Which ion was formed by providing the second ionization energy to remove an electron?

Answers

Answer 1
Answer: The correct answer for the question above is S2- (Sulfide.) S2- ion was formed by providing the second ionization energy to remove an electron. S2- is actually an inorganic anion of Sulfur. This anion contributes no color to any objects and is classified as a strong base.
Answer 2
Answer:

Answer:

It is Ca2+

Explanation:


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A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products have cooled to 20.0 °C at 1 bar, there are 4.41 L of CO2 and 3.26 mL of H2O . The density of water at 20.0 °C is 0.998 g/mL.

Answers

Explanation:

First, calculate the moles of CO_(2) using ideal gas equation as follows.

                PV = nRT

or,          n = (PV)/(RT)

                = (1 atm * 4.41 ml)/(0.0821 Latm/mol K * 293 K)      (as 1 bar = 1 atm (approx))

                = 0.183 mol

As,   Density = (mass)/(volume)

Hence, mass of water will be as follows.

                Density = (mass)/(volume)

             0.998 g/ml = (mass)/(3.26 ml)    

                 mass = 3.25 g

Similarly, calculate the moles of water as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                              =  (3.25 g)/(18.02 g/mol)            

                              = 0.180 mol

Moles of hydrogen = 0.180 * 2 = 0.36 mol

Now, mass of carbon will be as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

          0.183 mol =  (mass)/(12 g/mol)            

                              = 2.19 g

Therefore, mass of oxygen will be as follows.

              Mass of O = mass of sample - (mass of C + mass of H)

                                = 3.50 g - (2.19 g + 0.36 g)

                                = 0.95 g

Therefore, moles of oxygen will be as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                               =  (0.95 g)/(16 g/mol)            

                              = 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

                         C              H           O

No. of moles:  0.183        0.36       0.059

On dividing:      3.1           6.1            1

Therefore, empirical formula of the given compound is C_(3)H_(6)O.

Thus, we can conclude that empirical formula of the given compound is C_(3)H_(6)O.            

A beaker containing a mixture of N2(g) and H2(g) is cooled by placing it in a tray of cold water. In response to the cooling, the likely number of collisions between the molecules of N2(g) and H2(g) will . The rate of the reaction will .

Answers

The frequency of collisions between the N₂ and H₂ molecules will decrease and the rate of reaction will also decrease.

Since the water is cooler than the gas mixture, heat will flow from the gas to the water.

The gas will cool down, so the average kinetic energy of the gas molecules will decrease.

The molecules will be moving more slowly, so there will be fewer collisions and fewer of these collisions will have enough energy to react.

The rate of reaction between H₂ and N₂ molecules at room temperature is exceedingly slow, but cooling the gas mixture will make the reaction even slower.

Answer:

A beaker containing a mixture of N2(g) and H2(g) is cooled by placing it in a tray of cold water. In response to the cooling, the likely number of collisions between the molecules of N2(g) and H2(g) will  decrease. The rate of the reaction will  decrease.

Explanation:

#platofam

Which of the following is a property of both gases and liquids?

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FLUIDITY IS PROPERTY OF BOTH LIQUIDS AND GASES

What does catalase do? Use the terms substrate and product in your response.

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Catalase is an enzyme found in almost all living organisms exposed to oxygen. This catalyzes the decomposition of hydrogen peroxide. The substrate would be the hydrogen peroxide and the products are water and oxygen.

Chemistry Questions 3. What is true of a strong acid? A. It ionizes close to 100% in water B. It is a weak electrolyte C. It does not conduct electricity in solution D. It always has a high concentration 4. What substance is acting as the Bronsted-Lowry base in the forward reaction below? H2O + HCl --> H3O+ + Cl- A. H3O+ B. Cl- C. H2O D. HCl 5. Which of the following is NOT an acid-base neutralization reaction? A. NH3 + HCl --> NH4Cl B. NaOH + CH3COOH --> Na CH3COO + H2O C. 2 HNO3 + Ca(OH)2 --> Ca(NO3)2 + 2 H2O D. H2SO4 + 2 NaCl --> 2 HCl + Na2SO4

Answers

Answer:

For 3: The correct answer is Option A.

For 4: The correct answer is Option C.

For 5: The correct answer is Option D.

Explanation:

  • For 3:

There are 2 types of solutions on the basis of pH.

An acid is defined as the chemical substance which looses hydrogen ions in a solution.

A weak acid does not completely dissociates into its ions but a strong acid completely dissociates into its ions when dissolved in water.

A base is defined as the chemical substance which looses hydroxide ions in a solution.

A weak base does not completely dissociates into its ions but a strong base completely dissociates into its ions when dissolved in water.

Hence, the correct answer is Option A.

  • For 4:

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

For the given chemical equation:

H_2O+HCl\rightarrow H_3O^++Cl^-

H_2O is considered as a bronsted-lowry base because it is accepting hydrogen ion to form hydronium ion

HCl is considered as a bronsted-lowry acid because it is donating hydrogen ion to form chloride ion.

Hence, the correct answer is Option C.

  • For 5:

Neutralization reaction is defined as the chemical reaction in which an acid reacts with a base to produce a salt and water molecule.

HX+BOH\rightarrow BX+H_2O

For the given options:

Option A:

The chemical equation follows:

NH_3+HCl\rightarrow NH_4Cl

This is an example of neutralization reaction because ammonia is considered as a base and when it reacts with HCl, it leads to the production of salt.

Option B:

The chemical equation follows:

NaOH+CH_3COOH\rightarrow CH_3COONa+H_2O

This is an example of neutralization reaction.

Option C:

The chemical equation follows:

2HNO_3+Ca(OH)_2\rightarrow Ca(NO_3)_2+2H_2O

This is an example of neutralization reaction.

Option D:

The chemical equation follows:

H_2SO_4+2NaCl\rightarrow 2HCl+Na_2SO_4

This is an example of double displacement reaction.

Hence, the correct answer is Option D.


Strong acid does not conduct electricity. Question 4} A. H30  Question 5 } B. NaOH + CH3COOH

Explain why neon is monatomic but chlorine is diatomic.

Answers

Chlorine is a halogen and all halogens and oxygen, nitrogen and hydrogen are diatomics

Explanation:

Neon is in group 8/0, which means that it has a full outer shell. Atoms react to get a full outer shell but as neon already has a full outer shell, it doesn't react and stays monatomic.

However, chlorine is in group 7, so it needs 1 more electron to complete its outer shell, two chlorine atom share one electron each with each other so they have full outer shells. This is why chlorine is diatomic.