The body of a person who weighs 50 kilograms contains around 2 × 10^2 grams of sodium chloride. How much sodium chloride is contained in the bodies of 1.8 × 10^3 people who each weigh 50 kilograms? Represent the answer in scientific notation.

Answers

Answer 1
Answer: we can solve this problem by the rule of three.
1 person------------------2*10² g of sodium chloride.
1.8*10³ people----------      x

x=(1.8*10³ people  *   2*10² gr of sodium chloride) / 1 person=3.6*10⁵ g of sodium chloride.

answer: 3.6*10⁵ g of sodium chloride. 
Answer 2
Answer:

Answer:

Answer: 3.6*10⁵ g of sodium chloride.

Step-by-step explanation:

I took a Edmentum/plato test


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What are the values of a, b, and c in the quadratic equation –2x^2 + 4x – 3 = 0?a = 2, b = 4, c = 3 a = 2, b = 4, c = –3 a = –2, b = 4, c = 3 a = –2, b = 4, c = – 3
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Which is true about the polynomial ?It is a binomial with a degree of 2. It is a binomial with a degree of 3. It is a trinomial with a degree of 2. It is a trinomial with a degree of 3.

Which is greater -6 or -3

Answers

-3 is greater than -6

How do I do x/3-x/9=6 Pls solve with steps

Answers

Answer:

27

Step-by-step explanation:

Hello,

do you agree that

(1)/(3)-(1)/(9)=(3-1)/(9)=(2)/(9)    ?

Then,

we can simplify as below and multiply by 9 both sides and divide by 2

(x)/(3)-(x)/(9)=(2x)/(9)=6\n\n<=> 2x = 54\n\n<=> x = 54/2= 27

Thanks

A race car moving along a circular track has a centripetal acceleration of 12 m/s. Ifthe distance between the car and the center of the track is 40 m, what is the speed
of the car?

Answers

Answer:

The speed of the car is 21.91 m/s

Step-by-step explanation:

Centripetal Acceleration

It's the acceleration experienced by an object in a uniform circular motion.

It always points toward the center of rotation and is perpendicular to the linear velocity v.

The magnitude of the centripetal acceleration is:

\displaystyle a_c=(v^2)/(r)

Where r is the radius of rotation.

The race car has a centripetal acceleration of a_c=12 m/s^2 and the radius of rotation is r=40 m.

We can calculate the speed of the car by solving the above equation for v:

v=√(a_c\cdot r)

v=√(12\cdot 40)

v=√(480)

v=21.91\ m/s

The speed of the car is 21.91 m/s

The center of a great circle is also the center of a small circle. true or false

Answers

100% true!!!!!!!!!!!!!!!

Las fracciones que tienen denominador 10, 100, 1000, etc las llamamos fracciones decimales y a su vez las podemos escribir como nummeros decimales 1) encierro las fracciones decimales con color 21/10; 43/8 ;31/12 ;439/100 ;34/10 ;84/7 , 35/1000 ;28/15 ;851/1000

Answers

Answer:

las fracciones decimales son:

21/10 = 2,1

439/100 = 4,39

34/10 = 3,4

35/1000 = 0,035

851 / 1000 = 0,851

Step-by-step explanation:

Toda fraccion cuyo denominador (el numero de abajo) es multiplo de 10 es considerada una fraccion decimal. No importa si el numerador es mayor al denominador. Justamente el sistema decimal fue concebido para facilitar la multiplicacion y division de los numeros por algun multiplo de 10.

Solving equations 4x-2=18

Answers

4x - 2 = 18

4x = 20

x = 5

Nice days.......
thats easy its x = 5 , 4 times 5 is 20 minus 2 equals 18 

have a nice day