If there are 50 grams of U-238 on day zero of radioactive decay, how much will there be after 4.5 billion years

Answers

Answer 1
Answer: We use the formula of the half-life to calculate for the remaining U-238 after 4.5 billion years. The formula is expressed as A = A₀ (1/2)^(t/h) where A is the final amount, A₀ is the initial amount of the substance, t is the time and h is the half-life of the substance wherein for U-238 h is equal to 4.47 billion years.

A = A₀ (1/2)^(t/h)
A = 50 (1/2)^(4.5 / 4.47)
A = 24.88 g
Answer 2
Answer:

25 if using usatsyprep


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Which of the following statements is not true regarding atmospheric pressure?A. You calculate absolute pressure by adding atmospheric pressure to gage pressure.
B. When atmospheric pressure is higher than the absolute pressure of a gas in a container, a partial vacuum exists in the container
C. Mercury and aneroid barometers are used to measure atmospheric pressure.
D. Atmospheric pressure increases with increasing altitude

Answers

The correct answer is option B. i.e.When atmospheric pressure is higher than the absolute pressure of a gas in a container, a partial vacuum exists in the container. This is the incorrect statement about atmospheric pressure and the absolute pressure.

Gravity is affected by

Answers

Gravity is affected by mass and distance

How much energy is contained in matter with mass of 1 gram (0.001 kilogram)

Answers

The mechanical energy consisting of potential and kinetic energy is:

           0.001 x [ (acceleration of gravity x height) +  (1/2) (speed)² ] .


You want to know how much [ mc² ] there is in 1 gram of mass.

           E = m c² = (0.001) x (3 x 10⁸)² = 9 x 10¹³ joules

That's the energy that a 1,000-watt toaster uses 
in  2,852 years  of continuous toasting.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Hope that helped!

If an electric charge is accumulated on an object, it is referred to as _____

Answers

Static, because it stays on the object.
It is referred as Static Electricity.

In an engine governor, the two spheres (total mass of 1.0kg) are at 0.05m and rotating at 37rad/s If the engine increases the angular velocity to 58rad/s what is the new location of the spheres?

Answers

Here we can say that there is no external torque on this system

So here we can say that angular momentum is conserved

so here we will have

I_1\omega_1 = I_2\omega_2

now we have

I_1 = mr^2

I_1 = (1kg)(0.05^2)

I_1 = 25* 10^(-4) kg m^2

similarly let the final distance is "r"

so now we have

I_2 = mr^2

I_2 = 1r^2

now from above equation we have

(25* 10^(-4))37 = (r^2)(58)

r = 0.04 m

so final distance is 0.04 m between them

What is the minimum current rating of the motor disconnecting means for a 40-horsepower, 208-volt, 3-phase squirrel-cage motor?

Answers

Answer:

The minimum current rating of the motor disconnecting means is 165 Amperes.

Explanation:

First convert the given power into units of watt. Since,

1 horsepower = 746 watts

Therefore,

40 horsepower = 40 x 746 watts

40 horsepower = 29840 watts

Since, we know that:

Power = Full Load Current (FLC) x Voltage

FLC = Power/Voltage

FLC = 29840 watts/208 volts

FLC = 143.46 Amperes

Now, the current for disconnecting means is at least 115% of the FLC, for the motors rated at 600 Volts or less.

Current for Disconnecting Means = (1.15)(143.46 A)

Current for Disconnecting Means = 165 Amperes