kate has 4 3/8 of fabric and needs 2 7/8 yards to make a skirt. how much extra fabric will she have left?

Answers

Answer 1

Answer: 1 5/8 extra. Subtract 2 7/8 from 4 3/8. 3 11/8 -2 7/8= 1 5/8 :)

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(-2x) 4
O A. – 16x4
O B. -8x4
O C. -2xt
O D. 84
O E. 16x4

Answers

Answer:

The answer should be -8x

Step-by-step explanation:

You would use distiputive property and multiple four by negitive two and you would end up getting -8x

Which sequence is modeled by the graph below?coordinate plane showing the points 2, 1; 3, 3; and 4, 9

an = one third(27)n − 1

an = 27(one third)n − 1

an = one third(3)n − 1

an = 3(one half)n − 1

Answers

Answer:

$a_n=(1)/(3)\cdot (3)^(n-1)$

C is correct.

Step-by-step explanation:

We need to choose correct model by the graph which passes through the points (2,1) (3,3) and (4,9)

Option 1: $a_n=(1)/(3)\cdot (27)^(n-1)$

Put n=2 and to get a₂=1

$a_2=(1)/(3)\cdot (27)^(2-1)$

$a_2=9$

$9\neq 1$

False

Option 2: $a_n=27\cdot ((1)/(3))^(n-1)$

Put n=2 and to get a₂=1

$a_2=27\cdot ((1)/(3))^(2-1)$

$a_2=9$

$9\neq 1$

False

Option 3: $a_n=(1)/(3)\cdot (3)^(n-1)$

Put n=2 and to get a₂=1

$a_2=(1)/(3)\cdot (3)^(2-1)$

$a_2=1$

$1= 1$

TRUE

Similarly, we will check (3,3) and (4,9)

and we will get true

Hence, The sequence is $a_n=(1)/(3)\cdot (3)^(n-1)$

Answer:

the answer is C. an = one third (3)n − 1

i just took the test.

Step-by-step explanation:

Ron grew 224 flowers with 56 seed packets. How many seed packets does Ron need to have a total of 324 flowers in his garden? Assume the relationship is directly proportional.

Answers

Answer:

the relationship is directly proportional.

224 flowers 324 flowers

56 seed packets (324*56)/224=81 seed packets

Cynthia has $2.15 worth of change in her pocket. She has three more nickels than quarters and twice as many dimes as quarters. How many of each type coin has she?

Answers

Answer:

7 nickles

8 dimes

4 quarters

Step-by-step explanation:

d = 2q

n = q+3

25q + 10d + 5n = 215

25q + 10(2q) + 5(q + 3) = 215

25q + 20q + 5q - 15 = 215

50q = 200

q = 4

d = 2q = 8

n = q + 3 = 7

There are 20 seniors serving the student council of the Cebu Institute of Technology this year. Of these, 3 have not served before, 10 served on the council in their junior years, 9 in their sophomore years, and 11 in their freshman years. There are 5 who served during both their sophomore and junior years, 6 during both their freshman and junior years, and 4 during both their freshman and sophomore years. How many seniors served on the student council during each of the four years in high school?

Answers

Answer:15 seniors served on the student council during their freshman year, 14 seniors served during their sophomore year, 16 seniors served during their junior year, and 3 seniors have never served before.

Step-by-step explanation:

Final answer:

Using inclusion and exclusion principles, we find that 2 seniors served on the student council during each of the four years in high school.

Explanation:

The problem can be solved using the Principle of Inclusion and Exclusion (PIE), a common technique in combinatorial mathematics. First, we add the number of seniors serving in their freshman, sophomore, and junior years: 3 (never served) + 10 (junior) + 9 (sophomore) + 11 (freshman) giving us 33.

Then, we subtract the number of seniors who served during both sophomore and junior years, freshman and junior years, and freshman and sophomore years: 33 - 5 (sophomore and junior) - 6 (freshman and junior) - 4 (freshman and sophomore). This results in 18.

However, from the initial condition we know that there are 20 seniors in total. Therefore, the two 'extra' seniors must have served all four years in high school. Thus we find that 2 seniors served on the student council during each of the four years in high school.

Learn more about Inclusion and Exclusion Principle here:

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In a particular class of 23 students, 11 are men. What fraction of the students in the class are women?

Answers

if 11/23 are men, then the women are (23 - 11)/23 = 12/23

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