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PLEASEEEEEEEE ASAPPPPPWhat is the density of a piece of cardboard that has a mass of 250 g and volume of 46 mL? *

Answers

Answer 1

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Answer 2

Answer:

Answer:

5.4347826087

Explanation:

The formula for density is Mass/Volume so you would do 250/46 to get the answer of 5.4347826087 grams per milliliter

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Refer to the following balance equation : 2c2h6 + 7o2 = 4co2 + 6 h20. How many moles of c2h6 will combust completely with 2.0 moles of oxygen gas. How many grams of water will be produced when 30.0 g of c2h6 reacts completely with oxygen?
In the following structure, carbons (I),(2),(3) and (4) are classified respectively as
A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base (B) solution. Show all your work.pKb for the weak base = 4.82.Molar mass of the weak base = 82.0343g/mole.Note: pKa = -logKapKb = -logKbpH + pOH = 14[H+ ] [OH- ] = 10^-14
A structural model of retinol is shown below. How many carbon atoms are inretinol?А. 14В. 28С. 20D. 5
In general, atomic radii: A. decrease down a group and remain constant across a period. B. decrease down a group and increase across a period. C. increase down a group and increase across a period. D. increase down a group and remain constant across a period. E. increase down a group and decrease across a period.

Predict the product when 2-methylbutanol is oxidised with pyridium chlorochromate in dichloromethane (PCC/CH2C12) a. CH3CH2CH(CH3)COOH b. CH3CH2CH2CH(CH3)CHO C. CH3CH2CH(CH3)CHO d. CH3CH2CH(CH3)OH 8:40 PM Type a message

Answers

Answer:

c. CH3CH2CH(CH3)CHO

Explanation:

Hello there!

In this case, according to the process for the one-step oxidation of a primary alcohol with a moderately strong oxidizing agent like pyridinium chlorochromate (PCC), whereby an aldehyde is produced, we infer that the corresponding product will be 2-methylbutanal, which matches with the choice c. CH3CH2CH(CH3)CHO according to the following reaction:

$CH_3CH_2CH(CH_3)CH_2OH\rightarrow CH_3CH_2CH(CH_3)COH$

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Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium chloride and an excess of sodium phosphate, how much calcium phosphate can you make?

Answers

Answer:- 353.3 g

Solution:- The balanced equation is:

$2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2$

We start with given grams of calcium chloride and convert them to moles. Then using mol ratio, the moles of calcium phosphate are calculated and converted to grams as.

Molar mass of calcium chloride is 110.98 gram per mol and molar mass of calcium phosphate is 310 gram per mol.

The set is made using dimensional analysis as:

$379.4gCaCl_2((1molCaCl_2)/(110.98gCaCl_2))((1molCa_3(PO_4)_2)/(3molCaCl_2))((310gCa_3(PO_4)_2)/(1molCa_3(PO_4)_2))$

= $353.3gCa_3(PO_4)_2$

So, 353.3 grams of calcium phosphate can be formed.

Answer:

353.3g

Explanation:

Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0.6160959 kg, 3.225 mg, and 5480.7 g. The total mass of the samples should be reported as?

Answers

Answer:

6.1 kg

Explanation:

To obtain the total mass of the sample, we must first express each mass of the sample in the same unit of measurement.

Since the SI unit of mass is kilogram (kg), we shall express the total mass of the samples in kilogram (kg).

This is illustrated below:

Mass of the samples are:

M1 = 0.6160959 kg

M2 = 3.225 mg

M3 = 5480.7 g.

Conversion of 3.225 mg to kg

1 mg = 1×10¯⁶ kg

Therefore,

3.225 mg = 3.225 × 1×10¯⁶

3.225 mg = 3.225×10¯⁶ kg

Conversion of 5480.7 g to kg

1000 g = 1 kg

Therefore,

5480.7 g = 5480.7 /1000

5480.7 g = 5.4807 kg

Thus, we can obtain the total mass of the samples as follow:

M1 = 0.6160959 kg

M2 = 3.225×10¯⁶ kg

M3 = 5.4807 kg

Total mass =?

Total mass = M1 + M2 + M3

Total mass = 0.6160959 + 3.225×10¯⁶ + 5.4807

Total mass = 6.096799125 ≈ 6.1 kg

Therefore, the total mass of the samples is approximately 6.1 kg.

Does the density of a liquid depend on its volume? Write your answer as a CER.

Answers

Answer: Yes

Explanation:

Density of a liquid depend on its volume. This is because Density is mass of liquid divided by volume.

Density is inversely proportional to volume.

As density increases, volume decreases and vice versa. The density for water is 1g/ milliliter but it changes with changes in temperature or there are impurities dissolved in it. Ice is less dense that liquid water and it's the major reason it's float because it's volume is inversely proportional to it's density.

Classify these bonds as ionic, polar covalent, or nonpolar covalent p cl k br c c

Answers

Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent

Between 0.4 and 1.7 then it is Polar Covalent

Greater than 1.7 then it is Ionic

For P and Cl,
E.N of Chlorine    = 3.16
E.N of Phosphorous = 2.19
   ________

E.N Difference 0.97 (Polar Covalent)

For K and Br,
E.N of Bromine      = 2.96
E.N of Potassium    = 0.82
   ________

E.N Difference 2.14 (Ionic)

For C and C,
E.N of Carbon      = 2.55
E.N of Carbon     = 2.55
   ________

E.N Difference 0.00 (Non-Polar Covalent)

What is the principal reason we must consider the uncertainty principle when discussing electrons and other subatomic particles but not when discussing our macroscopic world?

Answers

The principal reason why we must consider the uncertainty principle when discussing electrons and other subatomic particles but not when discussing our macroscopic world is:

Photons of certain frequencies can be absorbed as the electron changes energy state

According to the given question, we need to state the principal reason why the uncertainty principle is used when discussing electrons and other subatomic particles but not used in our macroscopic world.

As a result of this, we can see that the reason for this is because there are certain frequencies at which the photons can be absorbed during the electron change as energy becomes more random.