What best describes how the testing of the initial version and the testing of the beta version fit into the four stages of the process of technological design

Answers

Answer 1

Answer:

The Testing of the initial version is carried out in the third stage to determine what needs to be improved, while the testing of the beta version is carried out during the fourth stage to ensure that all necessary criteria are met.

The process of technological design involves several distinctive processes which can be broken down into four stages.

The four stages involved in the process of technological design are :

Identify a need : during this process the engineer identifies a problem that needs to be resolved
design a solution : an initial design is created to provide a solution to the problem identified in stage 1
Implement the solution : The design is tested and implemented if successful
evaluate the solution : In this stage the result from the solution ( beta version ) is subjectedto ensure that all criteria are met

hence the testing of the initial version is to determine what needs improvement while the testing of the beta version is to ensure all criteria are met

learn more here: brainly.com/question/23367920

Answer 2

Answer:

Answer:

C. The initial version is tested during the third stage to determine what needs to be improved, and the beta version is tested during the fourth stage to ensure that criteria are met.

Explanation:

Edge 2021

Red

Explanation:

Red is diffracted the most due to its long wavelength. Compared to violet which is the shortest and is diffracted the least.

A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl + Ca(OH)2 > CaCl2 + 2H2O What was the molarity of the HCl solution?it is either 6.00 M or 0.375 M

Answers

The first step is to find the number of moles of OH⁻ that reacted with the HCl. To do this multiply 2.00L by 1.50M to get 3 moles of Ca(OH)₂. Then you multiply 3 by 2 (there are 2 moles of OH⁻ per every 1 mole of Ca(OH)₂) to get 6 moles of OH⁻. That means that you needed 6 moles of HCl since 1 mole of HCl contains 1 mole of H⁺ and equal amounts H⁺ and OH⁻ reacted with each other. To find the molarity of the HCl solution you need to divide 6mol by 1L to get 6M. Tat means that the concentration of the acid was 6M.

I hope this helps. Let me know if anything was unclear.

Answer:

D)- 6.00M

Explanation:

took test on edg

Based on enthalpy of formation data species ∆H◦ f H2S(g) −20.63 kJ/mol O2(g) 0 kJ/mol H2O(ℓ) −285.83 kJ/mol SO2(g) −296.83 kJ/mol calculate ∆Hrxn for 2 H2O(ℓ) + 2 SO2(g) ←→ 2 H2S(g) + 3 O2(g) 1. 562 kJ · mol−1 2. −562 kJ · mol−1 3. −1124 kJ · mol−1 4. 1124 kJ · mol−1

Answers

Answer: The enthalpy change of the reaction is 1124 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_(rxn)=\sum [n* \Delta H^o_f_{\text{(product)}}]-\sum [n* \Delta H^o_f_{\text{(reactant)}}]$

For the given chemical reaction:

$2H_2O(l)+2SO_2(g)\rightarrow 2H_2S(g)+3O_2(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_(rxn)=[(2* \Delta H^o_f_((H_2S(g))))+(3* \Delta H^o_f_((O_2(g))))]-[(2* \Delta H^o_f_((H_2O(l))))+(2* \Delta H^o_f_((SO_2(g))))]$

We are given:

$\Delta H^o_f_((H_2O(l)))=-285.83kJ/mol\n\Delta H^o_f_((O_2(g)))=0kJ/mol\n\Delta H^o_f_((SO_2(g)))=-296.83kJ/mol\n\Delta H^o_f_((H_2S(g)))=-20.63kJ/mol$