After the collapse of a nebular cloud, atoms begin gravitating together to form a condensed center. What happens next in the star formation process?

Answer:

The mechanical energy of the system increases, provided there is no loss of energy due to friction. The energy would transform to kinetic energy when the speed is increasing. The mechanical energy of the system remains constant provided there is no loss of energy due to friction.

Explanation:

Final answer:

An object's mechanical energy generally increases as its velocity increases. This is because mechanical energy is the sum of an object's kinetic and potential energy, and kinetic energy is directly proportional to the square of its velocity.

Explanation:

In physics, mechanical energy is the energy that an object has due to its motion (kinetic energy) and position (potential energy). When an object's speed or velocity changes, specifically increases, so does its kinetic energy, as kinetic energy is directly proportional to the square of the object's velocity. Essentially, if an object's velocity doubles, its kinetic energy would quadruple. However, this does not take into account variables like air resistance, friction, or changes in potential energy. In an ideal, frictionless scenario, an increase in an object's velocity directly results in an increase in its mechanical energy.

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Answer : Option D) Proton and Neutron.

Explanation : The part of the atom that carries a positive charge is the proton, and the part that carries a neutral charge is the neutron.

A proton is a small subatomic particle, denoted by symbol , with a positive electric charge of +1 e elementary charge and a mass which is slightly less than that of a neutron. It is located at the center o atomic nucleus along with neutron. The number of protons are equal to the number of electrons of that atom but are in opposite charges.

A neutron is a subatomic particle of an atom which is of the same mass as that of proton but without an electric charge, it is present in all atomic nuclei except those of ordinary hydrogen. It is also located at the center of an atomic nucleus.

Answer: Option (1) is the correct answer.

Explanation:

• A positron is a small particle which contains a +1 charge and its mass is equal to the mass of an electron, that is, kg.

A positron is represent by the symbol .

For example,

• Whereas nitrogen-16 does not decay to give a positron because nitrogen-16 is the daughter isotope formed due to decay of oxygen-16.

The decay reaction is as follows.

• And, on radioactive decay of thorium-232 there will be formation of radium-228 along with emission of an alpha particle.

The reaction will be as follows.

Therefore, we can conclude that out of the given options positrons are spontaneously emitted from the nuclei of potassium-37.

Answer:approximately 115.33 grams of H2O are needed to react with 3.20 moles of CaC2 in the given reaction.

Explanation:To determine how many grams of H2O are needed to react with 3.20 moles of CaC2 in the given reaction, we can use stoichiometry and the molar ratios between CaC2 and H2O in the balanced chemical equation.

First, let's write down the balanced chemical equation:

CaC2 (s) + 2H2O (l) -> C2H2 (g) + Ca(OH)2 (aq)

From the balanced equation, we can see that 1 mole of CaC2 reacts with 2 moles of H2O.

Now, let's use this information to calculate the moles of H2O required to react with 3.20 moles of CaC2:

Moles of H2O = (3.20 moles CaC2) * (2 moles H2O / 1 mole CaC2)

Moles of H2O = 3.20 moles * 2

Moles of H2O = 6.40 moles

Now that we know we need 6.40 moles of H2O, we can calculate the grams of H2O needed using the molar mass of H2O:

Molar mass of H2O = 2(1.01 g/mol) + 16.00 g/mol = 2.02 g/mol + 16.00 g/mol = 18.02 g/mol

Now, calculate the grams of H2O:

Grams of H2O = (6.40 moles) * (18.02 g/mol)

Grams of H2O ≈ 115.33 grams

So, approximately 115.33 grams of H2O are needed to react with 3.20 moles of CaC2 in the given reaction.

Answer:

The rubber becomes brittle and can break in your hand. The explanation for why this happens concerns cross-linking bonds. Ultra-violet light from the sun provides the polymer molecules with the activation energy they need to be able to form more cross-links with other chains.

Final answer:

If excessively excessive cross-links are formed in rubber, it becomes overly rigid and brittle, hampering its natural elasticity and strength. The increase in cross-links restricts the moving of the polymer chains, undermining the effectiveness of the rubber in many applications.

Explanation:

The formation of cross-links in rubber significantly affects its properties. In the case where too many cross-links are formed, the rubber is likely to become overly rigid and brittle. This is because the cross-links restrict the movement of the polymer chains, which reduces flexibility and elasticity. As a result, too many cross-links can compromise the usefulness of rubber for many applications, which require its natural elasticity and strength. For example, in a rubber band, if too many cross-links were formed, then it would be less stretchy and snap more easily when stretched.

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