David has four bags of apples and two bagsof mangoes. The first four bags contain
6 apples each and the bags with mangoes
contain 3 mangoes each. If David and his
friends ate 2 apples from each bag and 2
mangoes from each bag, what is the total
number of fruits left over?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation: the step by step explanation is 6*4=24 so 24 apples then 3*2=6 so 6 mangoes then if 8 apples are ate then 4 mangoes are ate then (24+6)-(8+4)=30-12 so the answer is 18.

Answer 2

Answer: 18 fruits left over
6 bags in total
4 bags x 6 apples each = 24 fruits
2 bags with 3 mangoes each= 6 fruits
Total 30 fruits
Friends ate 2 fruits from each of the 6 bags
They ate 12 fruits

30-12 = 18

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There are two more assignments in your course before the semester ends, and if you get an A on at least one of them, you will get an A for the semester. Your "what-if" scenario looks like this:Event Probability

A on paper and A on presentation 0.25
A on paper only 0.10
A on presentation only 0.30
Do not get an A on either 0.35

Answer the following questions: (1 point each, except the last item, 2 points)

a. What is the probability of getting an A on the paper?
b. What is the probability of getting an A on the presentation?
c. What is the probability of getting an A in the course?
d. Are the grades on the assignments independent? Explain your answer

Answers

Answer:

Step-by-step explanation:

Hello!

Given the events:

A: "obtain an A in the paper assigment" ⇒ P(A)= 0.10

B: "obtain A in the presentation assigment" ⇒ P(B)= 0.30

Ac: "do not get an A in the paper assigment" ⇒ P(Ac)= 1 - 0.10= 0.9

Bc: "do not get an A in the presentation assigment" ⇒ P(Bc)= 1 - 0.30= 0.7

P(A∩B)= 0.25

P(Ac∩Bc)= 0.35

a. P(A)= 0.10

b. P(B)= 0.30

c. To get an A in the course you have to get an A in the paper and an A in the presentation, symbolically: P(A∩B)= 0.25

d. If the events A and B are independent, then the ocurrence of one of them doesn't affect the probability of the other ocurring, if this is so then:

P(A)= P(A/B)

$P(A/B)= (P(AnB))/(P(B)) = (0.25)/(030)= 0.83$

P(A) ≠ P(A/B) this means that "B" ocurring modifies the probability of ocurrence of A, i.e. both events are not independent.

I hope it helps!

The principal is Rs.30,000 the interest rate is 12%. Calculate the total value after 2 yearusing compound interest.

Answers

Total value=
112/100 x 112/100 x 30,000
= 37632 Rs

Answer:

37632

Step-by-step explanation:

An=A(1+12%)²

What is the quotient of 1 over (1 plus the square root of 3)?

Answers

You can rationalize the denominator by multiplying by 1 in the form of the conjugate of the denominator divided by itself.

$(1)/(1+√(3))=(1)/(1+√(3))\cdot (1-√(3))/(1-√(3))\n\n=(1-√(3))/(1^(2)-(√(3))^(2))=(1-√(3))/(1-3)\n\n=(√(3)-1)/(2)$

This eqvaluates to approximately 0.3660254037844386.

ANSWER ASAP:Shayla wants to buy some CDs that each cost $14 and a DVD that costs
$23. She has $65 that she is able to spend. Which equation can be used to
determine how many CDs Shayla could buy?

Answers

14x+23=65
65 is the total money
23 is with the dvd
14 is how many she can buy

What is the equation of the line that passes through the point (-8,5) and has a slope
of o?

Answers

Answer: y = 5

Step-by-step explanation:

If the slope is 0, the graph of the line is a horizontal line (parallel to the x-axis). 0 slope means it is flat.

Here it passes through the y-axis at +5 and passes through every value of x.

Final answer:

The equation of a line with slope 0 that passes through the point (-8,5) is y = 5.

Explanation:

The equation of a line can be found using the slope-intercept form y = mx + b, where 'm' represents the slope and 'b' is the y-intercept. The given slope of the line is 0, which means the line is horizontal with equation y = b. However, our line needs to pass through the point (-8,5), and at this point, the y coordinate is 5. Hence, for this line, b equals 5. So, the equation of the line is y = 5.

Learn more about Equation of a Line here:

brainly.com/question/33578579

#SPJ3

The only swimming pool at the El Cheapo Motel is outdoors. It is 5.0 m wide and 12.0 m long. If the weekly evaporation is 2.35 in., how many gallons of water must be added to the pool if it does not rain?

Answers

Answer:

946.10 gallons per week

Step-by-step explanation:

1 cm = 0.393701 inch

Width = 5.0m = 196.85 inch

Length = 12.0 m = 472.44 inch

The volume evaporated weekly is given by:

$V = L*W*2.35 = 196.85*472.33*2.35\nV=218,550.12\ in^3$

Converting to gallons:

$1\ gal = 231\ in^3\nV=(218,550.12)/(231)\nV= 946.10\ gal$

946.10 gallons of water must be added to the pool each week.

Final answer:

To determine the volume of water evaporated from the pool at the El Cheapo Motel, we converted all measurements to a common unit and calculated the volume of water evaporated. The motel has to add approximately 946.13 gallons of water weekly, considering there is no rain.

Explanation:

To answer this question, we first need to convert the measurements to a common unit. Given that the pool is 5.0 m wide and 12.0 m long (a total area of 60.0 m2) and the weekly evaporation is 2.35 inches, we first convert the inches to meters. Since 1 inch is equal to 0.0254 meters, 2.35 inches equals 0.05969 meters.

Then, we calculate the volume of water evaporated in a week, which is calculated by multiplying the surface area of the pool by the depth of the water evaporated. Hence, it's 60.0 m2 * 0.05969 m = 3.58 m3. As 1 m3 is approximately 264.17 gallons, 3.58 m3 equals 946.1296 gallons approximately.

In conclusion, the El Cheapo Motel needs to add around 946.13 gallons of water to their pool on a weekly basis, if there is no rain.