b. atomic number = 8; mass number = 17
c. atomic number = 7; mass number = 17
d. atomic number = 7; mass number = 15
c. Atomic number = 7; mass number = 17
The atomic number of the first isotope is 7.
Isotopes of the same element have the same atomic number, so the atomic number of the second isotope must also be 7.
Mass number = no. of protons + no. of neutrons, or
A = p + n
∴ A = 7 + 10 = 17
Options “a.” and “b.” have the wrong atomic numbers, and option “d.” has the wrong mass number.
Answer:
C
Explanation:
(2) The entropy of the LiBr(aq) is less than the entropy of the water.
(3) The dissolving of the LiBr(s) in water is an endothermic process.
(4) The dissolving of the LiBr(s) in water is an exothermic process.
The statement best explains why the thermometer reading initially increases when LiBr(s) is dissolved in the water is the dissolving of the LiBr(s) in water is an exothermic process.
A thermometer is an instrument that is used to measure the temperature of an object.
An exothermic process is in which the heat and energy is released in the outer system.
Thus, the correct option is (4) The dissolving of the LiBr(s) in water is an exothermic process.
Learn more about thermometer
#SPJ2
(2) Br2(l) at 266 K (4) Br2(g) at 332 K
Answer:
Volume of brick = 3900 cm3 = 3.9*10^3 cm3
Volume of water displaced = 3900 ml = 3.9*10^3 ml
Explanation:
Given:
Dimension of the brick = 25 cm, 12 cm, 13 cm
To determine:
a) Volume of the brick
b) Volume (ml) of water displaced by the brick
Calculation:
a) Volume of the brick (cube) is expressed as a product of the dimensions
b) The volume of water displaced is equal to the volume of the brick.
Since, 1 ml = 1 cm3
Therefore, volume of water displaced = 3900 ml = 3.9*10^3 ml
NaCl, CH4, MgO and C6H12O6 are the empirical formula for four ionic compounds.
Empirical formula is defined as the chemical formula of a compound that gives the simplest proportions or ratios of the elements present in the compound but not the original numbers of atoms.
So we can conclude that NaCl, CH4, MgO and C6H12O6 are the empirical formula for four ionic compounds.
Learn more about ionic here: brainly.com/question/2687188
#SPJ1
The empirical formula for the four ionic compounds are CaF₂ and V₂S₅.
The empirical formula represents the simplest ratio of the elements in a compound. To determine the empirical formula of an ionic compound, we need to find the ratio of the ions involved. Given Ca²⁺, V⁵⁺, F⁻, and S²⁻, we can combine these ions to form different compounds by balancing their charges. Taking Ca²⁺ and F⁻, we get CaF₂. For V⁵⁺ and S²⁻, we get V₂S₅. Therefore, the empirical formula for the four ionic compounds is CaF₂, V₂S₅.
#SPJ6