M(5, 7) is the midpoint of mc140-1.jpg. The coordinates of S are (6, 9). What are the coordinates of R? (4, 5) (7, 11) (5.5, 8) (10, 14)

Answers

Answer 1
Answer:

Answer:

(4,5)

Step-by-step explanation:

Given that M is the midpoint of the Line RS. Where the coordinates of M, R and S are

M(5,7)

R(X,Y)

S(6,9)

Here we have to find the valuer of X and Y

We will use the mid point formula which is given below.

x=(x_1+x_2)/(2) \ny=(y_1+y_2)/(2)\n

Let put the coordinated of M and S and find coordinates of R

x=(x_1+x_2)/(2) \n5=(X+6)/(2) \n10=X+6\nX=4

y=(y_1+y_2)/(2)\n7=(Y+9)/(2) \n14=Y+9\ny=5

Hence our coordinates are

(4,5)

Answer 2
Answer: the coordinate of R(4,5)

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Please help find the value of sine.

Answers

Ok so all you have to do to find sine is divide the length of one side by another side. So the "Hypotenuse" is the long one, 12, by the "Opposite" is the shortest side, 8. 12 divided by 8 is 1.5 and that as a fraction is 3/2. So your answer is D. 3/2.

The domain of the function is given. Find the range.f(x) = 2x - 1
Domain: (-2, 0, 2, 4)
Range: (5,1, -3,7)
Range: (-5, 1, -3,7)
Range: (-5, -1,3,7)
Range: [5, 1, +3, +7)

Answers

Answer:

Range={-5,-1,3,7). [optionC]

Pleaseseetheattachedpictureforfullsolution..

Hopeithelps..

Goodluckonyourassignment..

5,-5,1,-3,7,3,
Explanation is that I’m guessing that this is the answer

State how many imaginary and real zeros the function has.f(x) = x5 + 7x4 + 2x3 + 14x2 + x + 7
A. 3 imaginary; 2 real
B. 4 imaginary; 1 real
C. 0 imaginary; 5 real
D. 2 imaginary; 3 real

Answers

Answer:

B. 4 imaginary; 1 real

Step-by-step explanation:

Given the polynomial:

x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7

it can be reordered as follows

(x^5 + 2*x^3 + x ) + (7*x^4  + 14*x^2 + 7)

Taking greatest common factor at each parenthesis

x*(x^4 + 2*x^2 + 1) + 7*(x^4  + 2*x^2 + 1)

Taking again the greatest common factor

(x + 7)*(x^4 + 2*x^2 + 1)

Replacing x^2 = y in the second parenthesis

(x + 7)*(y^2 + 2*y + 1)

(x + 7)*(y + 1)^2

Coming back to x variable

(x + 7)*(x^2 + 1)^2

There are two options to find the roots

(x + 7) = 0

or

(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0

In the former case, x = -7 is the real root.  In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.

Explaining How to Sve an ea
What should you do to solve the equation?
45 = x + 38
O Subtract 38 from both sides.
O Add 38 to both sides.
O Subtract 45 from both sides.
O Add 45 to both sides.

Answers

You subtract 38 from both sides

Answer:

Subtract 38 from both sides.

Step-by-step explanation:

THAT DA ANSWER

Write the equation in slope-intercept form.

2/3(6y+9)=3/5(15x-20)

Answers

(2)/(3)(6y+9)=(3)/(5)(15x-20)\ \ \ | multiply\ by\ 15\n\n10(6y+9)=9(15x-20)\n\n60y+90=135x-180\ \ \ | subtract\ 90\n\n60y=135x-270\ \ \ | divide\ by\ 60\n\nSlope\ intercept\ form:\ y=2.25x-4.5

What is the simplified value of the exponential expression 16^1/4?

Answers

The simplified value of the exponential expression 16^(1)/(4)is 2.

What does Fractional power mean for an integer?

Fractional power implies the root of the strength of the denominator of that integer.

For example: a^(1)/(n)=\sqrt[n]{a}.

Given here the exponential expression is 16^(1)/(4)

So here a=16,n=4

We know that, 2^4=16

Thus, 16^(1)/(4)=\sqrt[4]{16}=\sqrt[4]{2^4}=2

Hence the equivalent value of the given expression 16^(1)/(4) is 2.

Learn more about Fractional Power here -

brainly.com/question/13689764

#SPJ2

Answer

2

Explanation

First, we are going to use the law of fractional exponents: a^{(1)/(n) =\sqrt[n]{a}

We can infer form our expression that a=16 and n=4, so let's replace the values:

a^{(1)/(n) =\sqrt[n]{a}

16^{(1)/(4) }=\sqrt[4]{16}

Notice that we can also decompose 16 into prime factors to get 16=2^4, so we can rewrite our expression as follows:

\sqrt[4]{16}=\sqrt[4]{2^4}

Finally, we can use the rule of radicals: \sqrt[n]{a^n} =a, so:

\sqrt[4]{2^4}=2