A drive find difficulty to drive a car when the ground is cover with ice explain why?

Answers

Answer 1
Answer: the ground is less rough, so there is less friction between the ground and the wheels of the car. This makes it unable for the car to move forward

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What is the example of a sport related activity

Answers

sports are games so lets do process of elimination
A.) weight lifting (exercise)
B.) Soccer (sport)
C.) jump rope (exercise)
D.) Running a race (exercise) but questionable 

i would say B.) soccer

The correct answer is B. Soccer
Hope this helps you and have a good night! :3

How is a refracting telescope similar to a compound microscope?

Answers

Answer:

There are two similarities between refracting telescope and compound microscope.

1. both have objective lens and eyepiece lens

2. both the lenses are convex in nature.

Explanation:

Objective lens is near the object and eyepiece is near the eye through which we can see the image.

Convex or converging lens is used to converge the rays of light coming from the object.

They both have an objective lens and an eyepiece lens.

A container holding 1.2 kg of water at 20.0 °C is placed in a freezer that is kept at –20.0 °C. The water freezes and comes into thermal equilibrium with the interior of the freezer. a) How much heat is extracted from the water in thisprocess?
b) What is the minimum amount of electrical energy required bythe refrigerator to carry out this process if it operates betweenreservoirs at temperatures of 20.0 °C and -20.0 °C?

Answers

Answer:

(a) Q=556464\ J

(b) 556464 joule

Explanation:

Given:

  • mass of water, m_w=1.2\ kg
  • initial temperature of water, T_i=20^(\circ)C
  • final temperature of frozen water, T_f=-20{}^(\circ)C

The conversion of water of 20.0 °C to the ice of –20.0 °C will comprise of three steps:

  1. cooling of water to 0 °C Q_w
  2. formation of ice at 0 °C from the water of 0 °C Q_L
  3. further cooling of ice of 0 °C to -20 °C Q_i

We have,

  • Latent heat of fusion of ice, L=3.4* 10^5\ J.kg^(-1)
  • specific heat of water, c_w=4186\ J.kg^(-1).^(\circ)C^(-1)
  • specific heat of ice, c_i=2000\ J.kg^(-1).^(\circ)C^(-1)

(a)

Now, total heat lost in the process:

Q=Q_w+Q_L+Q_i

Q=m_w(c_w. \Delta T_w+L+c_i.\Delta T_i)

where:

\Delta T_i\ \&\ \Delta T_w = change in temperature of ice and water respectively.

\Rightarrow Q=1.2(4186* 20+3.4* 10^5+2000* 20)

Q=556464\ J is the total heat extracted during the process.

(b)

So, 556464 joule is the minimum electrical energy (by the law of energy conservation under no loss condition) required by refrigerator to carry out this process if it operates between the reservoirs at temperatures of 20.0 °C and -20.0 °C, because for a refrigerator to work in a continuous cycle it is impossible to transfer heat from a low temperature reservoir to a high temperature reservoir without consuming energy in the form of work. Here 556464 joule is the heat of the system to be eliminated.

Final answer:

The amount of heat extracted from the water involves the sum of heat lost as it cools and then freezes. The minimum energy needed by the refrigerator to do this is given by the formula for Carnot efficiency.

Explanation:

To answer these questions, we'll need to understand some fundamental principles of thermodynamics.

a) The heat Q taken from the water will be the sum of the heat released during cooling of the water until 0.0°C, and the heat released during freezing at 0.0°C. The heat loss as the water cools can be calculated using Q = mcΔt where m=mass of water, c=specific heat of water, and Δt=change in temperature. The heat loss as water freezes can be calculated using Q = mlf where lf is the latent heat of fusion. Adding these two quantities gives the total heat extracted.

b) The minimum energy needed by the refrigerator, W, is given by the Carnot efficiency formula, W = Q*(T_hot - T_cold)/T_hot, where T is in Kelvin. This would tell you how much energy the refrigerator needs to remove the heat from the water and cool it down to the freezer temperature.

Learn more about Thermodynamics here:

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When a sound source is moving toward the observer, the observer will hear a higher pitch. This is due toa. a decrease in the amplitude of the sound wave.
b. a decrease in the frequency of the sound wave.
c. an increase in the frequency of the sound wave.
d. an increase in the amplitude of the sound wave.

Answers

number one a and b are automatically out if you decrease the pitch or frequency you wont hear it louder it does not add up ok?
number 2 the answer would be C the higher the frequency the higher the pitch the lower the frequency the lower the pitch this just comes back to common sense. for example you cant decrease the frequency and than expect a louder pitch its like saying I am going to smash the key on this piano with all my strength and it will make a small very low pitch sound you get what I mean so your answer would indeed be C.

What is one major difference between how matter moves through an ecosystem and how energy moves through an ecosystem?

Answers

Matter is recycled: living things die and decay, for example. The nutrients living things need are obtained from plants or organisms that eat plants. The food chain thing. Energy flows on a one way street - the sun's energy is used by plants, then food chain again, and finally excess energy is radiated by the earth into space. There's no way to store and re use energy as there is for matter.

A toaster with a power rating of 1,000 watts is plugged into a household voltage of 120 volts. How much current runs through the toaster? A) 120,000 amps
B) 880 amps
C) 8.3 amps
D) 0.120 amps

Answers

Answer : I = 8.33 A

Explanation :

It is given that,

Power rating of the toaster, P = 1000 watts

Household voltage, V = 120 volts

We know the relation between power, voltage and the current is :

P=V* I

I=(P)/(V)

I=(1000\ W)/(120\ V)

I = 8.33\ A

8.33 A of current runs through the toaster.

Hence, this is the required solution.

C) 8.3 i believe i wouldnt take me 100%