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Given the following equation: 8 Fe + S8 ---> 8 FeSHow many moles of iron are needed to react with 16.0 moles of sulfur?
A FULL STEP EXPLANATION WILL BE APPRECIATED

Answers

Answer 1

Answer:

The number of moles of iron needed to react with 16.0 moles of sulfur is 128.0 moles.

Calculation of number of moles of iron

Given equation, 8Fe + S8 = 8 FeS

Moles of sulfur = 16.0

To react 1 mole of sulfur, we need 8 moles of Fe

So, for 16.0 moles of sulfur we need

$16.0* 8 = 128.0 moles$

Thus, to react with 16.0 moles of Sulfur, 128.0 moles of Fe is needed.

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Answer 2

Answer:

Answer:

To react with 16.0 moles of sulfur we need 128.0 moles of iron (Fe).

Explanation:

Step 1: Data given

Number of moles Sulfur = 16.0 moles

Step 2: The balanced equation

8 Fe + S8 → 8 FeS

Step 3: Calculate mole Fe

For 8 moles Fe we need 1 mol S8 to produce 8 moles FeS

For 16.0 moles of Sulfur we need 8*16.0 = 128.0 moles

To react with 16.0 moles of sulfur we need 128.0 moles of iron (Fe).

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By pipet, 11.00 mL of a 0.823 MM stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask and diluted to the calibration mark. Determine the molarity of the resulting solution. A stock solution of potassium permanganate (KMnO4) was prepared by dissolving 13.0g KMnO4 with DI H2O in a 100.00-mL volumetric flask and diluting to the calibration mark. Determine the molarity of the solution Molarity= O.822 M

Answers

Answer:

1) 0.18106 M is the molarity of the resulting solution.

2) 0.823 Molar is the molarity of the solution.

Explanation:

1) Volume of stock solution = $V_1=11.00 mL$

Concentration of stock solution = $M_1=0.823 M$

Volume of stock solution after dilution = $V_2=50.00 mL$

Concentration of stock solution after dilution = $M_2=?$

$M_1V_1=M_2V_2$ ( dilution )

$M_2=(0.823 M* 11.00 mL)/(50 ,00 mL)=0.18106 M$

0.18106 M is the molarity of the resulting solution.

Molarity of the solution is the moles of compound in 1 Liter solutions.

$Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}* Volume (L)}$

Mass of potassium permanganate = 13.0 g

Molar mass of potassium permangante = 158 g/mol

Volume of the solution = 100.00 mL = 0.100 L ( 1 mL=0.001 L)

$Molarity=(13.0 g)/(158 g/mol* 0.100 L)=0.823 mol/L$

0.823 Molar is the molarity of the solution.

Final answer:

To determine the molarity of the resulting solution, we can use the formula M1V1 = M2V2. Plugging in the given values, we find that the molarity of the resulting solution is 0.180 MM.

Explanation:

To determine the molarity of the resulting solution, we need to use the formula:

M1V1 = M2V2

Where M1 is the molarity of the stock solution, V1 is the volume of the stock solution used, M2 is the molarity of the resulting solution, and V2 is the final volume of the resulting solution.

Using the given values, we have:

M1 = 0.823 MM

V1 = 11.00 mL

V2 = 50.00 mL

Substituting these values into the formula, we can find the molarity of the resulting solution.

M2 = (M1 * V1) / V2

Plugging in the values:

M2 = (0.823 MM * 11.00 mL) / 50.00 mL = 0.180 MM

The molarity of the resulting solution is 0.180 MM.

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Calculate the mass % of magnesium sulfate (assume that there is a 1:1 mol ratio between sulfate and magnesium sulfate) in the original sample. Report your answer without units and use 3 sig figs, i.e. 55.23543% would be entered as 55.2

Answers

61.8 % is the mass percentage of magnesium sulphate.

Explanation:

The mass percent of individual solute or ion in a compound is calculated by the formula:

Grams of solute ÷ grams of solute + solvent × 100

mass percent of magnesium is calculated as 1 mole of magnesium having 24.305 grams/mole will have weight of 24.305 grams and 1 mole of MgSO4 will have 120.366 grams

Putting the values in the equation:

24.305 ÷ 144.671 × 100

= 16.8% of magnesium is in the mixture

The mass percentage of SO4 is calculated as

= 96.06 ÷ 216.426 × 100

= 44.38 %

The mass percentage of the mixture MgSO4 is 44.38 + 16.8 = 61.8 %

Mass percentage is a representation of the concentration of element or elements in a compound.

A gas occupies a volume of 30.0L, a temperature of 25°C and a pressure of 0.600atm. What will be the volume of the gas at STP?

Answers

Answer:

=16.49 L

Explanation:

Using the equation

P1= 0.6atm V1= 30L, T1= 25+273= 298K, P2= 1atm, V2=? T2= 273

P1V1/T1= P2V2/T2

0.6×30/298= 1×V2/273

V2=16.49L

Which is not the name of a family on the periodic tablea) Halogens
b) Noble Gases
c) Alkali Earth Metals
d) Actinides

Answers

Answer:

I think it's D

Explanation:

Actinides is the correct answer
your noble gases are in the 8th column
Your Halogens are your 7th column
and you alkali earth metals are the 2nd column

What is the volumetric flow rate in L/s of a stream of air (density = 1 kg/m3) at 1 kg/s?

Answers

Answer:

Volumetric flow rate: Q = 1000 L/s

Explanation:

Volumetric flow rate, also called the rate of fluid flow, is described as volume of fluid that passes a particular point per unit time. The SI unit of volumetric flow rate is m³/s.

Whereas, mass flow rate is defined as the mass of substance that passes through a point per unit of time. SI unit is kg/s.

Given- mass flow rate: ṁ = 1 kg/s and density: ρ = 1 kg/m³

Therefore, volumetric flow rate can be calculated by

$Q = \frac{\dot{m}}{\rho } = (1 kg/s)/(1 kg/m^(3)) = 1 m^(3)/s$