MATHEMATICS COLLEGE

Convert 3,A5D Base 16 to Base 10

Answers

Answer 1

Answer:

Answer:

14941.

Step-by-step explanation:

In base 16 we have that :

A=10, B=11, C=12, D=13, E=14, F=15 and the process of change is:

3: $3*16^(0)= 3$

A5D= $10*16^(2)+5*16^(1)+13*16^(0)= 2560+80+13=2653.$

3A5D = $3*16^(3)+10*16^(2)+5*16^(1)+13*16^(0)= 12288+2560+80+13=14941.$

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You decide to play roulette 4 times, each time betting on red. What is the distribution of X, the number of times you win?

Answers

Using the concept of binomial probability, the distribution of X which is the number of winning is ;

X ______ 0 ____1 _____ 2___ 3______ 4

P(X):_0.0767_0.2762_0.3729_0.2238_0.0503

Given the parmaters :

Total Number of slots = 38
Number of reds = 18

The probability of winning,p on a single play :

p = (red slots / total slots) = 18/38 = 9/19

Number of plays = 4

Number of winnings = X

Using the binomial probability relation :

P(x = x) = nCx * p^x * q^(n-x)
q = 1 - 9/19 = 10/19
n = 4

ForX=0:

P(x = 0) = 4C0 × (9/19)^0 × (10/19)⁴ = 0.0767

ForX=1:

P(x = 0) = 4C1 × (9/19)¹ × (10/19)³ = 0.2762

ForX=2:

P(x = 2) = 4C2 × (9/19)² × (10/19)² = 0.3729

ForX=3:

P(x = 3) = 4C3 × (9/19)³ × (10/19)¹ = 0.2238

For X = 4 :

P(x = 4) = 4C4 × (9/19)⁴ × (10/19)^0 = 0.0503

Therefore, the distribution of X in the roulette spin is :

X ____ 0 ____ 1 _____ 2 ______ 3 ______ 4

P(X):_0.0767_0.2762_0.3729_0.2238 _0.0503

Learn more :brainly.com/question/12474772

1.
If betting on red, 18/38 = 9/19 chance of winning, so 10/19 chance of losing
Chance of winning 4 times: (9/19)^4 = 6561/130321 =~ 5.034%
Chance of winning 3 times: (9/19)^3 * (10/19) * C(4,1) = 29160/130321 =~ 22.3755%
Chance of winning 2 times: (9/19)^2 * (10/19)^2 * C(4,2) = 48600/130321 =~ 37.2925%
Chance of winning 1 time: (9/19) * (10/19)^3 * C(4,3) = 36000/130321 =~ 27.624%
Chance of winning 0 times: (10/39)^4 = 10000/130321 =~ 76.7336%

Jessica is playing a game where there are 4 blue markers and 6 red markers in a box. She is going to pick 3markers without replacement.
If she picks all 3 red markers, she will win a total of $500. If the first marker she picks is red but not all 3 markers
are red, she will win a total of $100. Under any other outcome, she will win $0.
What is the expected value of Jessica's winnings?
Round your answer to the nearest cent.

Answers

Answer:

The probability of Jessica picking 3 consecutive red markers is: (1/6)

The probability of Jessica's first marker being red, but not picking 3 consecutive red markers is:

(3/5)−(1/6)=(13/30)

So i am bit stuck here

what i think is it shouldn't be that complex it should be as simple as chance of Jessica's first marker being red=chance of getting red 1 time i.e P(First marker being red)=(6/10) can any explain me the probability of Jessica's first marker being red=(13/30)?

Step-by-step explanation:

Answer:

$126.67

Step-by-step explanation:

Enter your answer in the box

____

Answers

Answer:

$\boxed{2144}$

Step-by-step explanation:

The sum can be found by adding the parts:

$\sum\limits_(n=1)^(32){(4n+1)}=4\sum\limits_(n=1)^(32){n}+\sum\limits_(n=1)^(32){1}=4\cdot(32\cdot 33)/(2)+32\n\n= 2112+32=\boxed{2144}$

The sum of numbers 1 to n is n(n+1)/2.

bananas cost $0.80 a pound. in a relation, the input is the number of pounds of bananas and the output is the cost.

Answers

Yes because one input (number of pounds of banana) will always have the same output (cost).

Answer:

True. This isn't really a question but it is a statement

Step-by-step explanation:

1 pound 80 cents

2 pounds 1.60

3 pounds 2.40

and so on

A veterinarian needs to know an animal’s weight in kilograms when treating them. If 20 pounds is about 9 kilograms and a dog weighs 30 pounds determine the dog’s weight in kilograms.

Answers

1 kilo is approximately 2.2 pounds, so we can divide 30 by 2.2

Carly's dog weighs 25 pounds and her cat weighs 12 pounds how much more does her dog weigh then her cat

Answers

Answer:

13 more pounds. The dog weighs 13 more pounds than the cat.

Answer:

13 pounds

Step-by-step explanation:

21-12=13

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David has four bags of apples and two bagsof mangoes. The first four bags contain6 apples each and the bags with mangoescontain 3 mangoes each. If David and hisfriends ate 2 apples from each bag and 2mangoes from each bag, what is the totalnumber of fruits left over?