MATHEMATICS HIGH SCHOOL

multiplying polynomials

find the product

(2a-1)(8a-5)

Answers

Answer 1
Answer:

The product of (2a-1)(8a-5) is 16a² - 18a + 5.

To find the product of (2a-1)(8a-5), we can use the distributiveproperty. This means that we multiply each term in the first polynomial (2a-1) by each term in the second polynomial (8a-5) and then combine like terms.

Applying the distributive property, we have:

(2a-1)(8a-5) = 2a(8a) + 2a(-5) - 1(8a) - 1(-5)

Simplifying this expression, we get:

16a² - 10a - 8a + 5

Combining liketerms, we have:

16a² - 18a + 5

Therefore, the product of (2a-1)(8a-5) is 16a² - 18a + 5.

In this case, we multiplied each term of the first polynomial by each term of the second polynomial, resulting in four terms. Then, we combined like terms to simplify the expression. The final product is a quadratic polynomial with a leading coefficient of 16 and terms involving the variable 'a'.

To learn more about Polynomials;

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Answer 2
Answer: (2a - 1) (8a - 5)

= {2a(8a - 5)} - {1(8a - 5)}

= 16a² - 10a - 8a + 5

= 16a² - 18a + 5

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Answers

Answer:

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PLEASE ANSWER FAST!
Find BDC.
BDC=​

Answers

Step-by-step explanation:

<NDC=<NCD (Given)

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<CAN=<DBN (Given)

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therefore, <CND = 180-35-35=110.

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Answer:

angle BDC= 95°............

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