Consider the generic chemical equation below. X + Ymc021-1.jpg W + Z Reactant X contains 199.3 J of chemical energy. Reactant Y contains 272.3 J of chemical energy. Product W contains 41.9 J of chemical energy. If the reaction loses 111.6 J of chemical energy as it proceeds, how much chemical energy must product Z contain?

Answers

Answer 1
Answer:

The reaction is:

X + Y → W + Z

Chemical energy of reactant X = 199.3 J = Ux

Chemical energy of reactant Y = 272.3 J = Uy

Chemical energy of Product W = 41.9 J = Uw

Chemical energy of Product Z = ? = Uz

Where reaction loses energy = 111.6 J = ΔU

By using the equation:

(Ux + Uy) – (Uw + Uz) = ΔU

Ux + Uy – Uw – Uz = ΔU

Uz = Ux + Uy – Uw –ΔU

Uz = 199.3 + 272.3 – 41.9 – 111.6

Uz = 318.1 J

Product Z must contain 318.1 J chemical energy.

Answer 2
Answer:

Answer:

person above me is correct

Explanation:


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Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. If 2.80g of carbon dioxide is produced from the reaction of 3.4g of octane and 5.9g of oxygen gas, calculate the percent yield of carbon dioxide. Be sure your answer has the correct number of significant digits in it.

Answers

Answer:

54%

Explanation:

The balanced equation is:

2 CH_(3)(CH_(2))_(6)CH_(3) + 25 O_(2) = 16 CO_(2) + 18 H_(2)O

The first step is to determine the limiting reactant. For this, we calculate the moles of each given component and divide the result for the stoichiometric coefficient.

3.4 g octane / 114.23 g/mol = 0.030 mol octane

0.030 mol octane/2=0.015

5.9 g O2 / 32 g/mol = 0.18 mol O2

0.18 mol O2/25= 0.0074 mol

The lower number, in this case oxygen, is the limiting reactant. The value corresponds to the theoretical yield of the reaction.

Similarly, the real yield is calculated from the product.

2.80 g CO2/ 44.01 g/mol = 0.0636 mol CO2

0.0636 mol CO2/16 = 0.00398 mol

The percent yield is the ratio of the 2 multiplied by a hundred, then

Percent yield= 0.0398/0.0074 *100 = 54%

Final answer:

The percent yield of carbon dioxide from the combustion reaction of octane and oxygen, given the provided masses of the reactants and the yield of CO2, is calculated to be 26.7%

Explanation:

The combustion of octane in oxygen yields carbon dioxide and water in a 1:1 ratio, as the balanced chemical equation for the reaction is 2C8H18 + 25O2 -> 16CO2 + 18H2O. To calculate the percent yield of CO2, we first need to determine the theoretical yield of CO2. We can use the provided masses of octane and O2 and their respective molar masses to calculate the number of moles of each reactant:

- Moles of octane = 3.4 g / 114.22 g/mol = 0.0298 mol
- Moles of O2 = 5.9 g / 32.00 g/mol = 0.184 mol

Now, using the stoichiometric relationship from the balanced chemical equation, we can calculate the theoretical yield of CO2:

- Theoretical yield = 0.0298 mol octane x 16 mol CO2/2 mol octane = 0.238 mol CO2

Next, we convert this to grams using the molar mass of carbon dioxide:

- Theoretical yield = 0.238 mol CO2 x 44.01 g/mol = 10.5g CO2

Now that we have both the actual yield (2.80 g) and the theoretical yield (10.5 g), we can calculate the percent yield:

- Percent yield = (actual yield / theoretical yield) x 100% = (2.80 g / 10.5 g) x 100% = 26.7%

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In the reaction C zH4 + H2 - e) +4 CHo the carbon atoms are a) oxidized b) reduced c) cannot be determined

Answers

Answer: Option (b) is the correct answer.

Explanation:

Reduction is defined as the process in which there occurs gain of hydrogen. Whereas oxidation is defined as the process in which there occurs loss of hydrogen.

As the given reaction is as follows.

      C_(2)H_(4) + H_(2) \rightarrow C_(2)H_(6)

Since, hydrogen is being added in this chemical reaction. It means that reduction is taking place and carbon atom is reduced.

Thus, we can conclude that in the given reaction carbon atoms are reduced.

List the 6 steps of the scientific method in the correct order. (7 points)For each step, explain what is going on during this step of scientific investigation. Do not simply restate the step. (7 points)

Be mindful of your spelling.

Answers

Scientific method involves the systematic step by step method of answering a question. The six major steps involved in a scientific method are purpose, research, hypothesis, experiment, analysis, and conclusion.

Purpose of a scientific method is the question being asked or the problem to be solved.

Research is the collection of background information relevant to the purpose of the experiment.

Hypothesis is the answer predicted to the question under study, as per the background research.

Experiment is the testing of the hypothesis. Experiment has independent and dependent variables, independent variable is changed by the experimenter and its effect is studied on the dependent variable.

Analysis involves the data interpretation in order to prove the hypothesis.

Conclusion is the review of data set to prove the hypothesis to be correct or incorrect.

Answer: -

1. Observation

Any incident that makes the scientific mind curious is an observation for the scientific mind.

2. Question

The scientific mind then refines the general observation into a proper line of curiosity to ponder the reason behind it.

3. Hypothesis

A hypothesis is an informed guess as to the possible answer of the question developed by the scientific mind. Hypothesis may not be correct but should provide a direction for further investigation.

4. Experiment

To test the hypothesis, the scientific mind designs an experiment. The experiment must be controlled and reproducible.

5. Analysis

Using several trials of the experiment, the results are noted down. The data is then correlated with the hypothesis.

6. Conclusion

After analysis of the data, a conclusion is drawn on whether the hypothesis is correct or incorrect. If the hypothesis is incorrect, then a new hypothesis must be made.

If it is correct, then our original question is answered.

What is the empirical formula of a compound that is 64.3 % c, 7.2 % h, and 28.5 % o by mass?

Answers

Asnwer : Empirical formula of a compound is : C_(3)H_(4)O

Given information : C = 64.3 % , H = 7.2 % , O = 28.5 %

Step 1 : Convert the given percentage (%) to grams.

Explanation : Let the total mass of the compound be 100 grams.

Mass of C = 64.3 g

(100g)* ((64.3percent))/((100percent)) = 64.3g

Mass of H = 7.2 g

(100g)* ((7.2percent))/((100percent)) = 7.2g

Mass of O = 28.5 g

(100g)* ((28.5percent))/((100percent)) = 28.5g

Step 2 : Convert the grams of each compound to moles.

Moles = (Grams)/(Molar mass)

Molar mass of C = 12.0g/mol  

Molar mass of H = 1.0 g/mol

Molar mass of O = 16.0g/mol

Moles of C = (64.3g)/(12.0(g)/(mol))

Moles of C = 5.36 mol

Moles of H = (7.2g)/(1.0(g)/(mol))

Moles of H = 7.2 mol

Moles of O = (28.5g)/(16.0(g)/(mol))

Moles of O = 1.78 mol

Step 3 : Find the mole ratio of C , H and O

Mole ratio is calculated by dividing the mole values by the smallest value.

Mole of C = 5.36 mol , Mole of H = 7.2 mol , Mol of O = 1.78 mol

Out of the three mole values , mole value of O that is 1.78 mol is less , so we divide all the mole values by 1.78 mol.

Mole of C = (5.36mol)/(1.78mol) = 3.0

Mole of H = (7.2mol)/(1.78mol) = 4.0

Mole of O = (1.78mol)/(1.78mol) = 1.0

C : H : O = 3 : 4 : 1

So empirical formula of the compound is C_(3)H_(4)O_(1) or C_(3)H_(4)O

Larry was told that a certain muscle cream was the newest best thing on the market and claims to double a person’s muscle power when used as part of a muscle-building workout. Interested in this product, he buys the special muscle cream and recruits Patrick and SpongeBob to help him with an experiment. Larry develops a special marshmallow weight-lifting program for Patrick and SpongeBob. He meets with them once every day for a period of 2 weeks and keeps track of their results. Before each session Patrick’s arms and back are lathered in the muscle cream, while Sponge Bob’s arms and back are lathered with the regular lotion.Which person is the control group?



SpongeBob

SpongeBob


Patrick

Patrick


Larry

Answers

SpongeBobs twin brother and Larry and Patrick’s twin brother

Final answer:

In the experiment, SpongeBob is the control group because regular lotion is used instead of the muscle cream. This allows a comparison with Patrick(rightly known as the experimental group) who uses the special muscle cream.

Explanation:

In the given scenario, SpongeBob represents the control group. In any experiment, the control group is the one that is kept normal or unchanged to be able to compare the effects of the variable being tested. In this case, it's the use of the special muscle cream. Patrick, whose arms and back are lathered with the muscle cream before each session, represents the experimental group because he is exposed to the variable being tested, which is the muscle cream. On the other hand, SpongeBob, who is given regular lotion instead of the special muscle cream, is part of the control group because he helps to provide a baseline for comparison.

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A 3.25 L solution is prepared by dissolving 285 g of BaBr2 in water. Determine the molarity.

Answers

Answer:

0.295 mol/L

Explanation:

Given data:

Volume of solution = 3.25 L

Mass of BaBr₂ = 285 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of solute:

Number of moles = mass/ molar mass

Molar mass of BaBr₂ = 297.1 g/mol

Number of moles = 285 g/ 297.1 g/mol

Number of moles= 0.959 mol

Molarity:

M = 0.959 mol / 3.25 L

M = 0.295 mol/L

Final answer:

The question is about calculating the molarity of a solution. First, convert the given mass of solute into moles using the molar mass. Then, using the molarity formula, divide the moles of solute by the volume of the solution in liters.

Explanation:

In order to determine the molarity of the solution, we will divide the amount of solute (in moles) by the volume of the solution (in liters). The formula for molarity (M) is:

M = moles of solute/volume of solution in liters

First, we need to convert the mass of BaBr2 into moles. The molecular weight of BaBr2 is 297.14 g/mol. So, 285 g of BaBr2 is equal to 285/297.14 = 0.959 moles.

 

The volume of the solution is given as 3.25 L. So, plugging these values into the formula gives us the molarity of the solution:

 

M = 0.959 moles/3.25 L = 0.295 M

So, the molarity of the solution is 0.295 M.

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