A 1200-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 35 mC/s at some instant in time. (A) What will be the magnitude of the induced magnetic field 10.0 cm radially outward from the center of the plates?

Answers

Answer 1
Answer:

Answer:

B = 7 * 10^(-8) T

Explanation:

As we know that charge on the plates of capacitor is changing at rate given as

i = (dq)/(dt) = 35 mC/s

now this rate of charging the plates will give the displacement current in the region between the plates

Now by Ampere's law we can say

\int B . dl = \mu_0 i

now we have

B(2\pi r) = \mu_0 i

B = (\mu_0 i)/(2\pi r)

B = (2 * 10^(-7) (35 * 10^(-3)))/(0.10)

B = 7 * 10^(-8) T


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Answers

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Answers

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A spring gun consists of a spring inside a plastic tube with spring constant, k. The spring can be compressed 20 cm from its equilibrium length. A 100 g hard plastic ball is then loaded into the tube. If the ball is shot directly up and reaches a height of 2 m above the top of the tube, what is the spring constant, k? Ignore air resistance.A) 98 N/m
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Answers

Answer: The spring constant is K=392.4N/m

Explanation:

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Answers

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Answers

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Answers

Answer:

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Explanation:

brainliest please? :))