Josh and Chris are racing their derby-car models in a boxcar derby. Two of the six racers in each heat are chosen at random to get the outside lanes. What is the probability that Josh and Chris will both get an outside lane in the first heat?

Answers

Answer 1

Answer: 2 out of 6 or 20% i think

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Answers

Answer:

i think its C it should be c

Please help with expressions and equations

Answers

l = 6, w = 2, h = 3
2 (lw + lh + wh)
2 (6×2 + 6×3 + 3×2)
2 (12 + 18 + 6)
2 (36)
72 is the answer

Under which operations is the set of whole numbers {0,1,2,3...} closed

Answers

Checking with Addition:

Let x, y be two whole numbers.

Then, x + y is definitely a whole number.

So, the set of whole numbers is closed under addition.

Checking with Subtraction:

Let x, y be two whole numbers.

Then, x - y may or may not be a whole number.

For example, if we take 3 and 2,

3 - 2 = 1 is a whole number but if we take 2 and 5, then

2 - 5 = -3 is not a whole number.

So, the set of whole numbers is not closed under subtraction.

Checking with Multiplication:

Let x, y be two whole numbers.

Then, x × y is definitely a whole number.

So, the set of whole numbers is closed under multiplication.

Checking with Division:

Let x, y be two whole numbers.

Then, x / y may or may not be a whole number.

For example, if we take 6 and 3,

6/3 = 2 is a whole number.

But, if we take 4 and 5,

4/5 is not a whole number.

So, the set of whole numbers is not closed under division.

Gianna is substituting t = 2 and t = 7 to determine if the two expressions are equivalent.5(2t+3) 5t+25
Which statement is true?
A. Both expressions are equivalent to 35 when t=2.
B. Both expressions are equivalent to 85 when t=7
C. Both expressions are equivalent to 60 when t=7
D. The expressions are equivalent.
PLEASE HELP!!!!

Answers

Answer: A. Both expressions are equivalent to 35 when t=2.

Step-by-step explanation:

Given: Gianna is substituting t = 2 and t = 7 to determine if the two expressions are equivalent.

At t=2

$5(2t+3)=5(2(2)+3)=5(4+3)=5(7)=35$

$5t+25=5(2)+25=10+25=35$

Therefore, both expressions are equivalent to 35 when t=2.

At t=7

$5(2t+3)=5(2(7)+3)=5(14+3)=5(17)=85$

$5t+25=5(7)+25=35+25=60$

Hence, A is the write option.

Break apart ones to subtract 36 - 7 = im confused please help

Answers

29 is answer
Ok hope this helps

36-7=29

Hope this helps

The mean of a set of twelve numbers is 5.5. The mean of another set of eight numbers is k. The mean of the combined set of twenty numbers is 8.5. Find the value of k.Can you please help me

Answers

mean is (sum of the values of the numbers in the set)/(how many numbers are in the set)

first bit
mean of 12 numbers is 5.5 is the same as
(12 numbers)/12=5.5

the second bit
mean of 8 numbers is k
(8 numbers)/8=k

(12numbres+8numbers)/20=8.5

interesting
one way is to solve the first and second equations for 12numbers and 8numbers

(12numbers)/12=5.5
times 12 both sides
12numbers=66

(8numbers)/8=k
multiply 8 both sides
8numbers=8k
input

(66+8k)/20=8.5
mulitply both sides by 20
66+8k=170
minus 66 both sides
8k=104
divide 8 both sides
k=13

k=13

k= 13.

You do (8.5 X 20) - (5.5 X 12), which is equal to 170 - 66 = 104
104 divided by 8 equals 13

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