What form of energy is found in surgar

Answers

Answer 1

Answer: Chemical energy would be the answer. :)

Answer 2

Answer:

well from what I know I am pretty sure that it is chemical energy

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The half-life for the process 238u→206pb is 4.5×109 yr. a mineral sample contains 61.0 mg of 238u and 15.5 mg of 206pb. part a what is the age of the mineral

Answers

The age of the mineral is 8.9×10⁹ years.

We'll begin by calculating the rate constant.

Half-life (t½) = 4.5×10⁹ years

Rate constant (K) =?

$K = (0.693)/(t_½) \n \n K = \frac{0.693}{4 * {10}^(9) } \n \n K = 1.54 * {10}^( - 10) /year \n \n$

Finally, we shall determine the age of the mineral.

Original amount (N₀) = 61.0 mg

Remain remaining (N) = 15.5 mg

Rate constant (K) = 1.54×10¯¹⁰ / year

Time (t) =?

$t = (2.303)/(k) log( (N_0)/(N) ) \n \n t = \frac{2.303}{1.54 * {10}^( - 10) } log( (61)/(15.5)) \n \n t = 8.9 * {10}^(9) years$

Therefore, the mineral is 8.9×10⁹ years old.

Learn more: brainly.com/question/25798542

What energy resource can be used instead of fossil fuel

Answers

We could use solar power, wind power, geothermal power, hydroelectric power, or nuclear power. There are probably more but this is what I can think of off the top of my head. I hope this helps. Let me know if anything is unclear.

What information do the coefficients of a balanced equation give about the reactants

Answers

The information that the coefficients of a balanced equation give about the reactants are to tell how many moles of reactants are needed and how many moles of product can be produced.

CaCO3---> CaO+CO2 How many moles of CaO form when 98.60g CaCO3 decompose? 98.60g CaCO3= ______ mol CaO

Answers

Answer:

0.9852 moles of CaO

Explanation:

Reaction equation for the decomposition of CaCO₃:

CaCO₃ → CaO + CO₂

The question asks how many moles of CaO form when 98.60g of CaCO₃ decompose.

We can see from the reaction equation that for every mol of CaCO₃, one mol of CaO will be produced (molar ratio 1:1)

_____________________________________________________

So first we need to calculate how many moles are the 98.60g of CaCO₃:

Molar Mass of CaCO₃ = molar mass Ca + molar mass C + 3 * molar mass O

= 40.078 + 12.011 + 3 * 15.999 = 100.086 g/mol

Moles of CaCO₃ = mass CaCO₃ / molar mass CaCO₃

Moles of CaCO₃ = 98.60 g / 100.086 g/mol = 0.9852 moles CaCO₃

________________________________________________________

As we said before for every mol of CaCO₃, one mol of CaO is produced.

So the decomposition of 0.9852 moles of CaCO₃ will produce 0.9852 moles of CaO.

Hey I think it is going to be 0986 moles. Cuz we can see that no. of moles of CaCO3 which will decompose is equivalent to the no. of CaO . Now it's just the matter of finding the no. of moles of CaCO3 .

no.of moles=mass /relative molecular mass

Please help me in this.
i'll seriously mark you brainly.
please help.

Answers

Answer:

First box: 3

Second box: 4

Third box: 3

Fourth box: 4

Explanation:

I tried out various numbers, but got 3 and 4 because:

3PbI4 + 4CrCl3 -----> 3PbCl4 + 4CrI3

Each term cancels put.

3Pb --> 3Pb

4Cr --> 4Cr

and so forth...

Hope this helps!

Which statement about one atom of an element identifies the element?(1) The atom has 1 proton. (2) The atom has 2 neutrons.(3) The sum of the number of protons and neutrons in the atom is 3.(4) The difference between the number of neutrons and protons in the atom is 1.

Answers

the atom has one proton

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