PHYSICS HIGH SCHOOL

Two cylindrical resistors are made from same material and have the same length. When connected across the same battery, one dissipates twice as much power as the other. How do their diameters compare ?

Answers

Answer 1

Answer:

Answer:

$(d_2)/(d_1) = \sqrt2 = 1.41$

Explanation:

As resistor is connected to the battery of constant EMF then the power across the resistor is given as

$P = (E^2)/(R)$

now if two resistors are made up of same material and of same length then due to different cross sectional area they both have different resistance

Due to different resistance they both will have different power

Since power is inversely depends on the resistance

So if the power is twice that of the other then the resistance must be half

so we have

$R_1 = \rho (L)/(A_1)$

$R_2 = \rho(L)/(A_2)$

since one resistance is half that of other resistance

So the area of one must be twice that of other

so we have

$(A_2)/(A_1) = 2$

$(\pi d_2^2)/(\pi d_1^2) = 2$

$d_2 = 1.41 d_1$

Answer: is

mass by volume

Explanation:

same quiz

A car maintains a constant velocity of 100 km/hr for 10 seconds. During this interval its acceleration is A) zero.
B) 10 km/hr.
C) 110 km/hr.
D) 1000 km/hr.

Answers

A.) acceleration is to increase or decrease in speed the only time your not accelerating is when your not moving or your going a constant speed

Glare appears on a computer screen when light from the surroundings reflects off of the screen’s surface. Some computer screens have a special coating to reduce glare.Which best explains how the coating works?

A:The coating absorbs light that shines on it and prevents the light from reflecting

B:The surface of the coating is rough, so light that shines on it gets scattered in many directions.

C:The coating bends light that passes through it and prevents the light from reaching the user’s eyes

D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.

Answers

Answer:

The correct answer is D.

D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.

Explanation:

Glare is produced on a computer screen when light from some external source reflects on the screen.

Anti-glare coating do not absorb light to reduce glare but they actually reduce glare by encouraging the light from the room to pass through the screen so that less light is reflected. Polarized lenses absorbs light to reduce glare, not anti-glare coating.

Answer: d

Explanation:

The inner planets are relatively small bodies composed mostly of rock and metals. Why did they develop this way instead of becoming gas giants like the outer planets?

Answers

The temperature of the early solar system explains why the inner planets are rocky and the outer ones are gaseous. As the gases coalesced to form a protosun, the temperature in the solar system rose. In the inner solar system temperatures were as high as 2000 K, while in the outer solar system it was as cool as 50 K. In the inner solar system, only substances with very high melting points would have remained solid. All the rest would have vaoprized. So the inner solar system objects are made of iron, silicon, magnesium, sulfer, aluminum, calcium and nickel. Many of these were present in compounds with oxygen. There were relatively few elements of any other kind in a solid state to form the inner planets. The inner planets are much smaller than the outer planets and because of this have relatively low gravity and were not able to attract large amounts of gas to their atmospheres. In the outer regions of the solar system where it was cooler, other elements like water and methane did not vaporize and were able to form the giant planets. These planets were more massive than the inner planets and were able to attract large amounts of hydrogen and helium, which is why they are composed mainly of hydrogen and helium, the most abundant elements in the solar system, and in the universe

https://lco.global/spacebook/planets-and-how-they-formed/

hope it helps

Please help me A person launches a home-built model rocket straight upinto the air at y = 0 from rest at time t = 0 . (The positive y-direction is upwards). The fuel burns out at t = t0. The position of the rocket is given by

with a0 and g are positive. Find the y-components of the velocity and acceleration of the rocket as a function of time. Graph ay vs t for 0 < t < t0.

Answers

-- We know that the y-component of acceleration is the derivative of the
y-component of velocity.

-- We know that the y-component of velocity is the derivative of the
y-component of position.

-- We're given the y-component of position as a function of time.

So, finding the velocity and acceleration is simply a matter of differentiating
the position function ... twice.

Now, the position function may look big and ugly in the picture. But with the
exception of 't' , everything else in the formula is constants, so we don't even
need any fancy processes of differentiation. The toughest part of this is going
to be trying to write it out, given the text-formatting capabilities of the wonderful
envelope-pushing website we're working on here.

From the picture . . . . . y (t) = (1/2) (a₀ - g) t² - (a₀ / 30t₀⁴ ) t⁶

First derivative . . . y' (t) = (a₀ - g) t - 6 (a₀ / 30t₀⁴ ) t⁵ = (a₀ - g) t - (a₀ / 5t₀⁴ ) t⁵

There's your velocity . . . /\ .

Second derivative . . . y'' (t) = (a₀ - g) - 5 (a₀ / 5t₀⁴ ) t⁴ = (a₀ - g) - (a₀ /t₀⁴ ) t⁴

and there's your acceleration . . . /\ .
That's the one you're supposed to graph.

a₀ is the acceleration due to the model rocket engine thrust
combined with the mass of the model rocket
'g' is the acceleration of gravity ... 9.8 m/s² or 32.2 ft/sec²
t₀ is how long the model rocket engine burns

Pick, or look up, some reasonable figures for a₀ and t₀
and you're in business.

The big name in model rocketry is Estes. Their website will give you
all the real numbers for thrust and burn-time of their engines, if you
want to follow it that far.

A 250 gram ball at the end of a string is revolving uniformly in a circle of radius 0.75 meters.The ball makes 2.0 revolutions per second. What is the centripetal acceleration?

Answers

The centripetal acceleration of the ball would be 88.44 m/ $s^2$ .

Centripetal acceleration

The centripetal acceleration (ac) of an object moving in a circle at a constant speed is given by the formula:

ac = (v^2) / r

where v is the speed of the object and r is the radius of the circle.

In this case, the ball is revolving uniformly in a circle of radius 0.75 meters, and it makes 2.0 revolutions per second. To find the speed of the ball (v), we need to convert the number of revolutions per second to the angular velocity (ω) in radians per second:

ω = 2π x (number of revolutions per second)

ω = 2π x 2.0 = 4π radians per second

The speed of the ball (v) is then given by:

v = ω x r
v = (4π rad/s) x 0.75 m = 3π m/s

Now we can calculate the centripetal acceleration (ac) of the ball:

ac = (v^2) / r
ac = [(3π m/s)^2] / 0.75 m
ac = 9π^2 m/s^2 ≈ 88.44 m/s^2

Therefore, the centripetal acceleration of the ball is approximately 88.44 m/s^2.

More on centripetal acceleration can be found here: brainly.com/question/1052267

#SPJ1

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20 miles per hour north is an example of ______A) acceleration B) velocity C) deceleration D) speed

An unbalanced force of 25 N, E, is applied to a 12-kg mass. What is the acceleration given to the mass?

Two cylindrical resistors are made from same material and have the same length. When connected across the same battery, one dissipates twice as much power as the other. How do their diameters compare ?

Answers

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Answer: is

mass by volume

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Centripetal acceleration