PHYSICS COLLEGE

An ac source of period T and maximum voltage V is connected to a single unknown ideal element that is either a resistor, and inductor, or a capacitor. At time t = 0 the voltage is zero. At time t = T/4 the current in the unknown element is equal to zero, and at time t = T/2 the current is I = -Imax, where Imax is the current amplitude. What is the unknown element?

Answers

Answer 1

Answer:

Answer:

This satisfy the above given condition so we can say that this capacitor.

Explanation:

Let's take one by one option and check whether is wrong or right

For inductor:

$I=I_osin(wt-(\pi )/(2))$

Given that at t=T/4 ,I=0 and we know that

$w=(2\pi )/(T)$

So at T/4

$I=I_osin((2\pi )/(T)* (T)/(4)-(\pi )/(2))$

I=0 A

At t=T/2

$I=I_osin((2\pi )/(T)* (T)/(2)-(\pi )/(2))$

$I=I_o$

It means that this not a indutor.

For capacitor:

$I=I_osin(wt+(\pi )/(2))$

At T/4, I=0

At t=T/2

$I=I_osin((2\pi )/(T)* (T)/(2)+(\pi )/(2))$

$I= -I_o$

This satisfy the above given condition so we can say that this capacitor.

Answer 2

Answer:

Final answer:

The nature of the unknown ideal element in the given AC circuit can be determined based on the phase difference between the current and voltage. In this case, since the current is zero at T/4 and a maximum at T/2, it suggests the current is lagging the voltage, indicating that the element in the circuit is a capacitor.

Explanation:

The question relates to an alternating current (AC) circuit connected to an unknown ideal element, and from the given conditions, it appears this element is a capacitor. Let us understand why.

Firstly, in an AC circuit, we can determine the nature of the circuit elements—resistor, inductor, or capacitor—based on the phase difference between the current and voltage. In a resistor, the current and voltage are in phase. In an inductor, the current lags behind the voltage by 90 degrees (or π/2 radians), whereas in a capacitor, the current leads the voltage by 90 degrees (or π/2 radians).

Based on the given problem, at time t = T/4, the current is zero. Considering that in one period of the AC voltage, it starts from zero, reaches a maximum, comes back to zero (at T/2), goes to a minimum (at 3T/4), and returns back to zero (at T), the current would reach its peak either at T/4 (if it's leading, a capacitor) or at 3T/4 (if it's lagging, an inductor). Here, since the current is zero at T/4 and it is a maximum at T/2 (albeit negative), it suggests the current is lagging the voltage, and hence, it suggests the element in the circuit is a capacitor.

Learn more about AC Circuits here:

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Answers

Final answer:

The forces directly acting on the ball hanging from a rear-view mirror while a car drives in a circle are tension, gravity, and the centripetal force.

Explanation:

The correct answer is c. tension, gravity, and the centripetal force.

When the car is driving in a circle, the ball experiences both tension and gravity. The tension in the string is what keeps the ball from falling, while gravity pulls the ball downward.

In addition to tension and gravity, the ball also experiences the centripetal force. This force is directed towards the center of the circular motion and keeps the ball moving in a circular path.

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Nina and Jon are practicing an ice skating routine. Nina is standing still. Jon, who is twice as heavy as Nina, skates toward her, pushing Nina away with force f. Assuming the system is closed, which statement is correct about this system? a. Nina experiences a force equal to f/2. b. Nina experiences a force equal to f^2. c. Nina experiences a force equal to 2f. d. Nina experiences a force equal to f.

Answers

Answer:

Explanation:

• Nina experiences a force equal to f.

Answer:

Nina experiences a force equal to f

Explanation:

got to get that 2nd answer slot correct too before an abusive expert verifier with an alt comes in and purposely verifies the wrong answer

What happens at night- describing air circulation

Answers

Answer:

The environment is warmed by the light throughout the day, such that the temperature increases. The weather is decreasing and the temperature decreases in the night as the sun falls. There was a misunderstanding. Thanks to the density, the atmosphere becomes densest on the earth. The air becomes colder and colder when you move up.

Explanation:

Answer is above

Hope this helps.

Starting from rest, a basketball rolls from the top to the bottom of a hill, reaching a translational speed of 6.1 m/s. Ignore frictional losses. (a) What is the height of the hill? (b) Released from rest at the same height, a can of frozen juice rolls to the bottom of the same hill. What is the translational speed of the frozen juice can when it reaches the bottom?

Answers

Answer:

a) h=3.16 m, b) v_{cm }^ = 6.43 m / s

Explanation:

a) For this exercise we can use the conservation of mechanical energy

Starting point. Highest on the hill

Em₀ = U = mg h

final point. Lowest point

$Em_(f)$ = K

Scientific energy has two parts, one of translation of center of mass (center of the sphere) and one of stationery, the sphere

K = ½ m $v_(cm )^(2)$ + ½ $I_(cm)$ w²

angular and linear speed are related

v = w r

w = v / r

K = ½ m v_{cm }^{2} + ½ I_{cm} v_{cm }^{2} / r²

Em_{f} = ½ v_{cm }^{2} (m + I_{cm} / r2)

as there are no friction losses, mechanical energy is conserved

Em₀ = Em_{f}

mg h = ½ v_{cm }^{2} (m + I_{cm} / r²) (1)

h = ½ v_{cm }^{2} / g (1 + I_{cm} / mr²)

for the moment of inertia of a basketball we can approximate it to a spherical shell

I_{cm} = ⅔ m r²

we substitute

h = ½ v_{cm }^{2} / g (1 + ⅔ mr² / mr²)

h = ½ v_{cm }^{2}/g 5/3

h = 5/6 v_{cm }^{2} / g

let's calculate

h = 5/6 6.1 2 / 9.8

h = 3.16 m

b) this part of the exercise we solve the speed of equation 1

v_{cm }^{2} = 2m gh / (1 + I_{cm} / r²)

in this case the object is a frozen juice container, which we can simulate a solid cylinder with moment of inertia

I_{cm} = ½ m r²

we substitute

v_{cm } = √ [2gh / (1 + ½)]

v_{cm } = √(4/3 gh)

let's calculate

v_{cm } = √ (4/3 9.8 3.16)

v_{cm }^ = 6.43 m / s

A uniform, 4.5 kg, square, solid wooden gate 2.0 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. A 1.2 kg raven flying horizontally at 4.5 m/s flies into this door at its center and bounces back at 1.5 m/s in the opposite direction. What is the angular speed of the gate just after it is struck by the unfortunate raven?

Answers

Answer:

Explanation:

Mass of the gate, $m_1 = 4.5 kg$

Mass of the raven, $m_2 = 1.2 kg$

Initial speed of raven, $v_1 = 4.5 m/s$

Final speed of raven, $v_2 = - 1.5 m/s$

Moment of Inertia of the gate about the axis passing through one end:

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Angular momentum of the gate, $L = I \omega$

$L = 5.33 \omega$

Using the law of conservation of angular momentum:

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in the demolition of an old building,a 1,300 kg wrenching ball hits the building at 1.07m/s^2.Calculate the amount of force at which the wrecking ball strikes the building

Answers

Answer:

1391 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1300 × 1.07

We have the final answer as

1391 N

Hope this helps you

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