PHYSICS COLLEGE

PLEASE HELP DUE BEFORE 11:30 TODAY!!!!Which of the following quantities is NOT a vector quantity?
A. 926 m to the north
B. 5.2 m/s to the west
C. 46 m down
D. 12.3 m/s faster

Answers

Answer 1
Answer:

Answer:

D is not the a vector quantities

Related Questions

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According to the U.S. Green Building Council, what percentage of the world’s energy use and greenhouse gas emissions can be attributed to buildings?

Answers

According to the US green building council, the US building account for 39% of world primary energy consumption . Electricity has approximately 78% of total building energy consumption and also contributes to GHG emissions

Answer:

40%

Explanation: United States Green Building Council is a body aimed at ensuring reduced green house gas emissions from activities taking place in building. they carry out surveys, carry out enlightenment activities and release the reports of and trending green house emission issues all these are to guarantee safe and healthy living for all. A total of 40% of Green house emissions are from buildings from the construction stage to it usage.

How can socialism
impact populations?

Answers

Answer:

it represents a fundamental difference. (more info below)

Explanation:

Production is incessantly developing and expanding in socialist countries, and employment is guaranteed for the entire productive population. Consequently, the relative overpopulation problem has been eliminated. This represents the fundamental difference between socialism's demographic law and capitalism's law.

hope this helped!
It represents a fundamental difference by gaining friends and losing friends or gaining jobs and losing jobs etc

A bicycle wheel of radius 0.70 m is rolling without slipping on a horizontal surface with an angular speed of 2.0 rev/s when the cyclist begins to uniformly apply the brakes. the bicycle stops in 5.0 s. how far did the bicycle travel during the 5.0 seconds of braking?

Answers

Distance traveled by the bicycle during the 5 seconds of braking is 22m

Explanation:

initial angular velocity= 2 rev/s

final angular velocity= 0 rev/s

Angular displacement Ф=((wi+wf)/(2) )t

Ф=((0+2)/(2) )5=5 rev

so the distance travelled= 5(2πr)

distance=5(2π*0.7)

distance=22m

The bicycle traveled about 22 m during the 5.0 seconds of braking

\texttt{ }

Further explanation

Centripetal Acceleration can be formulated as follows:

\large {\boxed {a = \frac{ v^2 } { R } }

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

\texttt{ }

Centripetal Force can be formulated as follows:

\large {\boxed {F = m \frac{ v^2 } { R } }

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

\texttt{ }

Given:

radius of wheel = R = 0.70 m

initial angular speed = ω = 2.0 rev/s = 4π rad/s

final angular speed = ωo = 0 rad/s

time taken = t = 5.0 s

Asked:

distance covered = d = ?

Solution:

d = \theta R

d = (\omega + \omega_o)(1)/(2)t R

d = ( 4 \pi + 0 ) (1)/(2)(5.0)( 0.70 )

d = 4\pi (1.75)

d = 7\pi \texttt{ m}

d \approx 22 \texttt{ m}

\texttt{ }

Learn more

\texttt{ }

Answer details

Grade: High School

Subject: Physics

Chapter: Circular Motion

What is the pH of a solution with a hydrogen ion concentration of 2.0x10^3.(Use 3 digits)

Answers

Answer:

2.70

Explanation:

pH = -log[H+]

pH = -log[2.0x10^-3]

pH = 2.70

If you have two objects of the same mass colliding at the same speed but opposite directions, what situation will happen in an inelastic collision? a. The objects will collide and bounce back with the same initial velocity.
b. The objects will collide and bounce back with a larger velocity.
c. The objects will collide and stay stationary.
d. The objects will collide and move forward in one direction.

Answers

c. The objects will collide and stay stationary.

A battery with an emf of 12.0 V shows a terminal voltage of 11.7 V when operating in a circuit with two lightbulbs, each rated at 4.0 W (at 12.0 V), which are connected in parallel.What is the battery's internal resistance?

Answers

Answer:

0.46Ω

Explanation:

The electromotive force (E) in the circuit is related to the terminal voltage(V), of the circuit and the internal resistance (r) of the battery as follows;

E = V + Ir                      --------------------(a)

Where;

I = current flowing through the circuit

But;

V = I x Rₓ                    ---------------------(b)

Where;

Rₓ = effective or total resistance in the circuit.

First, let's calculate the effective resistance in the circuit:

The effective resistance (Rₓ) in the circuit is the one due to the resistances in the two lightbulbs.

Let;

R₁ = resistance in the first bulb

R₂ = resistance in the second bulb

Since the two bulbs are both rated at 4.0W ( at 12.0V), their resistance values (R₁ and R₂) are the same and will be given by the power formula;

P = (V^(2) )/(R)

=> R = (V^(2) )/(P)             -------------------(ii)

Where;

P = Power of the bulb

V = voltage across the bulb

R = resistance of the bulb

To get R₁, equation (ii) can be written as;

R₁ = (V^(2) )/(P)    --------------------------------(iii)

Where;

V = 12.0V

P = 4.0W

Substitute these values into equation (iii) as follows;

R₁ = (12.0^(2) )/(4)

R₁ = (144)/(4)

R₁ = 36Ω

Following the same approach, to get R₂, equation (ii) can be written as;

R₂ = (V^(2) )/(P)    --------------------------------(iv)

Where;

V = 12.0V

P = 4.0W

Substitute these values into equation (iv) as follows;

R₂ = (12.0^(2) )/(4)

R₂ = (144)/(4)

R₂ = 36Ω

Now, since the bulbs are connected in parallel, the effective resistance (Rₓ) is given by;

(1)/(R_(X) ) = (1)/(R_1) + (1)/(R_2)       -----------------(v)

Substitute the values of R₁ and R₂ into equation (v) as follows;

(1)/(R_X) = (1)/(36) + (1)/(36)

(1)/(R_X) = (2)/(36)

Rₓ = (36)/(2)

Rₓ = 18Ω

The effective resistance (Rₓ) is therefore, 18Ω

Now calculate the current I, flowing in the circuit:

Substitute the values of V = 11.7V and Rₓ = 18Ω into equation (b) as follows;

11.7 = I x 18

I = (11.7)/(18)

I = 0.65A

Now calculate the battery's internal resistance:

Substitute the values of E = 12.0, V = 11.7V and I = 0.65A  into equation (a) as follows;

12.0 = 11.7 + 0.65r

0.65r = 12.0 - 11.7

0.65r = 0.3

r = (0.3)/(0.65)

r = 0.46Ω

Therefore, the internal resistance of the battery is 0.46Ω

Answer:

R_i_n_t=0.45 \Omega

Explanation:

Internal resistance is a concept that helps model the electrical consequences of the complex chemical reactions that occur within a battery. When a charge is applied to a battery, the internal resistance can be calculated using the following equation:

R_i_n_t=((V_N_L)/(V_F_L) -1)R_L

Where:

V_F_L=Load\hspace{3}voltage=11.7V\nV_N_L= O pen\hspace{3}circuit\hspace{3}voltage=12V\nR_L=Load\hspace{3}resistance

As you can see, we don't know the exactly value of the R_L. However we can calculated that value using the next simple operations:

The problem tell us that the power of each lightbulb is 4.0 W at 12.0 V, hence let's calculated the power at 11.7V using Cross-multiplication:

(12)/(11.7) =(4)/(P)

Solving for P :

P=(11.7*4)/(12) =3.9W

Now, the electric power is given by:

P=(V^2)/(R_b)

Where:

R_b=Resistance\hspace{3}of\hspace{3}each\hspace{3}lightbulb

So:

R_b=(V^2)/(P) =(11.7^2)/(3.9) =35.1\Omega

Now, because of the lightbulbs are connected in parallel the equivalent resistance is given by:

(1)/(R_L) =(1)/(R_b) +(1)/(R_b) =(2)/(R_b) \n\n R_L= (R_b)/(2) =(35.1)/(2)=17.55\Omega

Finally, now we have all the data, let's replace it into the internal resistance equation:

R_i_n_t=((12)/(11.7) -1)17.55=0.45\Omega
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