At the post office, Karen mails three packages that weigh 7.2, 7.5, and 7.9 pounds. The post office that Karenuses rounds the weight of a package to the nearest pound to determine the price of shipment. It costs $3 to
mail a package that weighs 7 pounds and $3.75 for packages that weigh 8 pounds.
(a) How much did Karen pay to ship each package?
(b) Karen has $10.25 in her wallet in cash. Use subtraction to determine whether Karen has enough to
mail the three packages and how much extra money she has or needs.

Answers

Answer 1

Answer: rounding
7.2 to 7
7.5 to 8
7.9 to 8

7 and 8 and 8

3+3.75+3.75=10.50

she has 10.25
10.25-10.50=-0.25
she is 0.25 short

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Anna is following this recipe to make biscuits.Anna uses 750 g of margarine.
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Answers

Answer:

130

Step-by-step explanation:

Solve for x. 1/36=6^(x-3)

Answers

$(1)/(36)=6^(x-3)\n6^(-2)=6^(x-3)\n-2=x-3\nx=1$

Please help with this question thank you.

Answers

Answer:

x = 5

Step-by-step explanation:

You can rewrite the right side, then equate the arguments of the log function.

4·ln(x) = 2·ln(25)

4·ln(x) = 2·ln(5^2)

4·ln(x) = 4·ln(5) . . . . . . . use the rule ln(a^b) = b·ln(a)

x = 5 . . . . . . . . . . . . . . . .divide by 4 and take the antilog

Answer:

x = 5

Step-by-step explanation:

Just as a note, you can look at x = 25 and know that it is not the answer. If it was, then you would get

4ln(25) = 2 ln(25) which reduces down to 4 = 2 when you divide by ln(25) on both sides.

4 ln(x) = 2 ln(25) Represent 25 as ln(5)^2

4 ln(x) = 2 ln(5)^2 The power on the right can be brought down.

4 ln(x) = 2 * 2 * ln(5) Divide both sides by 4

4 ln(x)/4 = 4 ln(5)/4

ln(x) = ln(5) Take the antiln of both sides.

antiln(ln(x)) = antiln(5)

x = 5

Factor the expression completely.

4x2 - 12x + 9

Answers

(2x - 3)(2x - 3)
the answer to the question

Using the distributive property to find the product (y — 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y2 – ay – 64. What is the value of a in the polynomial?

Answers

Answer:

Step-by-step explanation:

Since this is a multiplication of the square of (y+4) by (y-4) the value of Y will be eliminated in the product, if you want to assure this you just need to do the multiplication, and to do so we just need to multiply feach factor in the binomial by the polynomial:

$(y)(y^(2)+4y+16)= y^(3)+ 4y^(2) +16y\n(-4)(y^(2)+4y+16)=y^(2)-16y-64$

So now we know that the value for the Y is 16.

(y - 4)(y² + 4y + 16)

y³ + 4y² + 16y - 4y² -16y - 64

y³ + 4y² + ay - 4y² - ay - 64

a = 16

Yolanda owns 4 rabbits. She expects the number of rabbits to double every year.a) after how many years will she have 64 rabbits?

b) write and equation to model this situation

Show work plz

Answers

$a)\nn-after\ how\ many\ years\ will\ she\ have\ 64\ rabbits\n \n4\cdot (1-2^n)/(1-2) =64\ /:4\n \n(1-2^n)/(-1) =16\ \ \ \Leftrightarrow\ \ \ 2^n-1=16\ \ \ \Leftrightarrow\ \ \ 2^n=17>16\n \n2^n>2^4\n .\ \ \ \ \ \ \ \ \ \ \ \ \ \ a^b>a^c\ \ \wedge\ \ \ a>1\ \ \ \Rightarrow\ \ \ b>c\nn>4\n \nAns.\ Yolanda\ have\ 64\ rabbits\ after\ 4\ years$

$b)\nb-how\ much\ rabbits\ was\ in\ the\ beginning\nt-how\ many\ times\ will\ be\ an\ increase\ in\ the\ number\ of\ rabbits\n.\ \ \ \ in\ the\ years\ne-how\ many\ rabbits\ are\ expected\ Yolanda\n \n b\cdot (1-t^n)/(1-t) =e$

It is geometric sequence.
Therefore:
$a_1=4\n q=2\n S=a_1*(1-q^n)/(1-q)\n 64=4*(1-2^n)/(1-2)\n 16=(1-2^n)/(-1)\n -16=1-2^n\n 16+1=2^n\n 2^4+1=2^n\n n>4$

After 4 yours she will have over 64 rabbits.

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