PHYSICS HIGH SCHOOL

A 2.0-kilogram mass is located 3.0 meters abovethe surface of Earth. What is the magnitude of
Earth’s gravitational field strength at this
location?
(1) 4.9 N/kg (3) 9.8 N/kg
(2) 2.0 N/kg (4) 20. N/kg

Answers

Answer 1
Answer:

The correct answer is: Option (3) 9.8 N/kg

Explanation:

According to Newton's Law of Gravitation:

F_g = (GmM)/(R^2) --- (1)

Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²

m = Mass of the body = 2 kg

M = Mass of the Earth = 5.972 × 10²⁴ kg

R = Distance of the object from the center of the Earth = Radius of the Earth + Object's distance from the surface of the Earth = (6371 * 10³) + 3.0 = 6371003 m

Plug in the values in (1):

(1)=> F_g = (6.67408 * 10^(-11) * 2 * 5.972*10^(24))/((6371003)^2) = 19.63

Now that we have force strength at the location, we can use:

Force = mass * gravitational-field-strength

Plug in the values:

19.63 = 2.0 * gravitational-field-strength

gravitational-field-strength = 19.63/2 = 9.82 N/kg

Hence the correct answer is Option (3) 9.8 N/kg
Answer 2
Answer: (3) 9.8 N/kg is your answer.

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A 15g bullet travelling at 100m/s strikes and is absorbed by a 75kg object. Find the speed at which the final object moves.

Answers

The final object will move with a speed of 1.9 x 10⁻² m/s.

What is law of conservation of momentum ?

According to the law of conservation of momentum, when two objects meet in a closed system, the sum of their momentums before and after the collision is constant.

Here,

Initial velocity of the bullet, u = 100 m/s

Mass of the bullet, m = 15 g = 0.015 kg

Mass of the object, M = 75 kg

Total momentum before collision, P₁ = mu + (M x 0)

P₁ = 0.015 x 100

P₁ = 1.5 Kgm/s

Total momentum after collision, P₂ = (m + M)v

P₂ = (0.015 + 75)v

P₂ = 75.015 v

According to law of conservation of momentum,

P₁ = P₂

1.5 = 75.015 v

Therefore, the speed with which the final object moves,

v = 1.5/75.015

v = 1.9 x 10⁻² m/s

Hence,

The final object will move with a speed of 1.9 x 10⁻² m/s.

To learn more about law of conservation of momentum, click:

brainly.com/question/17140635

#SPJ2
what i got was
speed of impact that is 44.27 m/s
     or 159.38 km/h
time until impact is 4.525
 and last is the Energy at impact which I calauated outcome was 73500.00 joules

Which of the following stars would be the most luminous?2. Yellow star
3. Red star
4. Blue star
5. Orange star

Answers

The correct answer to the question that is stated above is the fourth option which is :Blue star.
Blue stars are uncommon but very bright. It has an average luminosity of  1,400,000 ( the Sun =1) with a strong UV continuum. The blue stars average mass is 60 ( the Sun =1) and its average radius is 15 ( the Sun =1).

Answer: Blue star.

Explanation:

How are kyanite crystals formed

Answers

It occurs as detrital grains in sedimentary rocks. It forms under extreme pressure.

3 The components of a 15-meters-per-secondvelocity at an angle of 60.° above the horizontal
are
(1) 7.5 m/s vertical and 13 m/s horizontal
(2) 13 m/s vertical and 7.5 m/s horizontal
(3) 6.0 m/s vertical and 9.0 m/s horizontal
(4) 9.0 m/s vertical and 6.0 m/s horizontal

Answers

First draw a picture to help make the problem easier. (see attached)

Next you can use sin and cos to find the x and y components of the velocity.

First lets find the vertical component:
sin = (opp)/(hyp)
sin(60) = (y)/(15m/s)
Multiply both sides by 15m/s
15m/s * sin(60) = y
y ≈ 13 m/s

Now you can find the horizontal component:
cos = (adj)/(hyp)
cos(60) = (x)/(15m/s)
Multiply both sides by 15m/s
15m/s * cos(60) - x
x = 7.5

Therefore the answer is 2, the vertical (y) component is 13m/s and the horizontal (x) component is 7.5m/s.

The components of the velocity are :

(2) 13 m/s vertical and 7.5 m/s horizontal

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Further explanation

Vector is a quantity that has a magnitude and direction.

A vector in a cartesian coordinate is represented by an arrow in which the slope of the arrow shows the direction of the vector and the length of the arrow shows the magnitude of the vector.

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A position vector of a point is a vector drawn from the base point of the coordinates O (0,0) to that point.

The addition of two vectors can be done in the following ways:

\overrightarrow {AB} + \overrightarrow {BC} = \overrightarrow {AC}

A negative vector is a vector with the same magnitude but in opposite direction.

\overrightarrow {AB} = -\overrightarrow {BA}

Let's tackle the problem!

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Given:

magnitude of the velocity = v = 15 m/s

direction of the velocity = θ = 60°

Asked:

horizontal component of the velocity = v_x = ?

vertical component of the velocity = v_y = ?

Solution:

Firstly , we will calculate the horizontal component of the velocity as follows:

v_x = v \cos \theta

v_x = 15 * \cos 60^o

v_x = 15 * (1)/(2)

\boxed {v_x = 7.5 \texttt{ m/s}}

\texttt{ }

Next , we will calculate the vertical component of the velocity as follows:

v_y = v \sin \theta

v_y = 15 * \sin 60^o

v_y = 15 * (1)/(2) √(3)

v_y = 7.5 √(3) \texttt{ m/s}

\boxed {v_y \approx 13 \texttt{ m/s}}

\texttt{ }

Learn more

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Answer details

Grade: High School

Subject: Physics

Chapter: Vectors

Using newton's second law of motion, if the force on an object is 20n, and its mass is 5g, what is the acceleration? Can someone explain to me in a simple way how to do this? I have tried but the formulas I see are confusing. Thank you :)

Answers

Answer: The acceleration of the object will be 4000 m/s^2

Explanation:

According to second law of motion:

Force(F)=mass(m)* acceleration(a)

Unit of the force: N=kg* m/s^2

According to question we have :

Force = 20 N

Mass of the object = 5 g = 0.005 kg (1 kg =1000 g)

Acceleration = ?

By using the second law of motion = F= ma

20 N= 0.005 kg* a

a=(Force)/(mass)=(20 N)/(0.005 kg)=4000 m/s^2

The acceleration of the object will be 4000 m/s^2
Do 20 divided by 5 and you'll get 4! All you have to do is take the net force (20n) and divide it by the mass (5g) and you'll have the answer! :)

What is refractive index?

Answers

The refractive index of a substance is the ratio . . .

           (speed of light in vacuum) divided by (speed of light in the substance) .


So the speed of light in a substance is

           (299,792,458 meters per sec) divided by (the refractive index of the substance).
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