A 10.00 g sample of a compound containing only carbon, hydrogen, and oxygen forms 23.98 g CO2 and 4.91 g H2O upon complete combustion. What is the empirical formula of the compound?

Answers

Answer 1

Answer: There are three major steps for finding an empirical formula from a combustion reaction.
1.) Determine the grams of carbon and hydrogen from the given data.

C: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C
H: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H
Determine the grams of oxygen in the sample by subtracting the mass of the compound given from the total mass solved earlier.
O: 10.0 - (6.54 + 0.55) = 2.91 g O

2) Convert the values in step 1 to moles.

C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol

3) Divide each by the lowest value calculated in step 2

C: 0.54 mol / 0.18 mol = 3
H: 0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1

Thus, the empirical formula is C3H3O.

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Plants and algae that convert sunlight to food energy are called producers

primary consumers

tertiary consumers

decomposers

Answers

The correct answer is the first choice given. Plants and algaes are producers. They are called as such since they produce their own food by using the energy from the sun, CO2 and water to form glucose as their food.

1. You were tasked to check if the liquid sample you have is a substance or a mixture.Which among these tasks is the BEST way to do so?
1. Color comparison
Il. Taste comparison
III. Boiling Test
iv.
Melting Test

Answers

Answer:

boiling test or melting test

Explanation:

What is the order, from simplest to most complex, for the classification of matter

Answers

B) element, molecule, compound, mixture is the answer just took the test ;) good luck : P

Atomic energy is the energy _____. in the nucleus of an atom of electrons and their shells in chemical bonds of elements and compounds

Answers

The correct statement to fill the blank would be the first option. Atomic energy is the energy in the nucleus of an atom of electrons and their shells. From the word atomic itself, we can say that this energy is energy within and carried by the atoms.

Answer:

in the nucleus of an atom

Explanation:

The slope of a speed time indicates

Answers

The slope of a peed versus time graph indicates acceleration. You can prove this by the fact that slope is Δy/Δx and the units for y are m/s and for x are s which means that the slope has the units (m/s)/s which are the same units used for acceleration.
I hope this helps. Let me know in the comments if anything is unclear.

Which isotope will spontaneously decay and emit particles with a charge of +2?(1) 53Fe (3) 198Au
(2) 137Cs (4) 220Fr

Answers

Answer: The correct option is 4.

Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:

1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

$_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)\textrm{Y}+_2^4\alpha$

2) Beta-minus decay: It is a decay in which a beta particle is released. The beta particle released has a mass number of 0 and a charge of (-1).

$_Z^A\textrm{X}\rightarrow _(Z+1)^A\textrm{Y}+_(-1)^0\beta$

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

$_Z^A\textrm{X}\rightarrow _(Z-1)^A\textrm{Y}+_(+1)^0\beta$

For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form $_(25)^(53)\textrm{Mn}$

$_(26)^(53)\textrm{Fe}\rightarrow _(25)^(53)\textrm{Mn}+_(+1)^0\beta$

Option 2: This nuclei will undergo beta-minus decay process to form $_(80)^(198)\textrm{Hg}$

$_(79)^(198)\textrm{Au}\rightarrow _(80)^(198)\textrm{Hg}+_(-1)^0\beta$

Option 3: This nuclei will undergo a beta minus decay process to form $_(56)^(137)\textrm{Ba}$

$_(55)^(137)\textrm{Cs}\rightarrow _(56)^(137)\textrm{Ba}+_(-1)^0\beta$

Option 4: This nuclei will undergo an alpha decay process to form $_(85)^(216)\textrm{At}$

$_(87)^(220)\textrm{Fr}\rightarrow _(85)^(216)\textrm{At}+_2^4\alpha$

Hence, the correct option is 4.

It is 220Fr that would spontaneously decay and emit particles with a charge of +2.

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