MATHEMATICS HIGH SCHOOL

Find the product of (4x + 3y)2.16x2 − 24x + 9y2
16x2 + 24xy + 9y2
16x2 − 9y2
16x2 + 9y2

Answers

Answer 1
Answer: 16+24xy+9y2 that is what I got
Answer 2
Answer: I got 8x+6y when i did it

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Three of the angles of a quadrilateral are 120 48 and 92 what is the size of the 4th angle

Answers

Answer:

Measure of fourth angle of quadrilateral is:

100

Step-by-step explanation:

We know that the sum of angles in a quadrilateral is 360°

Three of the angles of a quadrilateral are 120 48 and 92

we have to find the sum of the fourth angle of the quadrilateral

Let measure of fourth angle be x

120+48+92+x= 360

i.e. 260+x = 360

Subtracting both sides by 260, we get

x= 100

Hence, Measure of fourth angle of quadrilateral is:

100
You do 120+48+92=280All angles in a quadrilateral add up to 360, so 360-280=80The answer is 80HAVE FUN DOING MATHS!

Which is larger, 4/7 or 2/3?

Answers

2/3 becuase 2/3 in 4/7 is like 4.5/7

Variable g is 5 more than variable w. Variable g is also 2 less than w. Which pair of equations best models the relationship between g and w?g = w + 5
g = w − 2

g = w − 5
g = w + 2

w = 5g
w = g − 2

w = 5g
w = g + 2

Answers

Your answer is the first choice, g = w + 5    &    g = w − 2, because if variable g is 5 MORE THAN variable w, that would mean you would have to add 5 to w in order to get g, (g = w + 5), but if it said it was 5 TIMES MORE THAN, THHHHEEEENNNNN that would mean w times 5.
Now da second problem is g = w - 2, because they said that g is 2 LESS THAN w, so you would have to subtract 2 from w to get g, also known as g = w - 2.
I hope I helped! =D
g=w+5
g=w-2
This confused me at first as well, but just try and make a picture in your mind, anyway, if you add 5 to W, then it is equal to g because "Variable g is 5 more than variable w" 
If you subtract 2 from w it is equal to g because Variable g is also 2 less than w."

in 3 months Us energy giant Enron went from a company with assets of 62bn to a company with depts of 18bn What is the difference between these two amounts?

Answers

Its just 62-18 so it would be 44bn

6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP and 324 from Q. How far is the ship from each of the coastguard stations?

Answers

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^(o) - 324^(o)

     = 036^(o)

Sum of angles in a triangle = 180^(o)

<P + <Q + <S = 180^(o)

048° + 036^(o) + <S = 180^(o)

84^(o) + <S = 180^(o)

<S  = 180^(o) -  84^(o)

    = 96^(o)

<S = 96^(o)

Applying the Sine rule,

(y)/(Sin P) = (x)/(Sin Q) = (z)/(Sin S)

(y)/(Sin P) = (z)/(Sin S)

(y)/(Sin 48^(o) ) = (17)/(Sin 96^(o) )

(y)/(0.74314) = (17)/(0.99452)

⇒ y = (12.63338)/(0.99452)

       = 12.703

y = 12.70 km

(x)/(Sin Q) = (z)/(Sin S)

(x)/(Sin 36^(o) ) = (17)/(Sin 96^(o) )

(x)/(0.58779) = (17)/(0.99452)

⇒ x = (9.992430)/(0.99452)

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Solve 5m − 3h = 45 for h. Show your work.

Answers

Answer:

h =  -15 +(5)/(3).

Step-by-step explanation:

Given  :  5m − 3h = 45.

To find : Solve  for h.

Solution : We have given 5m − 3h = 45.

On subtracting both sides by 5m.

- 3h = 45 - 5m.

On dividing both sides by -3 .

h = (45 - 5m)/(-3).

h = (45)/(-3) +(5)/(3).

h =  -15 +(5)/(3).

Therefore , h =  -15 +(5)/(3).
5m-3h= 45
-5m -5m
(-3h= 45-5m)/(-3) to get h alone.
h= (-45/3)-(5/-3)m, simplify
h=-15+(5/3)m
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