Indicate the number of protons, neutrons, and electrons in each of the following species: 15N7, 33S16, 63Cu29, 84Sr38, 130Ba56, 186W74, 202Hg80

Answers

Answer 1

Answer:

The number of protons neutrons, and electrons in each of the following species given are below;

What is the atomic number?

The total number of protons present in an atom is known as the atomic number of that atom. The atomic number has no correlation either with the number of neutrons or the number of electrons present inside an atom.

15N7 ⇒ 7 electrons, 8 neutrons, 7 protons

33S16 ⇒ 16 protons, 16 electrons, 17 neutrons

63Cu29 ⇒ 29 electrons, 34 neutrons,29 protons

84Sr38 ⇒ 38 electrons, 46 neutrons,38 protons

130Ba56 ⇒ 56 electrons, 74 neutrons,56 protons

186W74⇒ 74 electrons, 112 neutrons,74 protons

202Hg80 ⇒ 80 electrons, 122 neutrons ,80 protons

To learn more about the atomic number from here, refer to the link ;

brainly.com/question/14190064

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Answer 2

Answer:

Answer:

1. 7 protons, 7 electrons, 8 neutrons

2. 16 protons, 16 electrons, 17 neutrons

3. 29 protons, 29 electrons, 34 neutrons

4. 38 protons, 38 electrons, 46 neutrons

5. 56 protons, 56 electrons, 74 neutrons

6. 74 protons, 74 electrons, 112 neutrons

7. 80 protons, 80 electrons, 122 neutrons

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A gas occupies a volume of 30.0L, a temperature of 25°C and a pressure of 0.600atm. What will be the volume of the gas at STP?

Answers

Answer:

=16.49 L

Explanation:

Using the equation

P1= 0.6atm V1= 30L, T1= 25+273= 298K, P2= 1atm, V2=? T2= 273

P1V1/T1= P2V2/T2

0.6×30/298= 1×V2/273

V2=16.49L

9. The first step in industrial nitric acid production is the catalyzed oxidation of ammonia. Without a catalyst, a different reaction predominates: 4NH3(g) + 3O2(g) ⇔ 2N2(g) + 6H2O(g) When 0.0120 mol gaseous NH3 and 0.0170 mol gaseous O2 are placed in a 1.00 L container at a certain temperature, the N2 concentration at equilibrium is 2.20×10-3 M. Calculate Keq for the reaction at this temperature.

Answers

Answer: The value of $K_(eq)$ is $4.66* 10^(-5)$

Explanation:

We are given:

Initial moles of ammonia = 0.0120 moles

Initial moles of oxygen gas = 0.0170 moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of ammonia = $(0.0120)/(1.00)=0.0120M$

Concentration of oxygen gas = $(0.0170)/(1.00)=0.0170M$

The given chemical equation follows:

$4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)$

Initial: 0.0120 0.0170

At eqllm: 0.0120-4x 0.0170-3x 2x 6x

We are given:

Equilibrium concentration of nitrogen gas = $2.20* 10^(-3)M=0.00220M$

Evaluating the value of 'x', we get:

$\Rightarrow 2x=0.00220\n\n\Rightarrow x=(0.00220)/(2)=0.00110M$

Now, equilibrium concentration of ammonia = $0.0120-4x=[0.0120-(4* 0.00110)]=0.00760M$

Equilibrium concentration of oxygen gas = $0.0170-3x=[0.0170-(3* 0.00110)]=0.0137M$

Equilibrium concentration of water = $6x=[6* 0.00110]=0.00660M$

The expression of $K_(eq)$ for the above reaction follows:

$K_(eq)=([N_2]^2* [H_2O]^6)/([NH_3]^4* [O_2]^3)$

Putting values in above expression, we get:

$K_(eq)=((0.00220)^2* (0.00660)^6)/((0.00760)^4* (0.0137)^3)\n\nK_(eq)=4.66* 10^(-5)$

Hence, the value of $K_(eq)$ is $4.66* 10^(-5)$

A gas has a volume of 300 mL and a pressure of 2 atm. What volume will the gas occupy when the pressure isincreased to 7 atm (total)?

Answers

Answer:

The answer is 85.71 mL

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

$V_2 = (P_1V_1)/(P_2) \n$

We have

$V_2 = (300 * 2)/(7) = (600)/(7) \n = 85.714285...$

We have the final answer as

85.71 mL

Hope this helps you

What is the purpose of a catalyst?O A. To change the potential energy of the reactants
O B. To lower the activation energy of a reaction
O C. To increase the kinetic energy of the reactants
O D. To shift the equilibrium position of a reaction

Answers

B. To lower the activation energy of a reaction

Answer:

To lower the activation energy of a reaction

Explanation:

i just took the test and got it right ...... i hope this helps :)

When palmitoleic acid reacts with hydrogen to form a saturated fatty acid, indicate the stoichiometry of the reaction and the product that is formed. If the stoichiometry of H2 or the product is not integral, enter a fraction (i.e. 3/2)

Answers

Answer:

Stoichiometric coefficient of hydrogen gas is 1.

Stoichiometric coefficient of palmitic acid is 1.

Explanation:

Addition of hydrogen to double bond is termed as hydrogenation reaction.

$C_(16)H_(30)O_2+H_2\rightarrow C_(16)H_(32)O_2$

According to stoichiometry, 1 mole of palmitoleic acid reacts with 1 mole of hydrogen gas to give 1 mole of palmitic acid.

Stoichiometric coefficient of hydrogen gas is 1.

Stoichiometric coefficient of palmitic acid is 1.

Assuming binding is fast relative to subsequent catalytic steps, what relative effect does substitute the various active site residues have on catalysis versus substrate-binding? The various substitutions affecta. substrate-binding more than catalytic turnover.
b. catalytic turnover more than substrate binding.
c. substrate binding, but not catalytic turnover.
d. catalytic turnover, but not substrate binding.

Answers

Answer:

Explanation:

The various substitutions affect catalytic turnover more than substrate binding.

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