What is the mass percent of sodium in NaCl?
Answers
The mass percent of sodium in NaCl can be determined by dividing the mass of sodium by the total mass of the compound (NaCl), then multiplying the result by 100. So, 39.34% of the mass of sodium in NaCl is composed of sodium.
The molecular weight of chlorine (Cl) is 35.45 g/mol while that of sodium (Na) is 22.99 g/mol.
The molecular weight of NaCl is calculated as follows:
- Na: 1 atom * 22.99 g/mol = 22.99 g/mol
- Cl: 1 atom * 35.45 g/mol = 35.45 g/mol
Total molecular weight = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
To determine the sodium mass percent in NaCl:
(mass of sodium / total mass of NaCl) * 100 to get the mass percent of sodium.
(22.99 g/mol / 58.44 g/mol) x 100 = 39.34% sodium mass percent
As a result, 39.34% of the mass of sodium in NaCl is composed of sodium.
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Therefore the percent mass of sodium in NaCl is 39.3%
I hope this helps. Let me know if anything is unclear.
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Answer:
The answer is 8.00 moles
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
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L is the Avogadro's constant which is
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From the question we have
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Answers
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Answers
Answer:
3.56L will be the obtained volume
Explanation:
0.3 M → Molarity
These are the moles of solute (for this case, the solute is KOH) that are contianed in 1L of solution
We dissolved 60 g of solute, so let's determine the moles:
60 g . 1 mol/ 56.1 g = 1.07 moles
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Answers
Answer:
35.10 g is the mass of 1.95 moles of water.
Explanation:
Moles of water = 1.95 mol
Mass of 1 mol of water = 18 g
Then the mass of 1.95 moles of water:
Mass of 1.95 mol =
35.10 g is the mass of 1.95 moles of water.
1.95 moles of H20
Required:
mass in grams
Solution:
The molar mass of water is 18.02 grams per mole
1.95 moles of water (18.02 grams / mole of water) = 35.1 grams of water