If a sodium atom lost one of its electrons and a chlorine atom gained it, what kind of bond would be formed between sodium and chlorine?a. ionic
b. valence
c. metallic
d. covalent

Answers

Answer 1
Answer: This would be an ionic bond.  Ionic bonds form between metals and nonmetals due to the relatively large different in electronegativities where nonmetals are more electronegative than metals.  This difference in electronegativities makes it so that the metal gives up the electron to make an octet and the nonmetal gains the electron to make an octet (there is no sharing of the electron).  The metal becomes a cation while the nonmetal becomes a anion and their opposite electric charges keep them together.

I hope this helps let me know in the comments if anything is unclear.
Answer 2
Answer: With no doubt, this type of bond would be ionic.

An ionic bond is when we transfer electrons. This means that the atoms would gain a charge.

Na+Cl- would be the resulting compound because:-

Na (sodium) loses : which means it would GAIN a positive charge.

Cl (chlorine) gains: which means it GAINS a negative charge.


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A solid precipitate is formed from the reaction of lead nitrate and sodium chromate. What would be the best method to separate this solid from the solution? distillation evaporation filtration sorting

What are cumulative pollutant examples?

Answers

a very fatal disese that causes you to poop blood 

How many grams of iron metal do you expect to be produced when 265 grams of an 84.5 percent by mass iron (II) nitrate solution react with excess aluminum metal? Show all of the work needed to solve this problem. 2Al (s) + 3Fe(NO3)2 (aq) yields 3Fe (s) + 2Al(NO3)3 (aq)

Answers

The balanced reaction is:

2Al (s) + 3Fe(NO3)2 (aq) = 3Fe (s) + 2Al(NO3)3 (aq)

We are given the amount of iron (II) nitrate solution with its purity. This will be the starting point of our calculation.

265 (.845) gram 
iron (II) nitrate (1 mol Fe(NO3)2 / 179.85 g Fe(NO3)2) ( 3 mol Fe / 3 mol Fe(NO3)2) (55.85 g Fe / 1 mol Fe) = 69.54 g Fe

If gas particles start colliding with the walls of their metallic container with increase force what is their direct effect

Answers

Answer: The increase in force will directly effect the pressure exerted by the gas that is high pressure of the gas.

Explanation:

The pressure is defined as force applied per unit area.

Pressure=(Force)/(Area)

Pressure\propto Force

If the gas particles colliding with the walls of container with increase in force then the pressure of the gas exerted by the particles of the gas will also get increased.

I believe your answer would be higher gas pressure.

How is the charge of an atom determined?
how is the amount of neutrons determined?

Answers

Atoms have positively charged protons and negatively charged electrons, the number of each tells you the charge.
The ionic charge is the number of protons subtracted by the number of electrons. They usually have the same charge, but with opposite signs, Electrons ( -) and protons ( +)
 To find the neutron number,subtract the proton number from the atomic mass. It will give you the neutron number.
Hope this helps.
 

Carbon dioxide is one of the main gases in the mixture of gases coming out of the kiln.Give two reasons why.

Answers

because the kiln utilizes fire, fire uses oxygen and the fuel to create CO2
CO2 would be the main gas because the main components of the reactants are carbon and oxygen, which make up CO2

For the same mixture, under the same conditions described in problem 7, calculate keq for 2nh3 (g) n2 (g) + 3h2(g). how is the keq for a forward reaction related to the keq for a reverse reaction

Answers

Answer: The relation between the forward and reverse reaction is K_f=(1)/(K_r)

Explanation:

For the given chemical equation:

2NH_3(g)\rightleftharpoons N_2 (g)+3H_2(g)

The expression of equilibrium constant for above equation follows:

K_f=([N_2][H_2]^3)/([NH_3]^2)         .......(1)

The reverse equation follows:

N_2 (g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression of equilibrium constant for above equation follows:

K_r=([NH_3]^2)/([N_2][H_2]^3)       .......(2)

Relation expression 1 and expression 2, we get:

K_f=(1)/(K_r)

Hence, the relation between the forward and reverse reaction is K_f=(1)/(K_r)