Choose the correct answer. The cord you use to plug in an electric lamp has an outer protective covering made of rubber or plastic because, unlike most metals, neither rubber nor plastic is a good ______________ of electricity.A) hypothesis

B) force

C) energy

D) conductor

Answers

Answer 1

Answer: D) conductor of electricity

Related Questions

Jose’s lab instructor gives him a solution of sodium phosphate that is buffered to a pH of 4. Because of an error that he made while calibrating the pH meter, Jose’s measurements of the pH of the sodium phosphate solution are 5.4, 5.4, and 5.4. Which statement best describes his results?
Starvation is the result of a mal-distribution of food, which is primarily due to drought and a lack of resources.exportation.civil war.dictatorships.
All points to the blank of zero on a horizontal number line are negative.
Why is the efficiency of a machine always less than 100 percent
A quarter is 2.4 millimeters thick. How tall are the following stacks of quarters?a. A stack worth 50 cents b. A stack worth $1 c. A stack worth $5 d. A stack worth $1,000 (Give your answer in millimeters and meters.)

Calculate the resistance of a lamp that draw 0.75 A current when connected to 4.5 V.

Answers

Calculate the resistance using the equation:

V=IR

In the question, the following values are given:

V = 4.5
I = 0.75

Substitute the values into the equation to find R, the resistance:

V = IR

4.5 = 0.75R

R = 4.5 / 0.75

R = 6 ohms

A police car is traveling at a velocity of 18.0 m/s due north, when a car zooms by at a constant velocity of 42.0 m/s due north. After a reaction time of 0.800 s the policeman begins to pursue the speeder with an acceleration of 5.00 m/s2. Including the reaction time, how long does it take for the police car to catch up with the speeder?

Answers

Answer:

t = 10.4 s

Explanation:

given,

velocity of the police car = 18 m/s

reaction time of policeman = 0.8 s

acceleration of the policeman to catch up the speeder = 5 m/s²

time taken to catch the speeder be t₁

distance traveled by the police and the speeder will be same

$D_p = D_s$

$u t_1 + (1)/(2)at_1^2 = u' t_1$

$18* t_1+ 0.5 * 5* t_1^2= 42* t_1$

$2.5 t_1^2 - 24 t_1 = 0$

$(2.5 t_1 - 24)t_1 = 0$

$t_1 = (24)/(2.5)$

t₁ = 9.6 s

total time taken by the policeman

= reaction time + t₁

= 0.8 + 9.6

t = 10.4 s

Total time taken by the policeman to catch the speeder is 10.4 s

The frequency of a purple photon is 7.14×10^14 Hz. Which equation should be used to solve for the wavelength of the photon?

Answers

Answer:

420.17 nm

Explanation:

Given:

f = 7.14 × 10¹⁴Hz

c = 3 × 10⁸ m/s

c = fλ

λ = c/f

$=(3*10^8)/(7.14*10^(14))$

$=(3)/(7.14)*10^((8-14))$

$=0.42017*10^(-6)$

$=420.17*10^(-9)$

= 420.17 nm

Three balls leave the edge of a table at the same time. Ball A rolls off the table with an initial horizontal velocity. Ball B is launched at an angle and has both an initial horizontal and vertical velocity. Ball C is dropped from rest, and has no initial velocity.a) Explain which one(s) hit the ground first.

b) Explain which one(s) hit the ground last

Answers

Explanation:

Balls A and C have the same initial vertical velocity of zero. Therefore, they land at the same time.

Ball B has a positive initial vertical velocity, so it hits the ground last.

Which of the following bodies has a brightness that surpasses Venus’? My options are Jupiter, Mars, the stars, and the Moon. Jupiter and mars are obviously out and Venus is brighter than all the stars in the sky (besides the sun lol) so it would be the moon right? just a lil confused.

btw i'm not sure what subject to post this in since there's no astronomy subject.

Answers

Answer: the Moon.

Explanation:

Brightness of celestial object is given in terms of magnitude. Apparent magnitude reflects how bright an object appears from the Earth. The apparent magnitude of the Moon is (-12.7 )greater than the apparent magnitude of the Venus (-4.4). The more negative value, the brighter is the object. Thus, the brightness of the moon surpasses the brightness of Venus.

Hi there!

The answer would be the stars. Since the sun is a star, the star is the answer. A star is much, much hotter than Venus, making it much brighter.

Hope this helps!

Problem 5. A bullet leaves a rifle with a velocity of 452 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.93 m. Determine the acceleration of the bullet.

Answers

Answer:

1.1 x 10⁵m/s²

Explanation:

Given parameters:

Velocity = 452m/s

distance = 0.93m

Unknown:

Acceleration of the bullet = ?

Solution:

To solve this problem, we use one of the kinematics equation which is given below:

V² = U² + 2aS

V is the final velocity

U is the initial velocity = 0m/s

a is the unknown acceleration

S is the distance traveled

So;

452² = 0² + (2 x a x 0.93)

204304 = 1.86a

a = 1.1 x 10⁵m/s²

Final answer:

The acceleration of the bullet in the gun barrel can be calculated using the kinematic equation for motion. By substituying the given values into the equation, we find the acceleration to be approximately 1.095 x 10^5 m/s^2.

Explanation:

The subject of this question is Physics, specifically a topic under mechanics known as kinematics. The problem given can be solved using kinematic equations which are used to describe the motion of an object without considering the forces that cause it to move. In this case, the final velocity (vf) of the bullet is given as 452 m/s, the initial velocity (vi) is assumed to be 0 as it starts from rest, and the distance (d) is given as 0.93 m. We are asked to determine the value of acceleration (a).

Using the kinematic equation vf2 = vi2 + 2ad and substituting the given values, we get (452 m/s)2 = 0 + 2*a*0.93 m. We can rearrange to solve for acceleration to get: a = (452 m/s)2 / (2*0.93 m) = 109523.66 m/s2.

So, the acceleration of the bullet in the gun barrel is approximately 1.095 x 105 m/s2.