A car of mass m accelerates from speed v_1 to speed v_2 while going up a slope that makes an angle theta with the horizontal. The coefficient of static friction is mu_s, and the acceleration due to gravity is g. Find the total work W done on the car by the external forces.

Answers

Answer 1
Answer:

Answer:

Work done by external force is given as

Work_(external) = mgLsin\theta + \mu mgLcos(\theta) + (1)/(2)mv_2^2 - (1)/(2)mv_1^2

Explanation:

As per work energy Theorem we can say that work done by all force on the car is equal to change in kinetic energy of the car

so we will have

Work_(external) + Work_(gravity) + Work_(friction) = (1)/(2)mv_2^2 - (1)/(2)mv_1^2

now we have

W_(gravity) = -mg(Lsin\theta)

W_(friction) = -\mu mgcos(\theta) L

so from above equation

Work_(external) - mgLsin\theta - \mu mgLcos(\theta) = (1)/(2)mv_2^2 - (1)/(2)mv_1^2

so from above equation work done by external force is given as

Work_(external) = mgLsin\theta + \mu mgLcos(\theta) + (1)/(2)mv_2^2 - (1)/(2)mv_1^2


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Answers

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Explanation:

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Answers

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Answer:

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Answers

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Explanation:

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Explanation: