Solve: 16x2 − 81 = 0.x = 4, 9
x = −4, −9
x = 9 over 4, x = −9 over 4
x = 81 over 16, x = −81 over 16

Answers

Answer 1

Answer: If you would like to solve 16x^2 - 81 = 0, you can calculate this using the following steps:

16x^2 - 81 = 0
(4x - 9) * (4x + 9) = 0
1. 4x - 9 = 0 ... 4x = 9 ... x = 9/4
2. 4x + 9 = 0 ... 4x = - 9 ... x = - 9/4

The correct result would be: x = 9 over 4, x = −9 over 4.

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Write an equation of a line in slope-intercept form. Slope = -2, y-intercept = 34

Answers

Answer:

y=-2x+34

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

Pablo is training for a marathon . He ran 5 4/8 miles on Friday 6 5/8 on sat and 7 4/8 on Sunday how many miles did he run A. 1 5/8
B. 12 1/8
C. 19 4/8
D. 19 5/8

Answers

If you would like to know how many miles did Pablo run, you can calculate this using the following steps:

5 4/8 miles on Friday + 6 5/8 miles on Saturday + 7 4/8 miles on Sunday = 5 4/8 + 6 5/8 + 7 4/8 = 44/8 + 53/8 + 60/8 = 157/8 = 19 5/8 miles

The correct result would be D. 19 5/8 miles.

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Answers

For this case we have the following functions:

The first thing we must do for this case is to subtract both functions.

We have then:

Substituting we have:

Rewriting we have:

Evaluating the obtained function for x = 3 we have:

Answer:

The value of the function evaluated at x = 3 is:

$(g - f) (3) = 23$

f(x) = -x² + 4
g(x) = 6x

(g - f)(3) = 6(3) - (-(3)² + 4)
(g - f)(3) = 18 - (-9 + 4)
(g - f)(3) = 18 - (-5)
(g - f)(3) = 18 + 5
(g - f)(3) = 23

Graham and Hunter are circus performers. A cable lifts Graham into the air at a constant speed of 1.5 ft/s. When Graham’s arms are 18 ft above the ground, Hunter, who is standing directly underneath Graham, throws Graham a ball as the cable continues to lift him higher. Hunter throws the ball from a position 5 ft above the ground with an initial velocity of 24 ft/s. Which system of equations can be used to model this situation?A) h=18+1.5t
h=5+24t-16t^2

B) h=18+1.5t
h=5+24t+16t^2

C) h=18+1.5t
h=5+24t

D) h=18t+1.5t-16t^2
h=5+24t-16t^2

Answers

Answer: Hello there!

this type of equations in one dimension (when all the factors are constants) are written as:

h = initial position + initial velocity*t + (acceleration/2)*t^2

First, let's describe the hunter's equation:

We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.

If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:

h = 18 + 1.5t

where t in seconds.

Now, the equation for the ball:

We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)

the equation for the ball is:

h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2

So the system is:

h = 18 + 1.5t

h = 5 +24t - 16.1t^2

so the right answer is A

Answer:

Step-by-step explanation:

EDGE 2020

Which quadrilateral does NOT always have congruent diagonals? Why? I know it is a rhombus but i dont know why. someone please help!

Answers

the formule of rhombus is 1/2 d1,d2
since the both diagonals can be of different lenght becos the diagonal through the base may not be equal to the diagonal of the hypotenuse,since the
rhombus is a square also

Most quadrilateral will not have congruent diagonals: rectangles (incl squares) and isosceles trapezium are the exception.

This is to help my wonderful mother. What is 1/3rd of 4 1/2s and 8 1/4s?