When molten material hardens and cools, what type of rock is formed?

Answers

Answer 1

Answer: Should be an igneous rock.

Related Questions

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BaCl2 (aq) and K2CrO4 (aq) combine in a double replacement reaction. Select the reaction below that correctly represents the products of the reaction. BaCl2 (aq) + K2CrO4 (aq) Ba (s) + 2KCl (aq) + 2Cr (s) + 2O2 (g) BaCl2 (aq) + K2CrO4 (aq) BaCrO4 (s) + 2KCl (aq) BaCl 2 (aq) + K2CrO4 (aq) BaCrO3 (s) + 2KCl (aq) + O (g) BaCl2 (aq) + K2CrO4 (aq) BaCrO4 (s) + KCl (aq)
Explain why hydrogen and oxygen are considered elements whereas water is not considered an element.

What is the theoretical yield of sodium oxide (Na₂O) in grams when 20.0g of calcium oxide (CaO) reacts with an excess amount of Sodium chloride? *10 points
Captionless Image
10.0g
22.1g
32.9g
5.6g

Answers

Answer:

22.1 g

Explanation:

The balanced reaction equation which serves as a guide in solving the problem is given as;

CaO(s) + 2NaCl(aq) ------> Na2O(s) + CaCl2(aq)

The question clearly specifies that sodium chloride is the reactant in excess. This means that calcium oxide should be used to calculate the theoretical yield of sodium oxide.

Number of moles of calcium oxide reacted = mass of calcium oxide / molar mass of calcium oxide

Molar mass of calcium oxide = 56.0774 g/mol

Mass of calcium oxide = 20.0g

Number of moles of calcium oxide = 20.0 g/ 56.0774 g/mol = 0.3566 moles

From the balanced reaction equation;

1 mole of calcium oxide produces 1 mole of sodium oxide

Therefore, 0.3566 moles of calcium oxide will produce 0.3566 moles of sodium oxide.

Mass of sodium oxide produced = number of moles × molar mass

Molar mass of sodium oxide= 61.9789 g/mol

Mass of sodium oxide = 0.3566 moles × 61.9789 g/mol

Mass of sodium oxide= 22.1 g

Answer:

22.1g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + 2NaCl —> Na2O + CaCl2

Next, we shall determine the mass of CaO that reacted and the mass of Na2O produced from the balanced equation.

This is illustrated below:

Molar mass of CaO = 40 + 16 = 56g/mol

Mass of CaO from the balanced equation = 1 x 56 = 56g

Molar mass of Na2O = (23x2) + 16 = 62g/mol

Mass of Na2O from the balanced equation = 1 x 62 = 62g

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Finally, we can determine the theoretical yield of Na2O as follow:

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Therefore, 20g of CaO will react to produce = (20 x 62)/56 = 22.1g of Na2O.

Therefore, the theoretical yield of Na2O is 22.1g

Which statement correctly describes whether a compound is a pure substance? A compound is not a pure substance because each of its molecules is made up of the atoms of two or more different elements. A compound is a pure substance because its molecule cannot be broken down into simpler particles by physical means. A compound is not a pure substance because it is not an element, and only elements are pure substances. A compound is a pure substance because it consists of two different elements, which are pure substances.

Answers

Answer is: A compound is a pure substance because its molecule cannot be broken down into simpler particles by physical means.

Pure substance is made of only one type of atom (element) or only one type of molecule, it has definite and constant composition with distinct chemical properties. Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.

Electrolysis of water (pure substance) is the chemical separation, because from one molecule (water) two molecules (hydrogen and oxygen) are produced. Water is separeted into two molecules:

Reaction of reduction at cathode: 2H⁺(aq) + 2e⁻ → H₂(g).

Reaction of oxidation at anode: 2H₂O(l) → O₂(g) + 4H⁺(aq) + 4e⁻.

Answer:

ANSWER:B
i take the test

What percent by mass of each chloroform molecule is composed of chlorine?

Answers

So chloroform is CHCl3 so the first thing we need to do is find out what the mass in amu of one atom of chloroform:
12.01amu(C)+1.008amu(H)+3*35.45amu(Cl3)=119.368amu
Then we find the amu of the Cl in the molecule which is 3*35.45amu=106.35amu
Then to find the percent by mass we take the mass of the 3 Cl divide it by the total mass of the molecule and multiply by 100.
so 106.35/119.368=0.89094 and 0.89094*100=89.094%
so the percent by mass of each chloroform molecule that is composed of chlorine is 89.094%!
I hope this helps!

Magnesium is an alkaline earth metal with an atomic number of 12. It’s in the third row in the periodic table. Which expression shows one way to find the number of valence electrons in one atom of magnesium?

Answers

Answer:

group # = # valence electrons

group 2= 2 valence electrons

Explanation:

Mg is in group #2 and subsequently has 2 valence electrons (electrons on the outermost shell)

After 32 days, 5 milligrams of an 80-milligram sample of a radioactive isotope remains unchanged. What is the half-life of this element?(1) 8 days (3) 16 days
(2) 2 days (4) 4 days

Answers

Unstable heavy atoms will undergo radioactive decay to produce stable species. The half life time of the isotope which undergone a decay of 75 mg in 32 days is 18 days.

What is half life time?

The half life time of a radioactive sample is the time taken to reduce it to half of the initial amount by decay.

The heavy unstable material have very short half life and they will easily undergoes radioactive decay by emitting certain radiation.

Radioactive decay is a firs order reaction and have the equation to find the radioactive constant as follows:

$\lambda = (1)/(t) log([Ni])/([Nt])$

Where, t is the time of decay and Ni and Nt be the initial and final amount respectively.

It is given that 5 mg is remaining out of 80 mg after 32 days. Thus the radioactive constant is calculated as follows:

$\lambda = (1)/(32 days ) log (80)/(5) \n \n = 0.0376. days ^(-1)$

Now the half life time of the decay is calculated as below:

t(1/2) = 0.693 /decay constant

= 0.693/0.0376

= 18 days

Therefore, the half life time of the isotope which undergone a decay of 75 mg in 32 days is 18 days.

To find more about radioactive decay, refer the link below:

brainly.com/question/1770619

#SPJ5

$m=m_0 * ((1)/(2))^(t)/(t_(1/2))$
m - the mass that remains unchanged, m₀ - the inital mass, t - the time of decay, t1⁄2 - the half-life

$t=32 \ days \n m=5 \ mg \n m_0 = 80 \ mg \n \n 5 = 80 * ((1)/(2))^(32)/(t_(1/2)) \ \ \ \ \ \ \ |/ 80 \n (5)/(80)= ((1)/(2))^(32)/(t_(1/2)) \n (1)/(16)=((1)/(2))^(32)/(t_(1/2)) \n ((1)/(2))^4=((1)/(2))^(32)/(t_(1/2)) \n 4=(32)/(t_(1/2)) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |* t_(1/2) \n 4t_(1/2)=32 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 4 \n t_(1/2)=8$

The half-life is (1) 8 days.

What did Bohr’s model of the atom include that Rutherford’s model did not have?

Answers

What did Bohr’s model of the atom include that Rutherford’s model did not have?

The answer is energy levels

I think it's orbitals.
I'm pretty sure...

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