What mass of oxygen gas contains the samenumber of moles as 56g of sulphur?
(Relative atomic mass: S=32,0=16)
(A) 0.56 g
B) 5.6 g
(C) 56 g
C) 560g

Answers

Answer 1
Answer:

The mass of oxygen gas contains the same number of moles as 56g of sulphur is 56g

Calculation,

Number of moles of sulphur = given mass/ molar mass of sulphur

Number of moles of sulphur = 56/ 32 moles

Number of moles of sulphur = 1.75 moles

According to question,

Number of moles of sulphur = Number of moles of oxygen(O2)

So, Let mass of oxygen be X.

Number of moles of oxygen = X/16×2 = 1.75 moles

Mass of oxygen (X) = 1.75×16×2 grams

Mass of oxygen (X) = 56 grams

What is moles ?

The 6.022×1023 of chemical species like an electrons, molecules atoms, ions etc is called moles

To learn more about moles here.

brainly.com/question/26416088

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Answer 2
Answer:

Answer:

C. 56 g

Explanation:

56 g S (1 mol S/ 32 g) = 1.75 mol S

1.75 mol O2 (32 g/ 1 mol O) = 56 g O2


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A 220.0-mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275 K. The piston is pushed in until the sample has a volume of 95.0 mL. The new temperature of the gas is 310. K. What is the new pressure of the sample?(1) 5l.1 kPa(2) 216 kPa(3) 243 kPa(4) 274 kPa

Answers

4. This problem is really simple if you realize that you can use the combined gas law:

P1V1/T1 = P2V2/T2

Therefore, just substitute in and solve:

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Answer is 274. kPa

The new pressure of the sample of helium gas in a cylinder with a movable piston is 274 kPa.

Option 4)274 kPa is the correct answer.

What is Combined gas law?

Combinedgas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 220.0mL = 0.22L
  • Initial pressure P₁ = 105kPa = 1.03627atm
  • Initial temperature T₁ = 275K
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  • Final temperature T₂ = 310K
  • Final pressure P₂ = ?

To calculate the new temperature of the gas, we substitute our given values into the equation above.

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

P₂ = (P₁V₁T₂) / V₂T₁

P₂ = ( 1.03627atm × 0.22L × 310K ) / ( 0.095L × 275K )

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The new pressure of the sample of helium gas in a cylinder with a movable piston is 274 kPa.

Option 4)274 kPa is the correct answer.

Learn more about the combined gaslaw here: brainly.com/question/25944795

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