocity of the 1.4-kilogram ball?m/s

Answers

The final velocity of the 1.4 kg ball is 11.0 m/s to the right

Explanation:

We can solve this problem, by using the law of conservation of momentum: in fact, the total momentum of the two balls must be conserved before and after the collision. Therefore, we can write:

p_i = p_f\nm_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 4.8 kg is the mass of the first ball

u_1 = 8 m/s is the initial velocity of the first ball (taking right as positive direction)

v_1 = 4.8 m/s is the final velocity of the first ball

m_2 = 1.4 kg is the mass of the second ball

u_2 = 0 is the initial velocity of the second ball  (it is at rest)

v_2 is the final velocity of the second ball

And solving the equation for v2, we find:

v_2 = (m_1 u_1-m_1v_1)/(m_2)=((4.8)(8)-(4.8)(4.8))/(1.4)=11.0 m/s

So, the 1.4 kg ball moves at 11.0 m/s to the right.

Learn more about momentum:

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