What is the potential energy of a 1-kilogram ball is thrown into the air with an initial velocity of 30m/sec?

Answers

Answer 1

Answer: the ball thrown from height=0
potental energy(PE) =0
kinetic energy(KE) = 0.5mv^2 = 0.5(1)(30^2) = 450

at the highest point the ball does not moved, v=0
potential energy at its maximum
kinetic energy = 0

Energy is conserved then
total energy before = after
PE1 + KE1 = PE2 + KE2
0 + 450 = PE2 + 0

conservation of energy is fun fact

Answer 2

Answer: mass=1kg
g=10m/s^2 (assuming)
u=30m/s
height(h)=u^2/2g
=900/20=45m
P.E.=mgh
=1×10×45=450 joules

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An ultrasound wave vibrates 30,000 times per second. what is the frequency

Answers

The frequency is 30,000 per second.
That's the same thing as 30 KHz.

N a nuclear reaction, mass must be lost to produce energy. true or false

Answers

The answer is true. Nuclear reactions, unlike chemical reactions, do not explicitly follow the law of conservation of mass in the sense that part of the mass is lost in nuclear reactions. In nuclear reactions, some of the mass is actually converted to energy. This is made possible due to Einstein's equation: E = mc^2. Also, nuclear reactions make use of nucleons which give off greater energies than chemical reactions.

A compact disc has a radius of 6 centimeters.a. What is its circumference in meters?
b. If the cd rotates 4 times per second, what is the linear speed of a point on the outer edge of the cd? Give
your answer in meters per second.
c. What is the linear speed of a point 3 centimeters from the center of the cd? (Assume the angular speed
has not changed).

Answers

Circumference is $2\pi{r}=37.7$ (approx.)
Speed is 4 times that. That is, 150.8 cm/s or 1.508 m/s.
If we get a point at distance 3 cm, we take the radius half of that. The circumference also gets half, so does the linear speed. We get 0.754 m/s or 75.398 cm/s.

Answer:75.389

Explanation:

The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration

Answers

Answer:The magnitude of the acceleration is $9.70 m/s^2$

Explanation:

Final velocity of the ball falling down ,v = 33 m/s

Initial velocity of the ball ,u= o m/s

Time taken by the ball to reach the ground ,t = 3.4 seconds

Acceleration of the ball during the fall = a

Using first equation of motion:

$v=u+at$

$33 m/s=0 m/s+a(3.4 s)$

$a=(33 m/s)/(3.4 s)=9.70 m/s^2$

The magnitude of the acceleration is $9.70 m/s^2$

The acceleration of the ball would be around 9.1666667m/s
To work this out use this formula

acceleration = distance*velocity/distance*time

The jovian planets contain a large percentage of the gases

Answers

The Jovian planets contain large percentage of Gases its because they are formed outside of what they called as frost line where temperature is low enough for ice condensation unlike terrestrial planets formed close to the sun where the temperature is very appropriate for metal and rock to condense.

The Jovian planets contain a large percentage of the gases Hydrogen and Helium.

88.0 km to m (in physics prefixes )

Answers

We know that,

kilometre = 1000 metre

1000 can be written as 10³ which is kilo.

Given,

88.0km = 88.0×1000

= 88.0×10³m

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