Refer to the following balance equation : 2c2h6 + 7o2 = 4co2 + 6 h20. How many moles of c2h6 will combust completely with 2.0 moles of oxygen gas. How many grams of water will be produced when 30.0 g of c2h6 reacts completely with oxygen?

Answers

Answer 1

Answer: 1. From the balanced equation given above, the ratio of the number of moles of the hydrocarbon and oxygen is equal to 2/7. Given that there are 2 moles of oxygen,

moles hydrocarbon = (2 moles O2)(2 moles HC / 7 moles oxygen)

Simplifying,
moles HC = 4/7 or 0.57 moles HC

Answer: 0.57 moles HC

2. The calculation for the mass of water is shown below with the dimensional analysis and conversion factors,

(30 g C2H6)1 mole C2H6/30 g C2H6)(6 molesH2O/2 moles C2H6)(18 g H2O/1 mole C2H6)

Simplifying,
mass = 54 grams of water

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What are neurons? Why are neurons important

Answers

Answer:

neurons are specialized to transmit information

(01.04 LC)What phase of matter has particles that are held together but can flow past each
other and takes the shape of a container, filling it from the bottom up? (3 points)
1) Gas
2) Liquid
3) Plasma
4) Solid

Answers

the answer is liquid ! hope this helped :)

1. The common name for the compound CH3-CH2-O-CH3 is

Answers

Answer:

propane

Explanation:

please mark me as brainliest

Answer:

Methoxyethane also known as ethyl methyl ether

A sample of gas occupies a volume of 67.5 mL . As it expands, it does 131.0 J of work on its surroundings at a constant pressure of 783 Torr . What is the final volume of the gas g

Answers

Answer:

The final volume $V2=1.3175L$

Explanation:

between work ( w), pressure ( P ) and volume ( V ) is the following:

w=−PΔV

where,

ΔV=V2−V1

It was stated that the gas is expanding, then the work is done by the system and it is of a negative value .

Note that work, should be expressed in 1L⋅atm=101.3J

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

A sample of iron having a mass of 93.3g is heated to 65.58OC is placed in 75.0g ofwater raising the temperature from 16.95 OC to 22.24 OC. Find the specific heatcapacity for this iron sample. The answer you find has had some lab errors due tohuman mistakes. Find your percent error for your work using %Error = [(Expected - Actual) / (Expected Yield)] x100

Answers

The heat gained or lost by a substance undergoing a change in temperature is:
Q = mCpΔT
The heat lost by the iron is equal to that gained by water. The Cp for water is 4.186 Joules/gram

75 x 4.186 x (22.24 - 16.95) = -93.3 x Cp x (22.24 - 65.58)
Cp = 0.411 J/g

The heat capacity of iron is 0.45 J/g

%Error = [(0.45 - 0.41) / 0.41] x 100
%Error = 9.76%

Need help I don't remember what to do?

Answers

I'm just doing the ones that you don't have numbers already for.
2.) just leave it alone and it's correct
3.) Mg + 2AgNo3 --> Mg(No3)2 + 2Ag
5.) just leave it alone and it's correct
8.) 10C3H8O3 + 15O2 --> 30CO2 + 4H2O
10.) P4 + 6Br2 --> 4PBr3
12.) 2FeCl3 + 6NaOH --> 2Fe(OH)3 + 6NaCl
13.) 2CH3OH + 3O2 --> 2CO2 + 4H2O
14.) 2Al + 3Cu(NO3)2 --> 2Al(NO3)3 + 3Cu
15.) 3CaCl2 + 2K3AsO4 --> Ca3(AsO4)2 + 6KCl
16.) 2NH3 --> N2 + 3H2
17.) 2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
19.) Mg3N2 + 6H2O --> 3Mg(OH)2 + 2NH3
I hope this helps you!!

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