Inside a calorimeter, two solutions are mixed and result in an endothermic reaction. Which of the following best illustrates how this reaction affects the water in the calorimeter? (2 points)Select one:
a. The reaction has no effect on the water. The kinetic energy of the water molecules remains the same.
b. The reaction causes the temperature of the water to increase. The kinetic energy of the water molecules increases.
c. The reaction causes the temperature of the water to decrease. The kinetic energy of the water molecules decreases.
d. The reaction causes the temperature of the water to decrease. Then, the water gains heat from the surroundings and the kinetic energy of the water molecules increases.

Answers

Answer 1

Answer: The correct option is C. A calorimeter is an isolated system. In isolated systems there is no exchange whatsoever with the surrounding. In an isolated system, an endothermic reaction results in a decrease in the temperature of the system. This is in contrast to the effect of an endothermic reaction in an open system. The heat of reaction remains a positive quantity.

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You wish to prepare 100 mL of a 0.100 M solution by dilution of a 1.00 M solution. Which of the following pieces of glassware will you use? A. 100 mL graduated cylinder B. 100 mL volumetric flask C. 10 mL volumetric pipet D. 25 mL volumetric pipet E. 10 mL graduated pipet F. 25 mL graduated pipet
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How many molecules are in 2.50 moles of co2

How much heat energy would be needed to raise the temperature of a 223 g sample of aluminum [(C=0.895 Jig Cy from 22.5°C to 55 0°C? Η Ο Ο Ο ΟΟ 10x10) not enough information given Prov 40 25 11 Next >

Answers

Answer : The heat energy needed would be, 6486.5125 J

Explanation :

To calculate the change in temperature, we use the equation:

$q=mc\Delta T\n\nq=mc(T_2-T_1)$

where,

q = heat needed = ?

m = mass of aluminum = 223 g

c = specific heat capacity of aluminum = $0.895J/g^oC$

$\Delta T$ = change in temperature

$T_1$ = initial temperature = $22.5^oC$

$T_2$ = final temperature = $55.0^oC$

Putting values in above equation, we get:

$q=223g* 0.895J/g^oC* (55.0-22.5)^oC$

$q=6486.5125J$

Therefore, the heat energy needed would be, 6486.5125 J

Which of the following changes is observed when we move across the row from left to right in the periodic table?

Answers

Answer:

there is no picture to look at

Answer:

Metallic character decreases as you move across a period in the periodic table from left to right. This occurs as atoms more readily accept electrons to fill a valence shell than lose them to remove the unfilled shell.

How many molecules are there in 4.27 mol of tungsten(VI) oxide, WO3

Answers

25.71 × 10²³ molecules are there in 4.27 mol of tungsten (VI) oxide, $WO_3$ .

How to find the number of molecules ?

To find the Number of molecules of substance multiply the number of moles of given substance by Avogadro number

Number of molecules = Number of moles × Avogadro's Number

Avogadro's Number

Avogadro's number $(N_(A))$ is the number of particles in one mole of substance. 6.023 × 10²³ is known as Avogadro's constant / Avogadro's number.

Avogadro's number = 6.023 × 10²³ $mol^(-)$

Now,

Number of molecules in 4.27 moles of $WO_(3)$

= Number of moles of $WO_(3)$ × Avogadro's Number

= 4.27 × 6.023 × 10²³

= 25.71 × 10²³ molecules

Thus, we can say that 25.71 × 10²³ molecules are there in 4.27 moles of tungsten (VI) oxide, $WO_3$ .

Learn more about the Avogadro's Number here: brainly.com/question/859564

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Answer:

Molar mass of WO3 = 231.8382 g/mol

Convert grams Tungsten(VI) Oxide to moles or moles Tungsten(VI) Oxide to grams

Molecular weight calculation:

183.84 + 15.9994*3

Explanation:

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A 14 wt% solution of cacl2 (110.98 g/mol) has a density of 1.126 g/ml. what is the mass (in milligrams) of a 20.0-ml solution of 14.0 wt% cacl2?

Answers

Density = mass / volume

Thus, Mass of the solution can be expressed as:

Mass of solution = Density of solution × volume of solution

Given- Density of solution = 1.126 g/ml

volume of solution = 20.0 ml

∴ Mass of 14 wt% solution of CaCl2 = (1.126 g/ml) × (20 ml)

= 22.52 g

= 22520 mg

What is the covalent bond for CO?

Answers

Answer:

Covalent bond or common bond is one of the types of chemical bonds. This connection arises from electronic participation. In fact, atoms that need to receive electrons to achieve stable electron arrangement (noble gas electron arrangement or octagonal arrangement) share electrons in their valence layer with other atoms. In this case, the transfer of electrons from one atom to another does not take place, but only a pair of electrons, called a bonded or shared electron pair, belongs to the nucleus of two atoms.

Construction crews sometimes use this reaction for welding underwater structures:Fe2O3 + 2Al → Al2O3 + 2Fe

How many moles of iron (Fe) would be produced if 2.50 mol Fe2O3 react? Make sure to use the correct number of significant figures in your answer.

2.50 mol Fe2O3 =