MATHEMATICS MIDDLE SCHOOL

What are the roots of the equation x^2+6x-9=0

Answers

Answer 1

Answer:

Answer:

The roots of the quadratic equation are

$x=-3+3√(2)$

$x=-3-3√(2)$

Step-by-step explanation:

we have

$x^(2) +6x-9=0$

we know that

The formula to solve a quadratic equation of the form $ax^(2) +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

$x^(2) +6x-9=0$

$a=1\nb=6\nc=-9$

substitute in the formula

$x=\frac{-6(+/-)\sqrt{6^(2)-4(1)(-9)}} {2(1)}$

$x=\frac{-6(+/-)√(72)} {2}$

$x=\frac{-6(+/-)6√(2)} {2}$

$x=-3(+/-)3√(2)$

$x=-3(+)3√(2)$

$x=-3(-)3√(2)$

Answer 2

Answer:

Given equation is :

$x^(2)+6x-9=0$

We will solve this quadratic equation, using the formula:

$x1,2=\frac{-b+\sqrt{b^(2)-4ac}}{2a}$ and

$x1,2=\frac{-b-\sqrt{b^(2)-4ac}}{2a}$

Now, putting a=1 , b=6 and c =-9 we get

$x=\frac{-6+\sqrt{6^(2)-4*1(-9)}}{2*1}$ and

$x=\frac{-6-\sqrt{6^(2)-4*1(-9)}}{2*1}$

Final solutions are: $x=3(√(2)-1)$ and

$x=-3(√(2)+1)$

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Hope this helps. I think it's right? haha haven't done this in a while.

Michelle made a bead necklace that was 14 inches long. The length of the necklace, in inches, is equal to 4 added to one-seventh the number of beads, b.1/7b + 4 = 14

How many beads did Michelle use for her necklace?
70
17
35
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