Simplify square root of 3 times square root of 21

Answers

Answer 1
Answer:

Step-by-step explanation: To multiply the square root of 3 times the square root of 21, we simply multiply the numbers that are inside the square roots together.

So, root 21 × root 3 equals root 63.

Next, we simplify the square root of 63. 63 factors as 3 x 21 and 21 factors as 3 x 7. So we have a pair of 3's which means a 3 can come out of the radical and the 7 doesn't pair up stays in the radical so our final answer is \sqrt[3]{7}.

Answer 2
Answer:

3√7 is the simplified value of the given expression.

To simplify the expression √3 * √21, we can combine the square roots and simplify under one radical if possible.

√3 * √21 = √(3 * 21)

Simplifying the product inside the radical:

√(3 * 21) = √63

Now, we can simplify further by factoring 63 into its prime factors:

√(3 * 21) = √(3 * 3 * 7)

Taking the square root of each factor:

√(3 * 3 * 7) = √3 * √3 * √7 = 3 * √7

Therefore, √3 * √21 simplifies to 3√7.

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2y = x + 3 5y = x - 7 What is the solution set of the given system? {(-1/3, -4/3)} {(1/3, 4/3)} {(-29/3, -10/3)} {(29/3, 10/3)}

Answers

I hope it cleared your doubt.

The answer for this question is option C.


What is the factored form of 2x2 − 7x + 6?

Answers

split -7 up so that one is a multiplule of 2 and the other is a factor of 6

2x^2-4x-3x+6
(2x^2-4x)+(-3x+6)
undistribute
(2x)(x-2)+(-3)(x-2)
undistribute
(2x-3)(x-2)

the factored form of 2x² - 7x + 6 is (2x - 3)(x - 2).

To find the factored form of the quadratic expression 2x² - 7x + 6, we can look for two binomials that, when multiplied, give us the original expression.

First, we need to determine two numbers that multiply to give 12 (the product of the leading coefficient, 2, and the constant term, 6) and add up to -7 (the coefficient of the linear term, -7).

The numbers -4 and -3 fit these conditions.

Now, we can express the quadratic expression in factored form:

2x² - 7x + 6 = (2x - 3)(x - 2)

Therefore, the factored form of 2x² - 7x + 6 is (2x - 3)(x - 2).

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What is the aswer ??????​

Answers

Answer:

The correct statement is Aprimenumberarenumberswhichhaveonlytwofactor.

Explanation:

Hope it helps you..

Your welcome in advance..

(ㆁωㆁ)

Answer:

A prime number is one which can be divided only by itself

please give brainliest

Which of the following is the inverse of the statement "If I like math, then I like science"?

Answers

the inverse statement means to say the opposite of both the if and then statementSince I don't see your choices this is the statementIf I DO NOT like math then I DO NOT like sciencehope this helps

Answer:

If I do not like math, then I do not like science

Step-by-step explanation:

we know that

To find the inverse of a conditional, negating both the hypothesis and conclusion of a conditional statement

In this problem we have

"If I like math, then I like science"

therefore

the inverse is

If I do not like math, then I do not like science


Please simplify

5×3−8÷2×3

Answers

The answer would be 3! You can find this using PEMDAs, aka order of operations. Hope this helps!!

Answer:

Use PEMDAS

Step-by-step explanation:

answer is 7/6 i think

i am not 100% sure

Identify each expression that represents the slope of a tangent to the curve y= -x^3+17x^2-x+3 at any point (x,y).

Answers

This is seriously so long I'm not sure it will even fit on a single line. The formula for the derivative using the limiting process is \lim_(h \to 0) (f(x+h)-f(x))/(h). And of course this is a problem because if h approaches 0, we would have a 0 in the denominator of that fraction and that is definitely not allowed! Every x in the function will be replaced with (x+h) to give us this: \lim_(h \to 0) (-(x+h)^3+17(x+h)^2-(x+h)+3)/(h). When we expand that we will get this very long numerator (I'm purposely leaving out the limit as h approaches 0 part to save space): (-(x^3+2x^2h+xh^2+x^2h+2xh^2+h^3)+17x^2+34xh+17h^2-x-h+3-(-x^3+17x^2-x+3))/(h). Simplifying that leaves us with this: (-x^3-2x^2h-xh^2-x^2h-2xh^2-h^3+17x^2+34xh+17h^2-x-h+3+x^3-17x^2+x-3)/(h). We have a lot of terms that cancel each other out so when we do that we are left with \lim_(h \to 0) (-3x^2h-3xh^2-h^3+34xh+17h^2-h)/(h). That is one of your choices for answers, the third one down on the left to be specific. Now we can factor out an h: \lim_(h \to 0) (h(-3x^2-3xh-h^2+34x+17h-1))/(h). That h on the top outside the parenthesis cancels with the h on the bottom. Now, as h approaches 0 we have no problems! Yay! That means when we now replace h with 0, we have this: -3x^2-0-0+34x+0-1, or simplified we have -3x^2+34x-1 which is also a choice for your answers, top one on the right. Those are your 2 answers for that dertivative. It's much simpler when you learn the rules!