Aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal. What is the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients? Aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal. What is the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients? 3. 1. 4. 2.

Answers

Answer 1

Answer:

The stoichiometric coefficient for aluminum, Al when the chemical equation is balanced is 2.

To obtain the stoichiometric coefficient for aluminum, we shall write and balance the equation for the reaction. This is illustrated below:

Aluminum => Al

Iron (II) chloride => FeCl₂

Aluminum chloride => AlCl₃

Iron => Fe

Aluminum + Iron (II) chloride —> Aluminum chloride + Iron

Al + FeCl₂ –> AlCl₃ + Fe

There are 3 atoms of Cl on the right side and 2 atoms on the left side. It can be balance by writing 3 before FeCl₂ and 2 before AlCl₃ as shown below:

Al + 3FeCl₂ –> 2AlCl₃ + Fe

There are 2 atoms of Al on the right side and 1 atom on the left. It can be balance by writing 2 before Al as shown below:

2Al + 3FeCl₂ –> 2AlCl₃ + Fe

There are 3 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 3 before Fe as shown below:

2Al + 3FeCl₂ –> 2AlCl₃ + 3Fe

Now, the equation is balanced.

The coefficient of Aluminum, Al in the balanced equation is 2.

Learn more about balancing equation:

brainly.com/question/2399130

Answer 2

Answer:

Answer:

Explanation:

The balanced chemical equation for the reaction of aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal is:

2Al(s) + 3FeCl₂(aq) → 2AlCl₃(aq) + 3Fe(s).

It is clear that 2 mol of Al react with 3 mol of FeCl₂ to produce 2 mol of AlCl₃ and 3 mol of Fe.

So, the the stoichiometric coefficient for aluminum when the chemical equation is balanced is 2.

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How many pairs of non-bonding electrons are in a silicon disulfide molecule?

Answers

Silicon disulfide (SiS2) is a covalent compound consisting of silicon (Si) and sulfur (S) atoms. To determine the number of pairs of non-bonding electrons in a silicon disulfide molecule, we can first calculate the total number of valence electrons in the molecule.

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Choose all answers that applyPLZ HELP ASAP i am doing a test and i need help. I WILL BE DOING BRAINLIEST TO THE FIRST PERSON WHO REPLYS
When dynamite explodes, it releases a large amount of light and heat. This is an example of _____.

slow combustion
rapid combustion
an exothermic reaction
an endothermic reaction
a chemical change
a physical change

Answers

Answer

Rapid Combustion

Explanation:

An explosion is a combustion and a quick reaction, That makes it rapid

Pls help its due in a few minutes

Answers

Answer:

Theory

Explanation:

When a substance freezes, what happens to the mass? The mass stays constant as it changes from a liquid to a solid.

The mass increases as it changes from a liquid to a solid.

The mass decreases as it changes from a liquid to a solid.

There is no mass once the substance becomes a solid

Answers

The correct answer is the first statement. The mass stays constant as it changes from a liquid to a solid. According to the Law of Conservation of Mass, mass is conserved. It is not created nor destroyed. Therefore, as the substance turn into solid, all of the substance goes only to the solid phase.

The mass stays constant as it changes from a liquid to a solid

A 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. How many grams of carbon dioxide escaped before the container could be sealed if the new volume of the balloon is 15.4L?

Answers

Assumptions made:
1. Temperature and pressure is constant.
2. Ideal gas is involved.

The variables involved in this problem is the moles of the gas and the volume. We find their relationship from the ideal gas law. PV=nRT. With all other concept besides n and V is constant, Volume is directly proportional to the amount of gas inside the balloon. Solving this is as simple as ratio and proportion.

25.5L/3.5 moles = =15.4L/X moles
X= 2.11 moles.

Answer:

61 grams

Explanation:

If the number of moles of CO₂ in the balloon is given to be 3.5 moles, the mass of CO₂ in the balloon will be

number of moles = mass ÷ molar mass

Hence, mass = number of moles × molar mass

Molar mass of CO₂ is 44g. This is 44 because the atomic mass of carbon is 12 while that of oxygen is 16. Thus, 12 + (16 × 2) = 44 g

mass= 3.5 moles × 44g

mass = 154g (which is the initial mass)

When the mass of CO₂ in the 25.5 liter balloon is 154g, the mass of CO₂ in the balloon when the volume of CO₂ in the balloon is 15.4 liter will be X

To get X,

25.5 L ⇒ 154g

15.4 L ⇒ X

cross-multiply, and

X = (15.4 × 154) ÷ 25.5

X = 93.00 grams (which is the final mass)

93.00 grams of CO₂ was left in the balloon, hence the mass of CO₂ that escaped will be: initial mass minus final mass

= 154g - 93g

= 61g

The mass of CO₂ that escaped is 61 grams

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