Answer:Following is the c++ code for the problem:
#include <iostream>
using namespace std;
int main() {
int number;
cout<<"Enter the number"<<endl;
cin>>number;
int i=0,c=0,odd[500];
while(i<=number)//loop for printing the numbers form 0 to number.
{
cout<<i<<" ";
if(i%2!=0)// storing in the odd array if the number is odd.
{
odd[c++]=i;//storing odd numbers..
}
i++;
}
cout<<endl;
i=0;
cout<<"The odd numbers are "<<endl;
while(i<c)//loop to print the odd numbers.
{
cout<<odd[i]<<" ";
i++;
}
cout<<endl<<"The prime numbers are "<<endl;
i=0;
int sum=0;
while(i<c)//loop to print the prime numbers..
{
int div=2;
while(div<odd[i])
{
if(odd[i]%div==0)
break;
div++;
}
if(div==odd[i])
{
cout<<odd[i]<<" ";
sum+=odd[i];//updating the sum..
}
i++;
}
cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..
return 0;
}
Output :
Enter the number
49
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49
The odd numbers are
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49
The prime numbers are
3 5 7 11 13 17 19 23 29 31 37 41 43 47
The sum of odd prime numbers is 326.
Explanation:
First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum.These all operations are done using while loop.
Answer:
To edit an existing pattern, double-click the pattern in the pattern swatch, or select an object containing the pattern and choose Object > Pattern > Edit Pattern
if (str.indexOf("pea") >= 0)
{
System.out.println("pea");
}
else if (str.indexOf("pear") >= 0)
{
System.out.println("pear");
}
else if (str.indexOf("pearl") >= 0)
{
System.out.println("pearl");
}
II.
if (str.indexOf("pearl") >= 0)
{
System.out.println("pearl");
}
else if (str.indexOf("pear") >= 0)
{
System.out.println("pear");
}
else if (str.indexOf("pea") >= 0)
{
System.out.println("pea");
}
Which of the following best describes the output produced by code segment I and code segment II?
Both code segment I and code segment II produce correct output for all values of str.
Neither code segment I nor code segment II produce correct output for all values of str.
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pear" but not "pearl".
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pearl".
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".
Answer:
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".
Explanation:
The main issue with the first code segment is the way how the if else if condition are arranged. The "pea" is checked at the earliest time in the first code segment and therefore so long as there is the "pea" exist in the string (regardless there is pear or pearl exist in the string as well), the if condition will become true and display "pea" to terminal. This is the reason why the code segment 1 only work for the values of str that contain "pea".
screen
power supply
RAM
second part
hard disk
keyboard
touchpad
Answer:
Power supply and Hard disk
Explanation:
Answer:
Establishing Tight deadlines for a rush job.
Explanation:
The time taken for a rush job has nothing to do with the art director because it has nothing to do with art. Also rush jobs already call for tight deadlines so technically the deadline is already established.
Answer: cropping a photograph for the sake of space
Explanation: edge 22
Answer:
B.
Explanation:
In Javascript, the if should have a condition attached to it with parenthesis and curly braces.
Answer:
Following are the program in the Python Programming Language.
#define function
def isPalindrome(test):
#set the if condition to check tuple is empty
if(len(test)==0):
return True
#Check the tuple contain 1 element
elif(len(test)==1):
return True
#check the element of tuple is palindrome or not
else:
lenth=len(test)
#check first last element is equal or not
if(test[0]==test[lenth-1] and isPalindrome(test[1:lenth-1] ) ):
#then, return true
return True
#otherwise
else:
#Return False,
return False
#define tuple type variable and initialize
test=(1,2,3,4,3,2,1)
#print and call the function
print(isPalindrome(test))
Output:
True
Explanation:
Here, we define a function "palindrome()" and pass an argument in its parameter, inside the function.