MATHEMATICS HIGH SCHOOL

Find the value of y in the diagram.

Answers

Answer 1

Answer:

Answer:

6.3

Step-by-step explanation:

y/9=7/10

cross multiply

10y=63

y =6.3

Related Questions

The domain of the following relation: R: {(−4, 8), (8, 10), (5, 4), (1, 6), (5, −9)} is{8, 10, 4, 6, −9} {−4, 1, 5, 8} {−4, 8, 5, 1, 5} No domain exists
Urgent help! This is very important please help me fast! How do you do: Expand & simplify:(x 4)(x 2)Can you tell me how to work it out please?
2. Given the following functions f(x) and g(x), solve (f + g)(5) and select the correct answer below:f(x) = 8x − 13 g(x) = x − 9 23 27 31 40
To change .3 to a fraction you must put 3 over what denominator?a. .1 b. 100 c. 1 d. 10
115 is greater, less than or equal to 10 = _ hm

What is the answer 8x-7 = 3x-7+5x

Answers

The answer is x=0 cause everything cancels out

A group of n friends go to the gym together, and while they are playing basketball, they leave their bags against the nearby wall. an evildoer comes, takes the student id cards from the bags, randomly rearranges them, and places them back in the bags, one id card per bag. (a) what is the probability that no one receives his or her own id card back? hint: use the inclusion-exclusion principle. (b) what is the limit of this proability as n â â? hint: e x = â â k=0 x k k! .

Answers

Answer:

bro just ask around lol or go find the person problem solved

Step-by-step explanation:

Mars takes 686 days to orbit the Sun. What percent is this of the time it takes the Earth to orbit the Sun?

Answers

All you want to do is find what 686-365 is because that's the percent increase. Next you divide the number that you got by 365 and that's your percentage increase.

While visiting in New York City, Monica rode in an Uber. The Uber driver charged her a fixed fee of $8 plus $4 for each mile she rode. Which equation could Monica have used to calculate the total cost in dollars as a function of the distance traveled, in miles, m? In addition, what is the range of the function for a maximum 5 mile taxi ride? f of m = 8(m) plus 4, Range: , 0, symbol, f of m, symbol, 28 f of m = 4(m), Range: , 0, symbol, f of m, symbol, 28 f of m = 4(m) plus 8 Range: , 8, symbol, f of m, symbol, 28 f of m = 4(m) plus 12, Range: , 0, symbol, f of m, symbol, 5

Answers

Step-by-step explanation:

The options are not to clear, nevertheless let us model the expression for the cost.

Let y be the total cost

And x be the number of miles

Given that the fixed rate is $8 and $4 for each extra mile traveled

The total cost is

y=8+4x

For a 5 mile journey the cost is

y=8+4(5)

y=8+20

y=28

$28

Where are the x-intercepts for f(x) = −4cos(x − pi over 2) from x = 0 to x = 2π?

Answers

recall that to get the x-intercepts, we set the f(x) = y = 0, thus

$\bf \stackrel{f(x)}{0}=-4cos\left(x-(\pi )/(2) \right)\implies 0=cos\left(x-(\pi )/(2) \right)\n\n\ncos^(-1)(0)=cos^(-1)\left[ cos\left(x-(\pi )/(2) \right) \right]\implies cos^(-1)(0)=x-\cfrac{\pi }{2}\n\n\nx-\cfrac{\pi }{2}=\begin{cases}(\pi )/(2)\n\n(3\pi )/(2)\end{cases}$

$\bf -------------------------------\n\nx-\cfrac{\pi }{2}=\cfrac{\pi }{2}\implies x=\cfrac{\pi }{2}+\cfrac{\pi }{2}\implies x=\cfrac{2\pi }{2}\implies \boxed{x=\pi }\n\n-------------------------------\n\nx-\cfrac{\pi }{2}=\cfrac{3\pi }{2}\implies x=\cfrac{3\pi }{2}+\cfrac{\pi }{2}\implies x=\cfrac{4\pi }{2}\implies \boxed{x=2\pi }$

you began membership in a new health and fitness club which has access to a dietician and personal trainer. They help you develop a special eight-week diet and exercise program. The data in the following table represents your weight, w, as a function of time, t, over an eight-week period. Time (weeks) 0 1 2 3 4 5 6 7 8 Weight (lb) 150 144 143 141 140 137 137 132 129. If you lost 13 pounds in the first five weeks, what is the average rate of change of weight with respect to time over the first five weeks of the program?

Answers

Time (weeks) 0 1 2 3 4 5 6 7 8
Weight (lb) 150 144 143 141 140 137 137 132 129

Change in time (weeks) = 5 - 0 = 5 = -0.3846
Change in weight (lbs) 137 -150 -13

The average rate of change of weight with respect to time over the first five weeks of the program is -0.3846. It is a negative sign because the weight is decreasing.

Answer:

On e2020 the correct answer is D -2.6 pounds per week

Step-by-step explanation:

I just took the test.

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