Write the balanced equation for the reaction that occurs when methanol, CH3OH (I) is burned in air. What is the coefficient of methanol in the balanced equation? (A) 1 (B) 3 (C) 2 (D) 4 (E) 3/2

Answers

Answer 1

Answer:

Answer:

Explanation:

Methanol is an organic compound which burns with oxygen to produce carbon dioxide and water.

$2CH_3OH_((l))+3O_2_((g))\rightarrow 2CO_2_((g))+4H_2O_((g))$

Multiply coefficients times subscripts for each element in the formula, We get that there are 2 number of atoms of the carbon, 8 number of atoms of the hydrogen, and 8 number of atoms of the oxygen on both sides of equation. Hence, it is balanced.

The coefficient of methanol from the balanced reaction is 2.

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Cigarettes contain many chemicals. Which of the following chemicals is the addictive component to cigarettes?a. tar
b. nicotine
c. carbon dioxide
d. carbon monoxide

Answers

B is the correct answer, thankyou.

What is an example of the strong nuclear force?

Answers

Here are two examples of strong nuclear force !

Protons and nucleons

I hope that's help !

Which is least likely to occur after an experiment is conducted to test a hypothesis?

Answers

The question is asking to states what would likely too occur after an experiment is conducted to test a hypothesis, base on my research, if your hypothesis is correct then you can go further with the experiment but,if the experiment is incorrect then you'll have to make another hypothesis

Calculate the pOH of a 0.410 M Ba(OH)2 solution.

Answers

The dissociation of this basic compound is: $Ba(OH)_2\ \to\ Ba^(2+) + 2OH^-$

There will be the double of $OH^-$ ions than molecules of $Ba(OH)_2$ , therefore, the concentration of $OH^-$ at the end will be 0.820 M.

$pOH = -log\ [OH^-] = - log (0.820) = \bf 0.09$

When a liquid is heated, the temperature stops rising at the liquid’s ____________________.

Answers

Turn into a gas/steam/gets cooler/or condenses - I say the most likely one is condenses

hydrogen is found primarily as two isotopes in nature: (1.0078u) and (2.0140u). Caluclate the percentage abundance of each isotope based on hydrogens average atomic mass

Answers

hydrogens average atomic mass = 1,01u

x = isotope about mass (1.0078u)
y = isotope about mass (2.0140u)

x + y = 100%
so:
x = 100% - y

$hydrogens ~average~atomic~mass=((1.0078\cdot x)+(2.0140\cdot y))/(100)\n 1.01=((1.0078\cdot (100-y))+(2.0140y))/(100)||\cdot 100\n 101=100.78-1.0078y+2.0140\n 101-100.78=1.0062y\n 0,22=1.0062y||:1.0062\n 0.219\%=y\n\n x=100\%-y\n x=100\%-0.219\%\n x=99.781\%\n\n$

answer:
$x=99.781\%\n y=0.219\%$

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