A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavelengths of visible light is strongly reflected?

Answers

Answer 1
Answer:

Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, n=1.35.

The thickness of the soap bubble wall is, t=300 nm.

Now, for constructive interference of soap bubble.

2nt=(m+(1)/(2))\lambda.

Now for first order m=1.

Therfore,

\lambda =(4)/(3) tn

Substitute all the variables in the above equation.

\lambda =(4)/(3) (1.35)(300 nm).

Therefore,

\lambda =540 nm.

Therefore the visible light wavelength which is strongly reflected is 540 nm.


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As the captain of the scientific team sent to Planet Physics, one of your tasks is to measure g. You have a long, thin wire labeled 1.73 g/m and a 1.30 kg weight. You have your accurate space cadet chronometer but, unfortunately, you seem to have forgotten a meter stick. Undeterred, you first find the midpoint of the wire by folding it in half. You then attach one end of the wire to the wall of your laboratory, stretch it horizontally to pass over a pulley at the midpoint of the wire, then tie the 1.30 kg weight to the end hanging over the pulley. By vibrating the wire, and measuring time with your chronometer, you find that the wire's second harmonic frequency is 200 Hz . Next, with the 1.30 kg weight still tied to one end of the wire, you attach the other end to the ceiling to make a pendulum. You find that the pendulum requires 313 s to complete 200 oscillations. Pulling out your trusty calculator, you get to work.What value of g will you report back to headquarters?
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A flat disk of radius 0.50 m is oriented so that the plane of the disk makes an angle of 30 degrees with a uniform electric field. If the field strength is 713.0 N/C find the electric Tiux through the surface A) 560 Nm2/C B) 620 N·m2/C C) 160 n N.m2/C D) 280 N.m2/C

Answers

Answer:

electric flux is 280  Nm²/C  

so correct option is D 280  Nm²/C

Explanation:

radius r = 0.50 m

angle = 30 degree

field strength = 713 N/C

to find out

the electric flux through the surface

solution

we find here electric flux by given formula that is

electric flux = field strength × area× cos∅   .......1

here area = πr² = π(0.50)²

put here all value in equation  1

electric flux = field strength × area× cos∅  

electric flux = 713 × π(0.50)² × cos60

we consider the cosine of the angle between the direction of the field and the normal to the surface of the disk

so we use cos60

electric flux = 280  Nm²/C

so correct option is D 280  Nm²/C

A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse

Answers

The amount of work done per second by the horse exerting a force of 1800 N on a wagon moving with a speed of 0.4 m/s  is 720 J/s.

What is power?

Power is the workdone by a body in one second.

To calculate the work done by the horse in one seconds, we use the formula below

Formula:

  • P = Fv................ Equation 1

Where:

  • P = work done on the horse in one second
  • F = Force of the horse
  • v = Velocity of the wagon

From the question,

Given:

  • F = 1800 N
  • v = 0.4 m/s

Substitute these values into equation 1

  • P = 1800×0.4
  • P = 720 J/s

Hence, the amount of work done per second by the horse is 720 J/s.

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Complete question: A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse per second.

In an evironmental system of subsystem, the mass balance equation is:__________.

Answers

Answer:

Explanation:

The mass balance is an application of conservation of mass, to the analysis of physical system. This is given in an equation form as

Input = Output + Accumulation

The conservation law that is used in this analysis of the system actually depends on the context of the problem. Nevertheless, they all revolve around conservation of mass. By conservation of mass, I mean that the fact that matter cannot disappear or be created spontaneously.

2H is a loosely bound isotope of hydrogen, called deuterium or heavy hydrogen. It is stable but relatively rare — it form only 0.015% of natural hydrogen. Note that deuterium has Z = N, which should tend to make it more tightly bound, but both are odd numbers.Required:
Calculate BE/A, the binding energy per nucleon, for 2H in megaelecton volts per nucleon

Answers

Answer:

0.88 MeV/nucleon

Explanation:

The binding energy (B) per nucleon of deuterium can be calculated using the following equation:

B = (Zm_(p) + Nm_(n) - M)/(A)*931.49 MeV/u

Where:

Z: is the number of protons = 1

N: is the number of neutrons = 1

m_(p): is the proton's mass = 1.00730 u

m_(n): is the neutron's mass = 1.00869 u

M: is the nucleu's mass = 2.01410

A = Z + N = 1 + 1 = 2    

Now, the binding energy per nucleon for ²H is:

B = (Zm_(p) + Nm_(n) - M)/(A)*931.49 MeV/u = (1*1.00730 + 1*1.00869 - 2.01410)/(2)*931.49 MeV/u = 9.45 \cdot 10^(-4) u*931.49 MeV/u = 0.88 MeV/nucleon

Therefore, the binding energy per nucleon for ²H is 0.88 MeV/nucleon.

I hope it helps you!

Final answer:

The binding energy per nucleon for 2H (deuterium) is 1.1125 MeV per nucleon.

Explanation:

The binding energy per nucleon, or BE/A, can be calculated by dividing the total binding energy of the nucleus by the number of nucleons. To calculate the BE/A for 2H (deuterium), we need to know the total binding energy and the number of nucleons in deuterium. The total binding energy of deuterium is approximately 2.225 MeV (megaelectron volts) and the number of nucleons is 2. Therefore, the BE/A for 2H is 2.225 MeV / 2 = 1.1125 MeV per nucleon.

Learn more about Binding energy per nucleon here:

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The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has a field strength of 5.81 T, and the current in the solenoid is 3.79 × 102 A. What is the number of turns per meter of length of the solenoid?

Answers

Answer:

n = 1.22 10⁴ turns/m

Explanation:

The magnetic field in a solenoid is proportional to the intensity of the current, the number of turns per unit length (n) and the magnetic permeability (myo), is described by the equation

      B = μ₀ n I

Let's clear the density of turns

     n = B / (μ₀ I)

Let's replace and calculate

     n = 5.81 / (4pi 10-7 3.79 102)

     n = 5.81 105 / 47.63

     n = 1.22 10⁴ turns / m

Where is the near point of an normal eye when accidentally wear a contact lens with a power of +2.0 diopters?

Answers

Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

Power, P = (1)/(f)

where

f = focal length

Thus

f = (1)/(P)

f = (1)/(2) = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

(1)/(f) = (1)/(u) + (1)/(u')

where

u = object distance = 25 cm = 0.25 m = near point of a normal eye

u' = image distance

Now,

(1)/(u') = (1)/(f) - (1)/(u)

(1)/(u') = (1)/(0.5) - (1)/(0.25)

(1)/(u') = (1)/(f) - (1)/(u)

Solving the above eqn, we get:

u' = - 0.5 m = - 50 cm