PHYSICS COLLEGE

While doing her crossfit workout, Yasmeen holds an 7.0 kg weight at arm's length, a distance of 0.57 m from her shoulder joint. What is the torque about her shoulder joint due to the weight if her arm is horizontal? A 30 N m B. 4.0 N m C. 43N-m D. 39 N m

Answers

Answer 1

Answer:

Answer:

D. 39 N m

Explanation:

m = mass of the weight used in crossfit workout = 7.0 kg

Force due to the weight used is given as

F = mg

F = (7.0) (9.8)

F = 68.6 N

d = distance of point of action of weight from shoulder joint = 0.57 m

τ = Torque about the shoulder joint due to the weight

Torque about the shoulder joint due to the weight is given as

τ = F d

Inserting the values

τ = (68.6) (0.57)

τ = 39 Nm

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Answers

Answer:

Explanation:

The average speed of a body is defined as the ratio between total distance and total time

v = dx / dt

v = 162.0 / 2.95

v = 54.9 m / s

The absolute errors (uncertainties) of the distance and time measurements as measured with instruments are the errors of the instruments

Δx = 0.1 cm

Δt = 0.01 s

Relative errors (uncertainties) are the absolute errors between the measured value

Er = Δx /x

Er = 0.1 / 162.0

Er = 6.2 10⁻⁴ length

Er = 0.01 / 2.95

Er = 3.4 10⁻³ time

The most uncertain measure is the time to have a greater relative error

Let's calculate the relative speed error

Δv / v = dv / dx dx + dv / dt dt

dv / dx = 1 / t

dv / dt = x (-1 / t²)

Er = Δv / v = 1 / t Δx + x / t² Δt

Er = 0.1 / 2.95 + 162.0/2.95² 0.01

Er = 0.034 + 0.19

Er = 0.22

We can observe that the relative error of time is much higher than the relative error of distance, so to reduce the speed error, time must be measured with much more precision

Absolut mistake

Er = Δv / v

Δv = Er v

Δv = 0.22 54.9

Δv = 12 cm / s

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Answers

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Answers

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Explanation:

Given that,

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Answers

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