The reaction of ethyl acetate with sodium hydroxide, CH3COOC2H5(aq)+NaOH(aq)⇌CH3COONa(aq)+C2H5OH(aq) is first order in CH3COOC2H5 and first order in NaOH. If the concentration of CH3COOC2H5 was increased by half and the concentration of NaOH was quadrupled, by what factor would the reaction rate increase?
Answers
Answer:
so the reaction rate increases by a factor 6.
Explanation:
For the given equation the reaction is first order with respect to both ester and sodium hydroxide
So we can say that the rate law is
now as per given conditions the concentration of ester is increased by half it means that the new concentration is 1.5 times of old concentration
The concentration of NaOH is quadrupled means the new concentration is 4 times of old concentration.
The new rate law is
the final rate = 6 X initial rate
so the reaction rate increases by a factor 6.
Related Questions
Be sure to answer all parts. Styrene is produced by catalytic dehydrogenation of ethylbenzene at high temperature in the presence of superheated steam. (a) Given these data, find ΔH o rxn , ΔG o rxn , and ΔS o rxn at 298 K: ΔH o f (kJ/mol) ΔG o f (kJ/mol) S o (J/mol·K) Ethylbenzene, C6H5−CH2CH3 −12.5 119.7 255 Styrene, C6H5−CH=CH2 103.8 202.5 238 ΔH o rxn ΔG o rxn ΔS o rxn kJ kJ J/K (b) At what temperature is the reaction spontaneous? °C (c) What are ΔG o rxn and K at 600.°C? ΔG o rxn K kJ/mol × 10 Enter your answer in scientific notation.
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1. Why the names such as sodium(l) chloride for NaCl andmagnesium(II) chloride for MgCl2 are not used?
What is the pH of a 0.45 M solution of hydrochloride acid (H
Answers
0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.
What is a mole?
One mole of any substance is the amount of the substance which contain 6.023 × 10²³ atoms or molecule if the substance is atomic or molecular in nature and known as gram atomic mass.
Number of atoms in carbon is 9.00 grams and isotope are 13C,
Number of moles = weight of substance / mass of substance
Substituting the value in formula,
Number of moles = 9.00 grams / 13
Number of moles = 0.629 moles
Therefore, 0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.
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Answers
Answer: Option (2) is the correct answer.
Explanation:
Atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. So, it contains only 2 orbitals which are closer to the nucleus of the atom.
As a result, the valence electrons are pulled closer by the nucleus of oxygen atom due to which there occurs a decrease in atomic size of the atom.
Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6. As there are more number of orbitals present in a sulfur atom so, the valence electrons are away from the nucleus of the atom.
Hence, there is less force of attraction between nucleus of sulfur atom and its valence electrons due to which size of sulfur atom is larger than the size of oxygen atom.
Thus, we can conclude that the oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.
Final answer:
The oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.
Explanation:
The correct option is (2) the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.
To understand why the oxygen atom is smaller than the sulfur atom, we need to consider their electron configurations. Oxygen has 8 electrons and sulfur has 16 electrons. Oxygen's electron configuration is 1s²2s²2p⁴, while sulfur's electron configuration is 1s²2s²2p⁶3s²3p⁴.
The outer orbitals of an atom, which are the valence orbitals, are the ones involved in bonding. The electrons in these orbitals determine the size of the atom. In the case of oxygen and sulfur, the outer orbitals of oxygen (2p orbitals) are closer to the nucleus compared to sulfur's outer orbitals (3p orbitals). As a result, the oxygen atom is smaller than the sulfur atom.
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Answers
Complete question is;
What is the frequency of light emitted when the electron in a hydrogen atom undergoes a transition from energy level n=6 to level n=3?
Answer:
Frequency = 2.742 × 10^(14) s^(-1)
Explanation:
First of all, the energy of hydrogen electron from online values is;
E_n = -2.18 × 10^(-18) × (1/n²) J
n is the principal quantum number
We are told that hydrogen atom undergoes a transition from energy levels n = 3 to n = 6.
Thus, it means we have to find the difference between the electrons energy in the energy levels n = 3 to n = 6.
Thus;
E_n = E_6 - E_3
Thus;
E_n = [-2.18 × 10^(-18) × (1/6²)] - [-2.18 × 10^(-18) × (1/3²)]
E_n = (2.18 × 10^(-18)) × [-1/36 + 1/9]
E_n = 0.1817 × 10^(-18) J
From Planck expression, we can find the frequency. Thus;
E = hf
Where h is Planck's constant = 6.626 × 10^(-34) m²kg/s
Thus;
0.1817 × 10^(-18) = 6.626 × 10^(-34) × f
f = (0.1817 × 10^(-18))/(6.626 × 10^(-34))
f = 2.742 × 10^(14) s^(-1)
Final answer:
The frequency of light emitted during an electron transition in a hydrogen atom is determined by calculating the energy difference between the two energy levels and then using this to calculate the frequency using the equation for energy of a photon.
Explanation:
The frequency of light emitted during a transition of an electron in a hydrogen atom can be calculated using the formula for the energy difference (∆E) between two energy levels n1 and n2 in the hydrogen energy level diagram.
The formula to calculate energy difference is: ∆E = E(n2) - E(n1) where E(n) represents the energy of an energy level n. The energy difference ∆E is negative when an electron goes down an energy level (i.e., emits a photon), as the energy level n1 is greater than n2.
The frequency of the emitted photon (∆E) is then given by the formula ∆E = hf where h is Planck's constant (6.63 x 10^-34 Joule seconds) and f is the frequency. Therefore, you can rearrange the equation to find the frequency: f = ∆E / h.
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Answers
Explanation:
2NOBr(g) --> 2NO(g) 1 Br2(g)
Rate constant, k = 0.80
a) Initial concentration, Ao = 0.086 M
Final Concentration, A = ?
time = 22s
These parameters are connected with the equation given below;
1 / [A] = kt + 1 / [A]o
1 / [A] = 1 / 0.086 + (0.8 * 22)
1 / [A] = 11.628 + 17.6
1 / [A] = 29.228
[A] = 0.0342M
b) t1/2 = 1 / ([A]o * k)
when [NOBr]0 5 0.072 M
t1/2 = 1 / (0.072 * 0.80)
t1/2 = 1 / 0.0576 = 17.36 s
when [NOBr]0 5 0.054 M
t1/2 = 1 / (0.054 * 0.80)
t1/2 = 1 / 0.0432 = 23.15 s
Answer:
(a)
(b)
Explanation:
Hello,
(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:
(b) Now, for a second-order reaction, the half-life is computed as shown below:
Therefore, for the given initial concentrations one obtains:
Best regards.
Answers
The main issues of using synthetic polymers include toxicity poor biocompatibility etc. Synthetic polymers stay non-degradable for ling time and make the surface polluted.
What are synthetic polymers?
Natural polymers are naturally made substances such as cellulose, starch, glycogen etc. Polymers made by man are called synthetic polymers. Synthetic polymers are diverse and are made through several polymerization techniques.
PVC, polyethylene, polyesters Teflon etc. are very common polymers in daily life. A major class of synthetic polymers include plastics which are major pollutants nowadays.
Most of the synthetic polymers are non-biodegradable and will cause landfill issues. Some them are toxic in nature and might cause several health issues. Blending them with biodegradable polymers is a solution for this.
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Answer: As trash, Synthetic Polymers are not biodegradable. Landfills can easily fill up with synthetic polymers. Plastics can be made into different products. Recycling synthetic polymers is costly.
Explanation: Hope this helps in any way possible!
Answers
Answer:
Because as the concentration is diminished, the capacity to transfer electricity is diminished as well.
Explanation:
Hello!
In this case, since electrolytes are substances that are able to conduct the electricity in aqueous media (solutions in which water is the the solvent) because they have the capacity to form ions with both positive and negative charges, due to the fact that HCl is a strong acid, we notice it is fully ionized in solution and therefore it is a strong electrolyte. However, when the concentration is diminished, we can notice that strength is diminished as well because less ions will have the capacity to transfer the electricity and therefore it'd become a poor conductor or weak electrolyte.
Best regards!