If 20 milliliters of 4.0 M NaOH is exactly neutralized by 20 milliliters of HCL, the molarity of the HCL is

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Answer 1
Answer: Volume of NaOH = 20 mL / 1000 = 0.02 L

Molarity NaOH = 4.0 M

number of moles NaOH :

n = M * V

n = 4.0 * 0.02

n = 0.08 moles of NaOH:

Finally we calculate the number of moles of HCl in the solution from the stoichiometry of the reaction :
HCl + NaOH = NaCl + H₂O

1 mole HCl ---------- 1 mole NaOH
? moles HCl --------- 0.08 moles NaOH

moles HCl = 0.08 * 1 / 1

= 0.08 moles of HCl

Volume of HCl = 20 mL / 1000 = 0.02 L

M ( HCl ) = n  / V

M = 0.08 / 0.02

4.0 M

hope this helps!
Answer 2
Answer:

Answer:

4.0

Explanation:


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Place the terms compounds; mixtures, and elements in the proper sequence according to increasing complexity

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The basic form of matter is the atom. Atoms can be distinguished from each other and they are known as elements. When elements combined, they form compounds. The can either contain two or more elements. When you combined compounds of different types or classes, they form mixtures.

Do the same volumes of H2O and H2SO4 have the same number of molecules?

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no, they do not. Hope I helped! :)

The process J is called deposition. Using water is an example; write an equation that represents the process of deposition.​

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In chemistry and phase equilibria, phase transition is a common phenomenon. There are many terms related to the phase transition. The process deposition is a physical process. This process is the opposite of sublimation.

Deposition is a phase transfer or phase transition process in which a substance in the gaseous state changes directly to the solid state. Freezing of air is an example of deposition in which the water vapour directly changes to ice.

Here the gaseous state converts into solid state without being in the liquid state.

An example is:

CO₂ (g) → CO₂ (s)

To know more about phase transition, visit;

brainly.com/question/3255181

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Stoichiometry! Please note:
- Use 6.022x1023 for avogadro’s number
- Ignore sig figs and do not round the final answer.
- Keep it to 1 decimal place.

Answers

Answer:

a) 13.2 moles 2H_(2)O

b) 79.33 grams of 2H_(2)O

Explanation:

First, we'll need to balance the equation

H_(2(g)) + O_(2(g))H_(2)O_((g))

There are 2 (O) on the left and only one on the right, so we'll add a 2 coefficient to the right.

H_(2(g)) + O_(2(g))2H_(2)O_((g))

Now there are 4 (H) on the right and only 2 on the left, so we'll add a 2 coefficient to the (H_(2)) on the left.

2H_(2(g)) + O_(2(g))2H_(2)O_((g))

The equation is now balanced.

a) This can be solved with a simple mole ratio.

4.6 moles O_(2) × (2 moles H_(2)O)/(1 mole O_(2)) = 13.2 moles 2H_(2)O

b) This problem is solved the same way!

2.2 moles H_(2) × (2 moles H_(2)O)/(2 moles H_(2)) = 2.2 moles 2H_(2)O

However, this problem wants the mass of 2H_(2)O, not the moles.

The molecular weight of 2H_(2)O is the weight of 4 (H) molecules and 2 (O) molecules (found on the periodic table). So,

4(1.008) + 2(15.999) = 36.03 g/mol

2.2 moles 2H_(2)O × (36.03 g)/(1 mol) = 79.33 grams of 2H_(2)O

How is the number of neutrons and in nucleus of an atom calculated

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Explanation:

Atomic number is defined as the sum of total number of protons present in an atom. Each element has different atomic number.

Whereas mass number is the sum of total number of both protons and neutrons present in an element.

For example, an atom with mass number as 15 and has atomic number 7. Then it means it has 7 protons.

Therefore, number of neutrons present in it will be calculated as follows.

                    Mass number = no. of protons + no. of neutrons

                         15 = 7 + no. of neutrons

                    no. of neutrons = 15 - 7  

                                               = 8

Thus, we can conclude that the number of neutrons is calculated as mass number minus total number of protons present in the atom.

The number of neutrons in an atoms nucleus can be calculated by subtracting the atomic number of that atom from its mass number.

(mass number - atomic number = number of neutrons)

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g

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To get the percent yield, we will use this formula: ((Actual Yield)/(Theoretical Yield)) * 100% Values given: actual yield is 220.0 g theoretical yield is 275.6 g Now, let us substitute the values given. (220.0 grams)/(275.6 grams) = 0.7983 Then, to get the percentage, multiply the quotient by 100. 0.7983 (100) = 79.83% Among the choices, the most plausible answer is 79.8%
If the actual yield of ferrous sulfide is 220.0 g and its theoretical yield is 275.6 g, the percent yield of ferrous sulfide is 79.8%. Make a proportion. 220.0 g is x percent. 275.6 g is 100%. 220.0 g : x = 275.6 g : 100%. After crossing the products: x = 220.0 g * 100% : 275.6 g = 79.8%