CHEMISTRY HIGH SCHOOL

A certain reaction has an activation energy of 66.41 kJ/mol. At what Kelvin temperature will the reaction proceed 3.00 times faster than it did at 293 K?

Answers

Answer 1

Answer:

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

$K=A* e^{(-Ea)/(RT)}$

or,

$\log ((K_2)/(K_1))=(Ea)/(2.303* R)[(1)/(T_1)-(1)/(T_2)]$

where,

$K_1$ = rate constant at $T_1$ = $K_1$

$K_2$ = rate constant at $T_2$ = $3K_1$

$Ea$ = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 293 K

$T_2$ = final temperature = ?

Now put all the given values in this formula, we get:

$\log ((3K_1)/(K_1))=(66410J/mole)/(2.303* 8.314J/mole.K)[(1)/(293K)-(1)/(T_2)]$

$T_2=392.462K$

Therefore, the temperature will be, 392.462 K

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The correct answer for the question that is being presented above is this one: "c. carbonization."

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The gases listed are at standard temperature and pressure: · 1 mol of CO2 gas · 1 mol of N2 gas · 2 mol of O2 gas Which statement is correct? The volume of 1 mol of CO2 is greater than that of 2 mol of O2 . The volume of 1 mol of CO2 is greater than that of 1 mol of N2 . The volumes of 2 mol of O2 and 1 mol of N2 gases are the same. **The volumes of 1 mol of CO2 and 1 mol of N2 gases are the same.**

Answers

Answer : The volume of 1 mole of $CO_(2)$ and $N_(2)$ gases are the same.

Solution: Given,

Moles of $CO_(2)$ = 1 mole

Moles of $N_(2)$ = 1 mole

Moles of $O_(2)$ = 2 mole

Formula used for ideal gas is :

P V = n R T

According to the question, the gases are at standard temperature and pressure. So, the volume of gases only depends on the number of moles. This means that the higher the number of moles, higher will be the volume of gas.

The moles of $O_(2)$ are more than the moles of $CO_(2)$ and $N_(2)$ . So, the volume of $O_(2)$ will be more.

And the moles of $CO_(2)$ and $N_(2)$ are equal. Therefore, their volumes are also equal.

Therefore, the best option is the volume of 1 mole of $CO_(2)$ and $N_(2)$ gases are the same.

The right answer for the question that is being asked and shown above is that: "The volumes of 1 mol of CO2 and 1 mol of N2 gases are the same." The statement that is correct as far as the gases listed are at standard temperature and pressure is concerned is that the volumes of 1 mol of CO2 and 1 mol of N2 gases are the same

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Answers

The Earth would then intern become way too hot.

At the moment the sun provides just the right amount of heat to sustain all life on Earth, if the Earth absorbed all of the heat from the sun, the temperature would increase dramatically, leading to extreme heat. That would also lead to pretty much everything on the planet to die.

Hope this helps! :)
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Answers

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