Answer: C)report the status of individual computer users
Explanation:Morris worm is known as the program that replicates itself automatically and hides in the computer system.Because of the vulnerability of the system ,the worm worked as finger protocol for the gaining of the user information and status.
Other option are incorrect as the they are not the vulnerability factor for the Morris worm to work on it and thus finger protocols don't work on those option.Thus, the correct answer is option(c)
Answer:
public class Main
{
public static void main(String[] args) {
minMax(1, 2, 3);
minMax(100, 25, 33);
minMax(11, 222, 37);
}
public static void minMax(int n1, int n2, int n3){
int max, min;
if(n1 >= n2 && n1 >= n3){
max = n1;
}
else if(n2 >= n1 && n2 >= n3){
max = n2;
}
else{
max = n3;
}
if(n1 <= n2 && n1 <= n3){
min = n1;
}
else if(n2 <= n1 && n2 <= n3){
min = n2;
}
else{
min = n3;
}
System.out.println("The max is " + max + "\nThe min is " + min);
}
}
Explanation:
*The code is in Java.
Create a function named minMax() that takes three integers, n1, n2 and n3
Inside the function:
Declare the min and max
Check if n1 is greater than or equal to n2 and n3. If it is set it as max. If not, check if n2 is greater than or equal to n1 and n3. If it is set it as max. Otherwise, set n3 as max
Check if n1 is smaller than or equal to n2 and n3. If it is set it as min. If not, check if n2 is smaller than or equal to n1 and n3. If it is set it as min. Otherwise, set n3 as min
Print the max and min
Inside the main:
Call the minMax() with different combinations
Answer:
num1 = 600
Explanation:
Given
The attached code snippet
Required
The output of n = funcOne(funcTwo(n)); when n = 30
The inner function is first executed, i.e.
funcTwo(n)
When n = 30, we have:
funcTwo(30)
This returns the product of n and 10 i.e. 30 * 10 = 300
So:
funcTwo(30) = 300
n = funcOne(funcTwo(n)); becomes: n = funcOne(300);
This passes 300 to funcOne; So, we have:
n = funcOne(300);
This returns the product of n and 2 i.e. 300 * 2 = 600
Hence, the output is 600
B) FALSE
It is true to say that Debugging is not testing but always occurs as a consequence of testing.
Debugging is the process of identifying and fixing defects in computer programs, software, or systems. It is a crucial step in computer programming and software development.
Debugging is used to identify and correct errors. The testing procedure just displays the consequences of the coding fault on the application; it does not assist the developer in identifying the mistake in the code.
Software developers and engineers use debugging to find and correct bugs in programs before making them available to the general public. It's an additional step to testing, which entails discovering how an issue impacts a program as a whole.
Debugging is the act of locating and fixing problems in software code that might lead to unexpected behavior or crashes. These mistakes are sometimes referred to as "bugs." Debugging is used to identify and fix faults or flaws in software or systems so that they don't operate incorrectly.
To read more about Debugging, refer to - brainly.com/question/13966274
#SPJ2
Answer:
Computer software, or simply software, is a collection of data or computer instructions that tell the computer how to work. This is in contrast to physical hardware, from which the system is built and actually performs the work.
Explanation:
B. Hierarchical
C. Linear
D. Group
Answer:B)Hierarchical
Explanation: Hierarchical order classifies the distribution of the data into the groups and their subgroups .The division of these groups and subgroups appear in the structure of pyramid generally.
The classification done in the hierarchical order is based on the authority on each level e.g.-the level with high authority is situated at higher level and below it, followed by its subgroup components.So, the correct option is option(B).
Traceback (most recent call last):
File " ", line 1, in
9/0
ZeroDivisionError: division by zero
Answer choices:
reserved word error
logical error
exception
syntax error
Answer: Logical Error
The division by 0 is a logical error.